leetcode 190
190. Reverse Bits
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
按位翻转输入的整数。
代码如下:
class Solution {
public:
uint32_t reverseBits(uint32_t n) {
unsigned ret = ;
unsigned pos1 = << ;
unsigned pos2 = ;
while(pos1)
{
if(pos1 & n)
ret |= pos2;
pos2 <<= ;
pos1 >>= ;
}
return ret;
}
};
leetcode 190的更多相关文章
- [LeetCode] 190. Reverse Bits 颠倒二进制位
Reverse bits of a given 32 bits unsigned integer. Example 1: Input: 00000010100101000001111010011100 ...
- LeetCode 190. Reverse Bits (反转位)
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in ...
- LeetCode 190. Reverse Bits (算32次即可)
题目: 190. Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 432 ...
- [LeetCode] 190. Reverse Bits 翻转二进制位
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in ...
- Java实现 LeetCode 190 颠倒二进制位
190. 颠倒二进制位 颠倒给定的 32 位无符号整数的二进制位. 示例 1: 输入: 00000010100101000001111010011100 输出: 0011100101111000001 ...
- Leetcode 190 Reverse Bits 位运算
反转二进制 class Solution { public: uint32_t reverseBits(uint32_t n) { uint32_t ans = ; ; i<; ++i,n &g ...
- Java for LeetCode 190 Reverse Bits
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in ...
- Java [Leetcode 190]Reverse Bits
题目描述: everse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represente ...
- Leetcode 190. Reverse Bits(反转比特数)
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in ...
随机推荐
- qsort C++ VS2013 leetcode
class Solution { private: static int compare(const void * a, const void * b) { return (*(int*)a - *( ...
- php $_SERVER中的SERVER_NAME 和HTTP_HOST的区别
关于这个问题,搜索引擎上搜到一大片的文章,有很多问题,在这找到一篇正确的说法:http://mimiz.cn/index.php/php/php-http_host-server_name-diffe ...
- jQuery下通过$.browser来判断浏览器
使用方法: $.browser.['浏览器关键字'] 代码如下: $(function() { if($.browser.msie) { alert("this is msie") ...
- css 超过宽度显示...
一般使用 display:block;white-space:nowrap; overflow:hidden; text-overflow:ellipsis; *****************未实验 ...
- Django 基础(一)
Python的WEB框架有Django.Tornado.Flask 等多种,Django相较与其他WEB框架其优势为:大而全,框架本身集成了ORM.模型绑定.模板引擎.缓存.Session等诸多功能 ...
- Best Practices for Performance_1、2 memory、Tips 性能和小的优化点、 onTrimMemory
http://developer.android.com/training/articles/memory.htmlhttp://developer.android.com/tools/debuggi ...
- 02shell编程环境的搭建
02shell编程环境的搭建 [02]Shell编程 02shell编程环境的搭建 在不同的操作系统上搭建shell编程环境 Linux Windows Mac 编辑器的选择 系统环境的搭建 注: 选 ...
- R语言-数据高级管理
数学函数 abs() 绝对值 sqrt() 平方 ceiling() 向上取整 floor() 向下取整 trunc() 截取整数部分 round(x,digits = n) 保留几位小数 统计函数 ...
- js加解密
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/ ...
- php判断是否是微信客户端的浏览器访问
代码: $user_agent = $_SERVER['HTTP_USER_AGENT']; if (strpos($user_agent, 'MicroMessenger') === false) ...