Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 5976   Accepted: 3231

Description

You are assigned to design network connections between certain points in a wide area. You are given a set of points in the area, and a set of possible routes for the cables that may connect pairs of points. For each possible route between two points, you are
given the length of the cable that is needed to connect the points over that route. Note that there may exist many possible routes between two given points. It is assumed that the given possible routes connect (directly or indirectly) each two points in the
area. 

Your task is to design the network for the area, so that there is a connection (direct or indirect) between every two points (i.e., all the points are interconnected, but not necessarily by a direct cable), and that the total length of the used cable is minimal.

Input

The input file consists of a number of data sets. Each data set defines one required network. The first line of the set contains two integers: the first defines the number P of the given points, and the second the number R of given routes between the points.
The following R lines define the given routes between the points, each giving three integer numbers: the first two numbers identify the points, and the third gives the length of the route. The numbers are separated with white spaces. A data set giving only
one number P=0 denotes the end of the input. The data sets are separated with an empty line. 

The maximal number of points is 50. The maximal length of a given route is 100. The number of possible routes is unlimited. The nodes are identified with integers between 1 and P (inclusive). The routes between two points i and j may be given as i j or as j
i. 

Output

For each data set, print one number on a separate line that gives the total length of the cable used for the entire designed network.

Sample Input

1 0

2 3
1 2 37
2 1 17
1 2 68 3 7
1 2 19
2 3 11
3 1 7
1 3 5
2 3 89
3 1 91
1 2 32 5 7
1 2 5
2 3 7
2 4 8
4 5 11
3 5 10
1 5 6
4 2 12 0

Sample Output

0
17
16
26

题意:

P个点。R对边。找出最小通路和

分析:

长度为边权的最小生成树问题

kruskal & 并查集
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
#include<vector>
#include<queue>
#define INF 0x3f3f3f3f using namespace std; const int maxn=5100; int r[maxn];
int n, m; struct node
{
int x;
int y;
int cost;
};
node a[maxn]; bool cmp ( node a, node b )
{
return a.cost<b.cost;
} void init()
{
for( int i=0; i<n; i++ )
scanf( "%d%d%d", &a[i].x, &a[i].y, &a[i].cost );
sort( a, a+n, cmp );
for( int i=0; i<n; i++ )
r[i] = i;
} int find( int x )
{
return r[x]==x? x : r[x] = find( r[x] );
} void kruskal()
{
int cnt = 0;
int ans = 0;
int x; int y;
for( int i=0; i<n; i++ )
{
x = find( a[i].x );
y = find( a[i].y );
if( x!=y )
{
cnt++;
ans += a[i].cost;
if( cnt == m-1 )
break;
r[y] = x;
}
}
printf( "%d\n", ans );
} int main()
{
while( scanf( "%d", &m )==1 &&m )
{
scanf( "%d", &n );
init();
kruskal();
}
return 0;
}

POJ 1287:Networking(最小生成树Kruskal)的更多相关文章

  1. POJ 1287 Networking (最小生成树)

    Networking Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u Submit S ...

  2. POJ 1287 Networking【kruskal模板题】

    传送门:http://poj.org/problem?id=1287 题意:给出n个点 m条边 ,求最小生成树的权 思路:最小生树的模板题,直接跑一遍kruskal即可 代码: #include< ...

  3. POJ 1287 Networking (最小生成树模板题)

    Description You are assigned to design network connections between certain points in a wide area. Yo ...

  4. ZOJ1372 POJ 1287 Networking 网络设计 Kruskal算法

    题目链接:problemCode=1372">ZOJ1372 POJ 1287 Networking 网络设计 Networking Time Limit: 2 Seconds     ...

  5. POJ.1287 Networking (Prim)

    POJ.1287 Networking (Prim) 题意分析 可能有重边,注意选择最小的边. 编号依旧从1开始. 直接跑prim即可. 代码总览 #include <cstdio> #i ...

  6. POJ - 1287 Networking 【最小生成树Kruskal】

    Networking Description You are assigned to design network connections between certain points in a wi ...

  7. POJ 1287 Networking (最小生成树)

    Networking 题目链接: http://acm.hust.edu.cn/vjudge/contest/124434#problem/B Description You are assigned ...

  8. POJ 1287 Networking(最小生成树)

    题意  给你n个点 m条边  求最小生成树的权 这是最裸的最小生成树了 #include<cstdio> #include<cstring> #include<algor ...

  9. [kuangbin带你飞]专题六 最小生成树 POJ 1287 Networking

    最小生成树模板题 跑一次kruskal就可以了 /* *********************************************** Author :Sun Yuefeng Creat ...

  10. poj 1287 Networking【最小生成树prime】

    Networking Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 7321   Accepted: 3977 Descri ...

随机推荐

  1. URAL 1146 Maximum Sum 最大子矩阵和

    题目:click here #include <bits/stdc++.h> using namespace std; typedef unsigned long long ll; con ...

  2. Opencv 完美配置攻略 2014 (Win8.1 + Opencv 2.4.8 + VS 2013)下

    前面说了一些在OpenCV在VS2013下的配置的过程,下面说一下其中的个别的知识点,了解一下这样配置的一点点更细节的过程.其实配置项目属性的时候,有两种方式: 一.通过项目属性管理器配置项目属性表 ...

  3. Java 操作mongodb

    package cn.test.db; import java.io.File; import java.io.IOException; import java.net.UnknownHostExce ...

  4. 基于百度地图api + AngularJS 的入门地图

    转载请注明地址:http://www.cnblogs.com/enzozo/p/4368081.html 简介: 此入门地图为简易的“广州大学城”公交寻路地图,采用很少量的AngularJS进行inp ...

  5. oracle去除字符串中间的空格

    update AC01 A set A.AAC003 = REGEXP_REPLACE(A.AAC003, '( ){1,}', '') WHERE A.AAC002 IN (SELECT AAC00 ...

  6. c# 流程控制

    using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.T ...

  7. USB接口定义

    一般的排列方式是:红白绿黑从左到右 定义: 红色-USB电源 标有-VCC.Power.5V.5VSB字样 绿色-USB数据线(正)-DATA+.USBD+.PD+.USBDT+ 白色-USB数据线( ...

  8. 部署一个class文件

    只发布一个class文件找到项目工作空间/target/class..根据项目结构找到修改的java文件编译的class文件比如RegexUtils.class使用SecureFXPortable将文 ...

  9. poj 1068 Parencodings(栈)

    题目链接:http://poj.org/problem?id=1068 思路分析:对栈的模拟,将栈中元素视为广义表,如 (((()()()))),可以看做 LS =< a1, a2..., a1 ...

  10. Robot Framework学习路线

    0. 官方网站  http://robotframework.org/ 所有资料都来自这里,从这里找到必要的链接,从而深入其中的细节. 1.  Quick Start Guide https://co ...