POJ 1306 Combinations

// 求 C[n][m]

// 组合公式 C[i][j]=C[i-1][j-1]+C[i-1][j];

#include <iostream>
#include <string>
#include<sstream>
#include <cmath>
#include <map>
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
#define  LL long long
LL C[][];
int main()
{
   int i,j;
   for(i=;i<=;i++) C[i][]=;
   for(i=;i<=;i++)
     for(j=;j<=i;j++)
       C[i][j]=C[i-][j-]+C[i-][j];
   int n,k;
   while(scanf("%d %d",&n,&k),n|k)
   {
      printf("%d things taken %d at a time is %lld exactly.\n",n,k,C[n][k]);
   }
   return ;
}