Python3找出List中最大_最小的N个数及索引

 # -*- coding: utf-8 -*-
 import heapq

 nums = [1, 8, 2, 23, 7, -4, 18, 23, 24, 37, 2]

 # 最大的3个数的索引
 max_num_index_list = map(nums.index, heapq.nlargest(3, nums))

 # 最小的3个数的索引
 min_num_index_list = map(nums.index, heapq.nsmallest(3, nums))

 print(list(max_num_index_list))
 print(list(min_num_index_list))

import heapq

a=[1,2,3,4,5]
re1 = map(a.index, heapq.nlargest(3, a)) #求最大的三个索引    nsmallest与nlargest相反，求最小
re2 = heapq.nlargest(3, a) #求最大的三个元素
print(list(re1)) #因为re1由map()生成的不是list，直接print不出来，添加list()就行了
print(re2)