You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

Example:

Given n = 5, and version = 4 is the first bad version.

call isBadVersion(3) -> false
call isBadVersion(5) -> true
call isBadVersion(4) -> true Then 4 is the first bad version. 

思路

binary search

代码

 /* The isBadVersion API is defined in the parent class VersionControl.
boolean isBadVersion(int version); */ public class Solution extends VersionControl {
public int firstBadVersion(int n) {
int start = 1, end = n;
while (start < end) {
// avoid overflow
int mid = start + (end-start) / 2;
if (!isBadVersion(mid)){
start = mid + 1;
} else {
end = mid;
}
}
return start;
}

[leetcode]278. First Bad Version首个坏版本的更多相关文章

  1. [LeetCode] 278. First Bad Version 第一个坏版本

    You are a product manager and currently leading a team to develop a new product. Unfortunately, the ...

  2. [LeetCode] First Bad Version 第一个坏版本

    You are a product manager and currently leading a team to develop a new product. Unfortunately, the ...

  3. LeetCode OJ:First Bad Version(首个坏版本)

    You are a product manager and currently leading a team to develop a new product. Unfortunately, the ...

  4. leetcode 278. First Bad Version

    You are a product manager and currently leading a team to develop a new product. Unfortunately, the ...

  5. (medium)LeetCode 278.First Bad Version

    You are a product manager and currently leading a team to develop a new product. Unfortunately, the ...

  6. Leetcode 278 First Bad Version 二分查找(二分下标)

    题意:找到第一个出问题的版本 二分查找,注意 mid = l + (r - l + 1) / 2;因为整数会溢出 // Forward declaration of isBadVersion API. ...

  7. Java [Leetcode 278]First Bad Version

    题目描述: You are a product manager and currently leading a team to develop a new product. Unfortunately ...

  8. LeetCode 278.First Bad Version(E)(P)

    题目: You are a product manager and currently leading a team to develop a new product. Unfortunately, ...

  9. LeetCode OJ:Compare Version Numbers(比较版本字符串)

    Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 &l ...

随机推荐

  1. ossfs工具将OSS挂载到阿里云linux系统目录例子

    ossfs 是基于 aliyun OSS 的 fuse 客户端了,所以我们把它用在阿里云上肯定是没有错了,下面来看一篇关于ossfs工具将OSS挂载到阿里云linux系统目录例子,具体的细节如下文介绍 ...

  2. VLC在web系统中应用(x-vlc-plugin 即如何把VLC嵌入HTML中)第一篇

    VLC毫无疑问是优秀的一款播放软件,子B/S机构的web项目中,如果能把它嵌入页面,做页面预览或者其他,是非常棒的. 第一步:下载VLC安装程序:(推荐1.0.3或者是1.0.5版本,比较稳定) ht ...

  3. php file_exists无效解决办法

    一:is_file 和 file_exists 的区别:当文件存在时:is_file 比 file_exists快了N倍当文件不存在时:is_file 比 file_exists慢总之一句话:file ...

  4. 【转载】Docker 经验之谈

    本文来源:Ghostcloud原创     对于用户来说,可能一开始在不了解的情况下会对容器报以拒绝的态度,但是在尝到容器的甜头.体验到它的强大性能之后,相信大家最终是无法抵挡其魅力的.容器技术能够解 ...

  5. 【洛谷】P1641 [SCOI2010]生成字符串(思维+组合+逆元)

    题目 传送门:QWQ 分析 不想画图. https://www.luogu.org/problemnew/solution/P1641 好神仙的题啊. 代码 // luogu-judger-enabl ...

  6. Spark分析之Worker

    override def preStart() { webUi = new WorkerWebUI(this, workDir, Some(webUiPort)) webUi.bind() //创建并 ...

  7. blktrace 深度了解linux系统的IO运作

    http://blog.yufeng.info/archives/751 我们在Linux上总是要保存数据的,数据要么保存在文件系统里(如ext3),要么就在裸设备里面.我们在使用这些数据的时候都是通 ...

  8. 异步请求fetch之初体验

    更好阅读体验可移步我的博客:Blog 导读 传递信息到服务器,从服务器获取信息,是前端发展的重中之重,尤其是现在前后端分离的大前提下,前后端的数据交互是前端的必修科目了.从很久之前到现在,ajax都是 ...

  9. selenium+python自动化96-执行jquery报:$ is not defined

    前言 背景介绍:做wap页面自动化的时候,把url地址直接输入到浏览器(chrome浏览器有手机wap模式)上测试,有个按钮死活点不到,用wap模式的触摸事件也无法解决,后来想用jquery去执行点击 ...

  10. J2SE 8的输入输出--序列化

    1. 普通序列化 implements Serializable 继承Serializable接口 class Employee implements Serializable { private S ...