Given a nested list of integers represented as a string, implement a parser to deserialize it.

Each element is either an integer, or a list -- whose elements may also be integers or other lists.

Note: You may assume that the string is well-formed:

String is non-empty.
String does not contain white spaces.
String contains only digits 0-9, [, - ,, ].
Example 1: Given s = "324", You should return a NestedInteger object which contains a single integer 324.
Example 2: Given s = "[123,[456,[789]]]", Return a NestedInteger object containing a nested list with 2 elements: 1. An integer containing value 123.
2. A nested list containing two elements:
i. An integer containing value 456.
ii. A nested list with one element:
a. An integer containing value 789.

有括号这种一般要用stack, stack top 就是当前着眼的那一个NestedInteger, 可以对其添加新的元素。

注意47行判断很关键,顺带处理了 "[]," 括号后面是逗号的情况

 /**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
* // Constructor initializes an empty nested list.
* public NestedInteger();
*
* // Constructor initializes a single integer.
* public NestedInteger(int value);
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // Set this NestedInteger to hold a single integer.
* public void setInteger(int value);
*
* // Set this NestedInteger to hold a nested list and adds a nested integer to it.
* public void add(NestedInteger ni);
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class Solution {
public NestedInteger deserialize(String s) {
if (!s.startsWith("[")) {
return new NestedInteger(Integer.parseInt(s));
}
NestedInteger res = new NestedInteger();
Stack<NestedInteger> st = new Stack<NestedInteger>();
st.push(res);
int start = 1;
for (int i=1; i<s.length(); i++) {
char c = s.charAt(i);
if (c == '[') {
NestedInteger ni = new NestedInteger();
st.peek().add(ni);
st.push(ni);
start = i+1;
}
else if (c==',' || c==']') {
if (i > start) { // "],"这种情况
int val = Integer.parseInt(s.substring(start, i));
st.peek().add(new NestedInteger(val));
}
start = i+1;
if (c == ']') st.pop();
}
}
return res;
}
}

Leetcode: Mini Parser的更多相关文章

  1. [LeetCode] Mini Parser 迷你解析器

    Given a nested list of integers represented as a string, implement a parser to deserialize it. Each ...

  2. 【LeetCode】385. Mini Parser 解题报告(Python)

    [LeetCode]385. Mini Parser 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/mini-parser/ ...

  3. 385. Mini Parser - LeetCode

    Question 385. Mini Parser Solution 分析:用NI(count,list)来表示NestedInteger,则解析字符串[123,[456,[789]]]过程如下: # ...

  4. 385 Mini Parser 迷你解析器

    Given a nested list of integers represented as a string, implement a parser to deserialize it.Each e ...

  5. [Swift]LeetCode385. 迷你语法分析器 | Mini Parser

    Given a nested list of integers represented as a string, implement a parser to deserialize it. Each ...

  6. 385. Mini Parser

    括号题一般都是stack.. 一开始想的是存入STACK的是SRING,然后POP出括号在构建新的NestedInteger放到另一个里面,但是操作起来费时费力. 后来猛然发现其实可以直接吧Neste ...

  7. LeetCode All in One 题目讲解汇总(持续更新中...)

    终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance ...

  8. leetcode bugfree note

    463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的 ...

  9. leetcode & lintcode for bug-free

    刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be it ...

随机推荐

  1. (转)maven 配置在eclipse中

    maven3 下载配置 下载地址 http://maven.apache.org/download.cgi 在线文档 http://maven.apache.org/ref/3.0.5/ 安装 一.安 ...

  2. 使用scrapy爬取网站的商品数据

    目标是爬取网站http://www.muyingzhijia.com/上全部的商品数据信息,包括商品的一级类别,二级类别,商品title,品牌,价格. 搜索了一下,python的scrapy是一个不错 ...

  3. linux 不能用clock 计算sleep的时间

    http://bbs.csdn.net/topics/390558707 在Windows Sleep()占用processor time,Linux下的sleep()不占用processor tim ...

  4. qmake理解(还可以加入Lex Yacc文件)

    关于qmake,好一段时间令我一头雾水,不知道用来干嘛的,只知道怎么用,而且也只懂那么一两个命令,详细看过资料以后整理如下: 1.首先,感性的认识是,qmake可以利用源文件(包括头文件h,实现文件c ...

  5. 创建数据库指定路径sql

    create database stuDB on  primary  -- 默认就属于primary文件组,可省略(/*--数据文件的具体描述--*/    name='stuDB_data',  - ...

  6. TCP keepalive overview

    2. TCP keepalive overview In order to understand what TCP keepalive (which we will just call keepali ...

  7. [LeetCode]题解(python):053-Maximum Subarray

    题目来源 https://leetcode.com/problems/maximum-subarray/ Find the contiguous subarray within an array (c ...

  8. Intervals---poj1201(差分约束系统)

    题目链接:http://poj.org/problem?id=1201 题目说[ai, bi]区间内和点集Z至少有ci个共同元素,那也就是说如果我用Si表示区间[0,i]区间内至少有多少个元素的话,那 ...

  9. Swift-05-SizeOf&&SizeOfValue

    在C中定义的运算符,可以作用于类型或者某个实际的变量,并返回其在内存中的尺寸size_t. 在Cocoa中,我们一般用来将数组生成NSData的时候传入数据长度.因为在OC里面,sizeOf这个C运算 ...

  10. html5向左滑动删除特效

    <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...