忘记的时候就翻阅翻阅吧~~

SQL

LINQ

Lambda

SELECT *FROM HumanResources.Employee

from e in Employees

select e

Employees .Select (e => e)

SELECT e.LoginID, e.JobTitle

FROM HumanResources.Employee AS e

from e in Employees

select new {e.LoginID, e.JobTitle}

Employees.Select (
      e => new {
            LoginID = e.LoginID, 
            JobTitle = e.JobTitle
         }
   )

SELECT e.LoginID AS ID, e.JobTitle AS Title

FROM HumanResources.Employee AS e

from e in Employees

select new {ID = e.LoginID, Title = e.JobTitle}

Employees.Select (
      e => new 
         {
            ID = e.LoginID, 
            Title = e.JobTitle
         }
   )

SELECT DISTINCT e.JobTitle

FROM HumanResources.Employee AS e

(from e in Employees

select e.JobTitle).Distinct()

Employees
   .Select (e => e.JobTitle)
   .Distinct ()

SELECT e.*

FROM HumanResources.Employee AS e

WHERE e.LoginID = 'test'

from e in Employees

where e.LoginID == "test"

select e

Employees
   .Where (e => (e.LoginID == "test"))

SELECT e.*

FROM HumanResources.Employee AS e

WHERE e.LoginID = 'test' AND e.SalariedFlag = 1

from e in Employees

where e.LoginID == "test" && e.SalariedFlag

select e

Employees
   .Where (e => ((e.LoginID == "test") && e.SalariedFlag))

SELECT e.* FROM HumanResources.Employee AS e

WHERE e.VacationHours >= 2 AND e.VacationHours <= 10

from e in Employees

where e.VacationHours >= 2 && e.VacationHours <= 10

select e

Employees
   .Where (e => (((Int32)(e.VacationHours) >= 2) && ((Int32)(e.VacationHours) <= 10)))

SELECT e.* FROM HumanResources.Employee AS e
ORDER BY e.NationalIDNumber

from e in Employees

orderby e.NationalIDNumber

select e

Employees
   .OrderBy (e => e.NationalIDNumber)

SELECT e.* FROM HumanResources.Employee AS e

ORDER BY e.HireDate DESC, e.NationalIDNumber

from e in Employees

orderby e.HireDate descending, e.NationalIDNumber

select e

Employees
   .OrderByDescending (e => e.HireDate)
   .ThenBy (e => e.NationalIDNumber)

SELECT e.* FROM HumanResources.Employee AS e

WHERE e.JobTitle LIKE 'Vice%' OR SUBSTRING(e.JobTitle, 0, 3) = 'Pro'

from e in Employees

where e.JobTitle.StartsWith("Vice") || e.JobTitle.Substring(0, 3) == "Pro"

select e

Employees
   .Where (e => (e.JobTitle.StartsWith ("Vice") || (e.JobTitle.Substring (0, 3) == "Pro")))

SELECT SUM(e.VacationHours)

FROM HumanResources.Employee AS e

 

Employees.Sum(e => e.VacationHours);

SELECT COUNT(*) FROM HumanResources.Employee AS e

 

Employees.Count();

SELECT SUM(e.VacationHours) AS TotalVacations, e.JobTitle

FROM HumanResources.Employee AS e

GROUP BY e.JobTitle

from e in Employees

group e by e.JobTitle into g

select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)}

Employees
   .GroupBy (e => e.JobTitle)
   .Select (
      g => new 
         {
            JobTitle = g.Key, 
            TotalVacations = g.Sum (e => (Int32)(e.VacationHours))
         }
   )

SELECT e.JobTitle, SUM(e.VacationHours) AS TotalVacations

FROM HumanResources.Employee AS e

GROUP BY e.JobTitle

HAVING e.COUNT(*) > 2

from e in Employees

group e by e.JobTitle into g

where g.Count() > 2

select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)}

Employees
   .GroupBy (e => e.JobTitle)
   .Where (g => (g.Count () > 2))
   .Select (
      g => 
         new 
         {
            JobTitle = g.Key, 
            TotalVacations = g.Sum (e => (Int32)(e.VacationHours))
         }
   )

