Problem 8

# Problem_8.py
"""
The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832.
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?
在这个1000位数字中找到毗连的、相乘数最大的13个数字
""" raw = """
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
"""
li = raw.split()
thousand = ''
for i in li:
thousand += i maximum = 1
size = 13
for i in range(1, len(thousand)-13):
thirteen = thousand[i-1:size+i-1]
total = 1
for i in thirteen:
total *= int(i)
if maximum < total:
maximum = total print(maximum)

Problem 8的更多相关文章

  1. 1199 Problem B: 大小关系

    求有限集传递闭包的 Floyd Warshall 算法(矩阵实现) 其实就三重循环.zzuoj 1199 题 链接 http://acm.zzu.edu.cn:8000/problem.php?id= ...

  2. No-args constructor for class X does not exist. Register an InstanceCreator with Gson for this type to fix this problem.

    Gson解析JSON字符串时出现了下面的错误: No-args constructor for class X does not exist. Register an InstanceCreator ...

  3. C - NP-Hard Problem(二分图判定-染色法)

    C - NP-Hard Problem Crawling in process... Crawling failed Time Limit:2000MS     Memory Limit:262144 ...

  4. Time Consume Problem

    I joined the NodeJS online Course three weeks ago, but now I'm late about 2 weeks. I pay the codesch ...

  5. Programming Contest Problem Types

        Programming Contest Problem Types Hal Burch conducted an analysis over spring break of 1999 and ...

  6. hdu1032 Train Problem II (卡特兰数)

    题意: 给你一个数n,表示有n辆火车,编号从1到n,入站,问你有多少种出站的可能.    (题于文末) 知识点: ps:百度百科的卡特兰数讲的不错,注意看其参考的博客. 卡特兰数(Catalan):前 ...

  7. BZOJ2301: [HAOI2011]Problem b[莫比乌斯反演 容斥原理]【学习笔记】

    2301: [HAOI2011]Problem b Time Limit: 50 Sec  Memory Limit: 256 MBSubmit: 4032  Solved: 1817[Submit] ...

  8. [LeetCode] Water and Jug Problem 水罐问题

    You are given two jugs with capacities x and y litres. There is an infinite amount of water supply a ...

  9. [LeetCode] The Skyline Problem 天际线问题

    A city's skyline is the outer contour of the silhouette formed by all the buildings in that city whe ...

  10. PHP curl报错“Problem (2) in the Chunked-Encoded data”解决方案

    $s = curl_init(); curl_setopt($s, CURLOPT_POST, true); curl_setopt($s, CURLOPT_POSTFIELDS, $queryStr ...

随机推荐

  1. iOS_网络请求_代理方式

    #pragma mark - 网络请求代理方式(异步) - (IBAction)DelegateButtonDidClicked:(UIButton *)sender { // 1.拼接 urlStr ...

  2. 生产上数据库大量的latch free 导致的CPU资源耗尽的问题的解决

    中午的时候,我们生产上的某个数据库,cpu一直居高不下 通过例如以下的sql语句,我们查看当时数据库的等待,争用的情况: select s.SID, s.SERIAL#, 'kill -9 ' || ...

  3. mysql稳定的版本号选择及下载说明(2014-11-10)

    怎样选择新稳定的版本号       mysql的版本号大概能够分为Alpha.Beta.GA. GA版即mysql官方公布的稳定版本号. 怎样在官方下载Mysql        能够通过http:// ...

  4. 解决xftp失去链接需要重新链接问题。

    XFTP 失去连接需要重新连接 打开 Xftp 主程序. 在顶部菜单[文件] – [属性], 打开[默认会话属性]窗口,点击[选项],在连接部分选择勾选"发送保持活动状态消息(s)" ...

  5. docker overlay网络实现

    DOCKER的内置OVERLAY网络 内置跨主机的网络通信一直是Docker备受期待的功能,在1.9版本之前,社区中就已经有许多第三方的工具或方法尝试解决这个问题,例如Macvlan.Pipework ...

  6. Android线程间异步通信机制源码分析

    本文首先从整体架构分析了Android整个线程间消息传递机制,然后从源码角度介绍了各个组件的作用和完成的任务.文中并未对基础概念进行介绍,关于threadLacal和垃圾回收等等机制请自行研究. 基础 ...

  7. lua单链表实现

    List = {} --创建一个节点 function List.new(val) return {pnext = nil, value = val} end --往一个节点后添加一个节点 funct ...

  8. 关于百分比宽高div居中并垂直居中问题

    <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...

  9. Android 拍照图片选取与图片剪裁

    最近从以前的项目中扒下来一个常用的模块,在这里有必要记录一下的,就是android上获取图片以及裁剪图片,怎么样?这个功能是不是很常用啊,你随便打开一个App,只要它有注册功能都会有设置人物头像的功能 ...

  10. wpf ComboBox 获取选中项的文本内容

    一:根据数据源类型获取选中项 类: public class Region { public int REGION_ID { get; set; } public string REGION_CODE ...