POJ 1287:Networking(最小生成树Kruskal)
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 5976 | Accepted: 3231 |
Description
given the length of the cable that is needed to connect the points over that route. Note that there may exist many possible routes between two given points. It is assumed that the given possible routes connect (directly or indirectly) each two points in the
area.
Your task is to design the network for the area, so that there is a connection (direct or indirect) between every two points (i.e., all the points are interconnected, but not necessarily by a direct cable), and that the total length of the used cable is minimal.
Input
The following R lines define the given routes between the points, each giving three integer numbers: the first two numbers identify the points, and the third gives the length of the route. The numbers are separated with white spaces. A data set giving only
one number P=0 denotes the end of the input. The data sets are separated with an empty line.
The maximal number of points is 50. The maximal length of a given route is 100. The number of possible routes is unlimited. The nodes are identified with integers between 1 and P (inclusive). The routes between two points i and j may be given as i j or as j
i.
Output
Sample Input
1 0 2 3
1 2 37
2 1 17
1 2 68 3 7
1 2 19
2 3 11
3 1 7
1 3 5
2 3 89
3 1 91
1 2 32 5 7
1 2 5
2 3 7
2 4 8
4 5 11
3 5 10
1 5 6
4 2 12 0
Sample Output
0
17
16
26
题意:
P个点。R对边。找出最小通路和
分析:
长度为边权的最小生成树问题
kruskal & 并查集
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
#include<vector>
#include<queue>
#define INF 0x3f3f3f3f using namespace std; const int maxn=5100; int r[maxn];
int n, m; struct node
{
int x;
int y;
int cost;
};
node a[maxn]; bool cmp ( node a, node b )
{
return a.cost<b.cost;
} void init()
{
for( int i=0; i<n; i++ )
scanf( "%d%d%d", &a[i].x, &a[i].y, &a[i].cost );
sort( a, a+n, cmp );
for( int i=0; i<n; i++ )
r[i] = i;
} int find( int x )
{
return r[x]==x? x : r[x] = find( r[x] );
} void kruskal()
{
int cnt = 0;
int ans = 0;
int x; int y;
for( int i=0; i<n; i++ )
{
x = find( a[i].x );
y = find( a[i].y );
if( x!=y )
{
cnt++;
ans += a[i].cost;
if( cnt == m-1 )
break;
r[y] = x;
}
}
printf( "%d\n", ans );
} int main()
{
while( scanf( "%d", &m )==1 &&m )
{
scanf( "%d", &n );
init();
kruskal();
}
return 0;
}
POJ 1287:Networking(最小生成树Kruskal)的更多相关文章
- POJ 1287 Networking (最小生成树)
Networking Time Limit:1000MS Memory Limit:10000KB 64bit IO Format:%I64d & %I64u Submit S ...
- POJ 1287 Networking【kruskal模板题】
传送门:http://poj.org/problem?id=1287 题意:给出n个点 m条边 ,求最小生成树的权 思路:最小生树的模板题,直接跑一遍kruskal即可 代码: #include< ...
- POJ 1287 Networking (最小生成树模板题)
Description You are assigned to design network connections between certain points in a wide area. Yo ...
- ZOJ1372 POJ 1287 Networking 网络设计 Kruskal算法
题目链接:problemCode=1372">ZOJ1372 POJ 1287 Networking 网络设计 Networking Time Limit: 2 Seconds ...
- POJ.1287 Networking (Prim)
POJ.1287 Networking (Prim) 题意分析 可能有重边,注意选择最小的边. 编号依旧从1开始. 直接跑prim即可. 代码总览 #include <cstdio> #i ...
- POJ - 1287 Networking 【最小生成树Kruskal】
Networking Description You are assigned to design network connections between certain points in a wi ...
- POJ 1287 Networking (最小生成树)
Networking 题目链接: http://acm.hust.edu.cn/vjudge/contest/124434#problem/B Description You are assigned ...
- POJ 1287 Networking(最小生成树)
题意 给你n个点 m条边 求最小生成树的权 这是最裸的最小生成树了 #include<cstdio> #include<cstring> #include<algor ...
- [kuangbin带你飞]专题六 最小生成树 POJ 1287 Networking
最小生成树模板题 跑一次kruskal就可以了 /* *********************************************** Author :Sun Yuefeng Creat ...
- poj 1287 Networking【最小生成树prime】
Networking Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 7321 Accepted: 3977 Descri ...
随机推荐
- 写一个兼容性比较好的拖拽DEMO
写一个兼容性比较好的拖拽DEMO 查看Demo 思路 div盒子 鼠标按下事件onmousedown 鼠标移动事件onmousemove,获得鼠标的坐标,将div移动至鼠标的当前坐标 鼠标抬起事件om ...
- vagrant 入门4
7. 打包 Packaging , 8080 end 2. 打包Project $ vagrant package --vagrantfile Vagrantfile.pkg 8. 打包完成后,在工程 ...
- glib 文档 代码 索引 编译
./configure --prefix=/opt/glib-2.28.8 --enable-staticmakemake install linux下载 WIN32下载 代码索引 文档索引 GLib ...
- qt qml 利用xmlhttprequest 调用有赞api
最近朋友在有赞商城上面开了一个店铺,因为有实体店,一般卖商品后送货上门,但是打票时候老是人工用world文档人工复制黏贴订单打印小票, 所以就找我帮忙做一个软件专门打印小票的,就研究起来调用有赞第三方 ...
- 腾讯QQ是用什么语言开发的(转)
腾讯QQ的部分COM组件用的VC6,用exescope看其中几个dll的依赖,依赖于MFC42.dll,MSVCRT.dll,MSVCP60.dll都说明是VC6写的. 还有一部分用的VS2005,包 ...
- 让我们共同构筑物联网起飞的平台:物联网操作系统Hello China寻求应用合作伙伴
经过几天的努力,终于把Hello China V1.76版的内核移植到基于Cortex-M3内核的STM32 chipset上.因为还希望进一步写一个USART驱动程序,因此详细的移植文档,预计一周之 ...
- vim插件配置(一)
vim代码自动显示提示代码插件:AutoComplPop: 代码(普通变量函数) c/c++代码(类的 . , ->, :: 操作符)的自动补全插件: OmniCppComplete
- 【Hibernate】双向多对多Set查询
一个计划对于多个竞价,一个竞价对应多个计划. 1.实体 /** * @author Tidy * @Description 计划 */ public class EbgStockPlanContent ...
- 【Eclipse】调试java程序的九个技巧
本文转自[半夜乱弹琴],原文地址:http://www.cnblogs.com/lingiu/p/3802391.html 九个技巧: 逻辑结构 条件debug 异常断点 单步过滤 跳到帧 Inspe ...
- BZOJ 2242: [SDOI2011]计算器( 快速幂 + 扩展欧几里德 + BSGS )
没什么好说的... --------------------------------------------------------------------- #include<cstdio&g ...