SELECT *

FROM Production.Product AS p, Production.ProductReview AS pr

from p in Products

from pr in ProductReviews

select new {p, pr}

Products
   .SelectMany (
      p => ProductReviews, 
      (p, pr) => 
         new 
         {
            p = p, 
            pr = pr
         }
   )

SELECT *

FROM Production.Product AS p

INNER JOIN Production.ProductReview AS pr ON p.ProductID = pr.ProductID

from p in Products

join pr in ProductReviews on p.ProductID equals pr.ProductID

select new {p, pr}

Products
   .Join (
      ProductReviews, 
      p => p.ProductID, 
      pr => pr.ProductID, 
      (p, pr) => 
         new 
         {
            p = p, 
            pr = pr
         }
   )

SELECT *

FROM Production.Product AS p

INNER JOIN Production.ProductCostHistory AS pch ON p.ProductID = pch.ProductID AND p.SellStartDate = pch.StartDate

from p in Products

join pch in ProductCostHistories on new {p.ProductID, StartDate = p.SellStartDate} equals new {pch.ProductID, StartDate = pch.StartDate}

select new {p, pch}

Products
   .Join (
      ProductCostHistories, 
      p => 
         new 
         {
            ProductID = p.ProductID, 
            StartDate = p.SellStartDate
         }, 
      pch => 
         new 
         {
            ProductID = pch.ProductID, 
            StartDate = pch.StartDate
         }, 
      (p, pch) => 
         new 
         {
            p = p, 
            pch = pch
         }
   )

SELECT *

FROM Production.Product AS p

LEFT OUTER JOIN Production.ProductReview AS pr ON p.ProductID = pr.ProductID

from p in Products

join pr in ProductReviews on p.ProductID equals pr.ProductID

into prodrev

select new {p, prodrev}

Products
   .GroupJoin (
      ProductReviews, 
      p => p.ProductID, 
      pr => pr.ProductID, 
      (p, prodrev) => 
         new 
         {
            p = p, 
            prodrev = prodrev
         }
   )

SELECT p.ProductID AS ID

FROM Production.Product AS p

UNION

SELECT pr.ProductReviewID

FROM Production.ProductReview AS pr

(from p in Products

select new {ID = p.ProductID}).Union(

from pr in ProductReviews

select new {ID = pr.ProductReviewID})

Products
   .Select (
      p => 
         new 
         {
            ID = p.ProductID
         }
   )
   .Union (
      ProductReviews
         .Select (
            pr => 
               new 
               {
                  ID = pr.ProductReviewID
               }
         )
   )

SELECT TOP (10) *

FROM Production.Product AS p

WHERE p.StandardCost < 100

(from p in Products

where p.StandardCost < 100

select p).Take(10)

Products
   .Where (p => (p.StandardCost < 100))
   .Take (10)

SELECT *

FROM [Production].[Product] AS p

WHERE p.ProductID IN(

SELECT pr.ProductID

FROM [Production].[ProductReview] AS [pr]

WHERE pr.[Rating] = 5

)

from p in Products

where (from pr in ProductReviews

where pr.Rating == 5

select pr.ProductID).Contains(p.ProductID)

select p

Products
   .Where (
      p => 
         ProductReviews
            .Where (pr => (pr.Rating == 5))
            .Select (pr => pr.ProductID)
            .Contains (p.ProductID)
   )

直接上实例,学习起来是不是更方便些!

SQL-LINQ-Lambda语法对照,好记性不如烂笔头的更多相关文章

  1. SQL,LINQ,Lambda语法对照图(转载)

    如果你熟悉SQL语句,当使用LINQ时,会有似曾相识的感觉.但又略有不同.下面是SQL和LINQ,Lambda语法对照图 SQL LINQ Lambda SELECT * FROM HumanReso ...

