2016 ACM/ICPC Asia Regional Qingdao Online HDU5878
链接:http://acm.hdu.edu.cn/showproblem.php?pid=5878
解法:先保存,再二分查询~具体http://blog.csdn.net/coder_xia/article/details/6707600
#include<stdio.h>
//#include<bits/stdc++.h>
#include<string.h>
#include<iostream>
#include<math.h>
#include<sstream>
#include<set>
#include<queue>
#include<map>
#include<vector>
#include<algorithm>
#include<limits.h>
#define MAXN (100000+10)
#define MAXM (100000)
#define inf 0x3fffffff
#define INF 0x3f3f3f3f
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define ULL unsigned long long
using namespace std;
long long data[10000];
long long index = 0;
void get(int n)
{
data[0] = 1;
long long T2 = 0;
long long T3 = 0;
long long T5 = 0;
long long T7 = 0;
// long long index = 0;
while (index < n)
{
index++;
long long d1=min(data[T2] * 2, data[T3] * 3);
long long d2=min(data[T5] * 5, data[T7] * 7);
long long d = min(d1,d2);
data[index] = d;
while (data[T2] * 2 == data[index]) T2++;
while (data[T3] * 3 == data[index]) T3++;
while (data[T5] * 5 == data[index]) T5++;
while (data[T7] * 7 == data[index]) T7++;
}
}
int main()
{
int i,n;
get(7000);
// cout<<data[7000]<<endl;
// cout<<index<<endl;
int t;
while(~scanf("%d",&t))
{
}
while(t--)
{
int m;
scanf("%d",&m);
int pos=lower_bound(data,data+index,m)-data;
printf("%lld\n",data[pos]);
}
return 0;
}
2016 ACM/ICPC Asia Regional Qingdao Online HDU5878的更多相关文章
- 2016 ACM/ICPC Asia Regional Qingdao Online 1001/HDU5878 打表二分
I Count Two Three Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others ...
- HDU 5889 Barricade 【BFS+最小割 网络流】(2016 ACM/ICPC Asia Regional Qingdao Online)
Barricade Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total S ...
- 2016 ACM/ICPC Asia Regional Qingdao Online(2016ACM青岛网络赛部分题解)
2016 ACM/ICPC Asia Regional Qingdao Online(部分题解) 5878---I Count Two Three http://acm.hdu.edu.cn/show ...
- 数学--数论--HDU--5878 Count Two Three 2016 ACM/ICPC Asia Regional Qingdao Online 1001
I will show you the most popular board game in the Shanghai Ingress Resistance Team. It all started ...
- 【2016 ACM/ICPC Asia Regional Qingdao Online】
[ HDU 5878 ] I Count Two Three 考虑极端,1e9就是2的30次方,3的17次方,5的12次方,7的10次方. 而且,不超过1e9的乘积不过5000多个,于是预处理出来,然 ...
- hdu 5878 I Count Two Three (2016 ACM/ICPC Asia Regional Qingdao Online 1001)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5878 题目大意: 给出一个数n ,求一个数X, X>=n. X 满足一个条件 X= 2^a*3^ ...
- Hdu OJ 5884-Sort (2016 ACM/ICPC Asia Regional Qingdao Online)(二分+优化哈夫曼)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5884 题目大意:有n个有序的序列,对于第i个序列有ai个元素. 现在有一个程序每次能够归并k个序列, ...
- 2016 ACM/ICPC Asia Regional Qingdao Online HDU5889
链接:http://acm.hdu.edu.cn/showproblem.php?pid=5889 解法:http://blog.csdn.net/u013532224/article/details ...
- 2016 ACM/ICPC Asia Regional Qingdao Online HDU5883
链接:http://acm.hdu.edu.cn/showproblem.php?pid=5883 解法:先判断是不是欧拉路,然后枚举 #pragma comment(linker, "/S ...
随机推荐
- 序列变换(hdu5248)
序列变换 Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submis ...
- Java SE series:1. environment configure and Hello world! [We use compiler and packager to create an application!]
1. cli (command line interface) and gui (graphic user interface) use javahome path, search classpath ...
- [原创]java WEB学习笔记85:Hibernate学习之路-- -映射 一对一关系 ,基于主键方式实现
本博客的目的:①总结自己的学习过程,相当于学习笔记 ②将自己的经验分享给大家,相互学习,互相交流,不可商用 内容难免出现问题,欢迎指正,交流,探讨,可以留言,也可以通过以下方式联系. 本人互联网技术爱 ...
- MDX Order排序
Order基础用法: Numeric expression syntaxOrder(Set_Expression, Numeric_Expression [ , { ASC | DESC | BASC ...
- 怎么查看windows2003中隐藏用户
在命令模式下删除1.你在MS-dos下先输入net user 看有那些用户, 注意第一步看不出隐藏的用户 2.然后在输入net localgroup administrators 或者 net loc ...
- mysql 导出过长的数字列时变科学计数法问题解决办法
--mysql 导出数据时, 数字类型的列如果位数过长,变为科学技术发问题 concat('\t',a.IDCARD_NO) 例子: select concat('\t',a.IDCA ...
- [MacOS] xcrun: error: active developer path ("/Volumes/Xcode/Xcode6-Beta.app/Contents/Developer") does not exist, use xcode-select to change
When using MacOS with xcode6-beta, i always meet these error: xcrun: error: active developer path (& ...
- [OrangePi] Features (the features of Loboris's Images)
boot0_sdcard.fex, u-boot.fex and kernel (uImage) created from sources kernel built with many feature ...
- UIActivityViewController(转)
在iOS 6之后提供了一个分享列表视图,它通过UIActivityViewController管理.苹果设计它主要的目的是替换分享动作选单(ActionSheet),分享动作选单是出于分享目的的动作选 ...
- 在Linux中打印函数调用堆栈【原创】
本人学习笔记,代码参考如下网址 参考http://www.cnblogs.com/dma1982/archive/2012/02/08/2342215.html zhangbh@prolin-srv: ...