POJ3080:Blue Jeans
Description
As an IBM researcher, you have been tasked with writing a program that will find commonalities amongst given snippets of DNA that can be correlated with individual survey information to identify new genetic markers.
A DNA base sequence is noted by listing the nitrogen bases in the order in which they are found in the molecule. There are four bases: adenine (A), thymine (T), guanine (G), and cytosine (C). A 6-base DNA sequence could be represented as TAGACC.
Given a set of DNA base sequences, determine the longest series of bases that occurs in all of the sequences.
Input
- A single positive integer m (2 <= m <= 10) indicating the number of base sequences in this dataset.
- m lines each containing a single base sequence consisting of 60 bases.
Output
Sample Input
3
2
GATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
3
GATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATA
GATACTAGATACTAGATACTAGATACTAAAGGAAAGGGAAAAGGGGAAAAAGGGGGAAAA
GATACCAGATACCAGATACCAGATACCAAAGGAAAGGGAAAAGGGGAAAAAGGGGGAAAA
3
CATCATCATCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
ACATCATCATAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AACATCATCATTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT
Sample Output
no significant commonalities
AGATAC
CATCATCAT
找出n个串中最长的公共串,并且要求字典序最大
直接枚举第一串的所有子串,然后与后面的所有串进行比较即可
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std; char str[15][65];
char sub[65];
char ans[65];
int len; int main()
{
int t,i,j,k,n,maxn;
scanf("%d",&t);
while(t--)
{
maxn = 0;
scanf("%d",&n);
memset(ans,'\0',sizeof(ans));
for(i = 1; i<=n; i++)
scanf("%s",str[i]);
for(i = 1; i<=60; i++)
{
int find = 0;
for(j = 0; j<=60-i; j++)
{
len = 0;
int check = 1;
for(k = j;;k++)
{
sub[len++] = str[1][k];
if(len == i)
break;
}
sub[len] = '\0';
for(k = 2; k<=n; k++)
{
if(!strstr(str[k],sub))
{
check = 0;
break;
}
}
if(check)
{
find = 1;
if(strlen(ans)<strlen(sub))
strcpy(ans,sub);
else if(strcmp(ans,sub)>0)
strcpy(ans,sub);
}
}
if(!find)
break;
}
if(strlen(ans)<3)
printf("no significant commonalities\n");
else
printf("%s\n",ans);
} return 0;
}
POJ3080:Blue Jeans的更多相关文章
- POJ3080 Blue Jeans —— 暴力枚举 + KMP / strstr()
题目链接:https://vjudge.net/problem/POJ-3080 Blue Jeans Time Limit: 1000MS Memory Limit: 65536K Total ...
- POJ3080——Blue Jeans(暴力+字符串匹配)
Blue Jeans DescriptionThe Genographic Project is a research partnership between IBM and The National ...
- poj3080 Blue Jeans【KMP】【暴力】
Blue Jeans Time Limit: 1000MS Memory Limit: 65536K Total Submissions:21746 Accepted: 9653 Descri ...
- POJ 3080 Blue Jeans (字符串处理暴力枚举)
Blue Jeans Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 21078 Accepted: ...
- POJ 3080 Blue Jeans(Java暴力)
Blue Jeans [题目链接]Blue Jeans [题目类型]Java暴力 &题意: 就是求k个长度为60的字符串的最长连续公共子串,2<=k<=10 规定: 1. 最长公共 ...
- (字符串 KMP)Blue Jeans -- POJ -- 3080:
链接: http://poj.org/problem?id=3080 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=88230#probl ...
- POJ 3080 Blue Jeans 找最长公共子串(暴力模拟+KMP匹配)
Blue Jeans Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20966 Accepted: 9279 Descr ...
- POJ Blue Jeans [枚举+KMP]
传送门 F - Blue Jeans Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u ...
- POJ 3080 Blue Jeans (求最长公共字符串)
POJ 3080 Blue Jeans (求最长公共字符串) Description The Genographic Project is a research partnership between ...
随机推荐
- Sniffer抓包教程
上网络信息安全的时候用了下,中途出现了一堆奇葩的事,这里就不提了... 上教程: 先把虚拟机里面的防火墙给关了,主机防火墙也关了 之前由于ip自己设置了,然后一直ping不通,后面把ip改成自动获取就 ...
- 关于asp.net程序连接不了ORACLE数据库而PL/SQL可以连接的问题
今天在发布ASP.NET WEB网站时发现程序连接不了数据 报“ORA-12154: TNS: 无法解析指定的连接标识符”的错误,但PL/SQL连接又没有问题.真莫名其秒.在百度找了好多相关的问题.都 ...
- Swift - 27 - 使用元组让函数返回多个值
//: Playground - noun: a place where people can play import UIKit // 定义一个数组 var userScores:[Int]? = ...
- 关于模板中的动态取值 ---反射与javascript脚本编译
在项目中经常遇到一个问题,打印word或者打印excel的时候,我们经常使用一对一的赋值或者批量替换的方式来对模板进行修改. 但是现在遇到两种场景: 1.取值是通过自定以方法进行取值的. 如:一个销售 ...
- 关于SVD(Singular Value Decomposition)的那些事儿
SVD简介 SVD不仅是一个数学问题,在机器学习领域,有相当多的应用与奇异值都可以扯上关系,比如做feature reduction的PCA,做数据压缩(以图像压缩为代表)的算法,还有做搜索引擎语义层 ...
- 新手对css的浅识
对于css的一个初步理解与认识 在最近的学习中接触到了之前自己从来都不曾想过的语言,C语言,html超文本标记语言等等,还有今天在这里我要进行分析的css,之前浏览过很多的网页,也曾想过这里面的秘密, ...
- 【CEOI2004】锯木厂选址
[题目描述] 从山顶上到山底下沿着一条直线种植了n棵老树.当地的政府决定把他们砍下来.为了不浪费任何一棵木材,树被砍倒后要运送到锯木厂.木材只能按照一个方向运输:朝山下运.山脚下有一个锯木厂.另外两个 ...
- Windows Phone获得IsolatedStorage中指定目录下的所有文件
在Windows Phone 中对隔离存储空间中的文件操作需要通过System.Io.IsolatedStorage下的类进行操作 获得指定文件夹下的所有文件: 参数:是指定文件夹的路径加上通配符,格 ...
- 09_linux下安装Nvidia显卡驱动
下载驱动 去官网找去,哈哈o(^▽^)o 安装kernel source [root@localhost ~]# yum install kernel-devel 如果还不行,试试下面的 [root@ ...
- 百度分享share.js插件
//百度分享window._bd_share_config = { common : { bdText : '分享标题', bdDesc : '分享描述', bdUrl : '分享链接', bdPic ...