A AFei Loves Magic
链接:https://ac.nowcoder.com/acm/contest/338/A
来源:牛客网
题目描述
AFei knew that the magical circle would disappear after t seconds. It meant that after t seconds, he could move and the stones would return to immobility. This also meant that AFei would get those stones. He wondered how many magic stones he could get in the end, including the first one he got when he came to the forest.
输入描述:
The first line contains three integers n, L, t (0≤n≤1000000, 2≤L≤1000000000, 0<=t<=1000000) − the number of stones on the line is n,the length of the line is L meter, and the magic circle will disappear after t seconds.
The following n lines contain description of magic stones on the line. Each i-th of these lines contains two space-separated integers x[i] and d[i] (0<x[i]<L, d[i]∈{1,2} for i<=n), which stand for initial position and direction of motion(1 means from 0 to L, 2 means from L to 0.).
输出描述:
Output a number indicating the amount of the magic stones that AFei will eventually be able to obtain.
说明
The stones are A(1,1), B(5,2), C(6,1), D(9,2). After 1s, they become A(2,1), B(4,2), C(7,1), D(8,2); After 2s, they become A(3,2), B(3,1), C(7,2), D(8,1); After 3s, they become A(2,2), B(4,1), C(6,2), D(9,1); After 4s, they become A(1,2), B(5,2), C(5,1), D reach L and disappears; After 5s, they become A reach 0 and disappears, B(4, 2), C(6,1), D disappeared; After 6s, they become A disappeared, B(3, 2), C(7, 1), D disappeared. AFei finially gets the first one, B and C.
备注:
1,Input guarantees that there will not be two magic stones in one location. 2,If stone A and stone B are located at 4 and 5, respectively, and A's direction is 1, B's direction is 2. Then next second, the position of the two stones have not changed, but they have gone in the opposite direction. 解题思路:不考虑碰撞,直接根据初始坐标,方向,时间和速度求出每一个魔法石的最终坐标,最终坐标在(0,L)的魔法石数量就是剩下的魔法石
#include<stdio.h>
int main()
{
int n ;
int len, t;
int a,b; while(scanf("%d%d%d",&n,&len,&t)!=EOF)
{
int sum = 1;
for(int i = 0; i<n; i++)
{
scanf("%d %d",&a,&b);
if(b == 1)
{
if(a+t<len)
sum++; }
else
{ if(a-t>0)
sum++;
}
}
printf("%d\n",sum);
} }
A AFei Loves Magic的更多相关文章
- 湖南大学第十四届ACM程序设计新生杯(重现赛)
RANK 0 题数 0 期末复习没有参加,补几道喜欢的题. A: AFei Loves Magic 签到 思路 :不需考虑 碰撞 直接计算最终状态即可. #include<bits/stdc ...
- Little Elephant and Magic Square
Little Elephant loves magic squares very much. A magic square is a 3 × 3 table, each cell contains s ...
- F Find the AFei Numbers
链接:https://ac.nowcoder.com/acm/contest/338/F来源:牛客网 题目描述 AFei loves numbers. He defines the natural n ...
- CodeForces-259B]Little Elephant and Magic Square
Little Elephant loves magic squares very much. A magic square is a 3 × 3 table, each cell contains ...
- BestCoder Round #90
有生以来第一场在COGS以外的地方打的比赛.挂成dog了. 主要是没有经验,加之代码能力过弱.还有最后的瞎hack三次,Too Young Too Simple...... 言归正传. (抄一发题解先 ...
- codeforces259B
Little Elephant and Magic Square CodeForces - 259B Little Elephant loves magic squares very much. A ...
- 【Codeforces717F】Heroes of Making Magic III 线段树 + 找规律
F. Heroes of Making Magic III time limit per test:3 seconds memory limit per test:256 megabytes inpu ...
- HDU4876ZCC loves cards(多校题)
ZCC loves cards Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Tot ...
- 多校训练赛2 ZCC loves cards
ZCC loves cards Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) ...
随机推荐
- goland使用:导入一个github开源项目tidb
概要:在windos下的IDEA 的go语言的编辑器 goland的使用,导入github上面的开源项目. 问题: 下载好goland之后,open project打开一个下载好的githubhub项 ...
- linux基础知识(三)
添加用户 •useradd -d 家目录 -g 组名 -G 组集合(逗号间隔) -p 密码 -s 用户shell程序 用户名 •useradd -d /usr/local/nginx/ -g ngin ...
- Windows系统中,循环运行.bat/.exe等文件
一.创建循环运行的run-everySecond.vbs文件[双击次文件即可启动运行] dim a set a=CreateObject("Wscript.Shell") Do # ...
- AOP技术介绍--(AOP技术基础)
2.1 AOP技术起源 AOP技术的诞生并不算晚,早在1990年开始,来自Xerox Palo Alto Research Lab(即PARC)的研究人员就对面向对象思想的局限性进行了分 ...
- 去掉Tomcat网站地址栏的小猫图标
当我们打开CSDN等网站时,在地址栏前面就会出现红色的C状图标,如果在桌面新建此链接的快捷方式,则桌面图标也自动变为该地址栏ICO图标.在基于TOMCAT的BS应用或网站开发时,默认的图标为黄色的小猫 ...
- HTML5 音频播放
代码实例: <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF ...
- ThinkPhp view 路径用到的常量 __STATIC__ __JS__ __CSS__等
https://www.edoou.com/articles/1556848583530922 ThinkPHP5.1 里面__PUBLIC__无法生效的问题 在用PHP模板的时候需要引用外部的样式文 ...
- Task2.设立计算图并自动计算
1.numpy和pytorch实现梯度下降法 import numpy as np # N is batch size; N, D_in, H, D_out = 64, 1000, 100, 10 # ...
- hibernate插入数据测试无异常,但数据库没有数据
解决方法: spring test测试默认会将事务回滚,如果想阻止spring transactional回滚,在test方法上加注解@Rollback(false)即可. Hibernate hql ...
- create-react-app下的@修饰器正确的使用方式记录
在create-react-app下使用es7的@修饰器会报错''Support for the experimental syntax 'decorators-legacy' isn't curre ...