ZOJ 3787 Access System 水

LINK：http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3787

思路：结构体 时间转化为秒记录下最小并且排序就好了

/** @Date    : 2017-03-23-22.06
  * @Author  : Lweleth (SoungEarlf@gmail.com)
  * @Link    : https://github.com/
  * @Version :
  */
#include<bits/stdc++.h>
#define LL long long
#define PII pair
#define MP(x, y) make_pair((x),(y))
#define fi first
#define se second
#define PB(x) push_back((x))
#define MMG(x) memset((x), -1,sizeof(x))
#define MMF(x) memset((x),0,sizeof(x))
#define MMI(x) memset((x), INF, sizeof(x))
using namespace std;

const int INF = 0x3f3f3f3f;
const int N = 2e4+20;
const double eps = 1e-8;

struct yuu
{
    int t, m;
}a[N];

int cmp(yuu a, yuu b)
{
    if(a.t != b.t)
        return a.t < b.t;
    return a.m < b.m;
}

int b[N];
int main()
{
    int T;
    cin >> T;
    while(T--)
    {
        int n, l;
        int h, m, s;
        cin >> n >> l;
        int cnt = 0;

        int mi = -1;
        for(int i = 0; i < n; i++)
        {
            scanf("%d:%d:%d", &h, &m, &s);
            a[i].t = h * 3600 + m * 60 + s;
            a[i].m = i + 1;
        }
        sort(a, a + n, cmp);
        for(int i = 0; i < n; i++)
        {
            if(a[i].t >= mi)
                b[cnt++] = a[i].m, mi = a[i].t + l;
        }
        printf("%d\n", cnt);
        sort(b, b + cnt);
        for(int i = 0; i < cnt; i++)
            printf("%d%s", b[i], i==cnt - 1?"\n":" ");
    }
    return 0;
}