  2. 好记性不如烂笔头-linux学习笔记1

    好记性不如烂笔头-linux学习笔记1 linux的文件系统有ext2,ext3,ext4,目前主流是ext4 linux主要用于服务器级别的操作系统,安装时需要至少2个分区 一个是交换分区,swap ...

  3. 好记性不如烂笔头-Mysql查找如何判断字段是否包含某个字符串

    好记性不如烂笔头-Mysql查找如何判断字段是否包含某个字符串 利用mysql 字符串函数 find_in_set(); SELECT * FROM users WHERE find_in_set(' ...

  4. [nodejs]修改全局包位置,修复npm安装全局模块命令失效。好记性不如烂笔头

    修复npm -g 全局安装命令失效,好的吧不得不承认,好记性不如烂笔头,我居然会忘记方法哈哈哈 Linux安装nodejs sudo apt install node sudo apt install ...

  5. Common lang一些边界方法总结(好记性不如烂笔头,需要慢慢积累).一定要利用好现有的轮子,例如Apache common与Google Guava

    好记性真是不如烂笔头啊!!!! 如下代码: List<String> list = new ArrayList<String>(); list.add("1" ...

  6. SQL语句笔记/好记性不如烂笔头/持续更新

    常用的增删改查操作,针对库,表,字段,记录分类有助于记忆,当然熟能生巧,还是需要多多实操 库操作 删除库 drop database dbx; 列出所有库 show databases; 切换库 us ...

  7. SQL,Linq,Lambda之间的转换练习

    1.查询Student表中的所有记录的Sname.Ssex和Class列. SQL:select sname,ssex,class from Students linq:from s in Stude ...

  8. sql linq lambda 对比

    . 查询Student表中的所有记录的Sname.Ssex和Class列. select sname,ssex,class from student Linq: from s in Students ...

  9. 好记性不如烂笔头-linux学习笔记5mysql主从复制

    mysql主从复制的原理 mysql master服务器,开启bin-log日志,开启IO线程 slave服务器,开启IO线程,开启SQL线程(执行SQL) 1)slave服务器,通过授权用户开启IO ...

随机推荐

  1. centos atomic host第一次启动

    centos atomic host安装完成会,第一次启动时会调用cloud-init等服务.这是个什么东东? cloud-init用于在创建虚拟机时通过元数据服务对虚拟机基本配置,包括常见的主机名, ...

  2. 解读CSS布局之-水平垂直居

    对一个元素水平垂直居中,在我们的工作中是会经常遇到的,也是CSS布局中很重要的一部分,本文就来讲讲CSS水平垂直居中的一些方法.由于我们大搜车的日常工作中已经不再需要理会低版本IE,所以本文所贴出的方 ...

  3. IOS CLLocationManager定位反编码位置信息

    //获取位置和坐标#if __IPHONE_OS_VERSION_MAX_ALLOWED > __IPHONE_7_1        if (IOS_VERSION >= 8.0) {   ...

  4. [原]NYOJ 括号匹配系列2,5

    本文出自:http://blog.csdn.net/svitter 括号匹配一:http://acm.nyist.net/JudgeOnline/problem.php?pid=2 括号匹配二:htt ...

  5. js实现文字截断

    先前用jq做了一个文字截断功能,但是不用jq的项目要实现此功能还要引如jq显得过于麻烦.这里写了一个js的文字截断功能.直接上代码. HTML(测试用的): <div>我是pox我是pox ...

  6. Creating a Unique File Name

    If you are working with files or file attachments in PeopleCode, you will typically want to create a ...

  7. 一些peoplecode小技巧平【二】

    1. Set component changed page field property: For understanding this open a page in application desi ...

  8. JS限定手机版中图片大小随分辨率自动调整

    <script type="text/javascript"> var ObjImg = jQuery(".Dy_Content img"); fo ...

  9. 一些CSS"bug"

    1.img三像像素问题 解决办法:img{display:block;} or img{vertical-align:middle;} 问题原因:img是行内元素,默认的垂直对齐方式 baseline ...

  10. Cassandra 之 入门

    1.到官网下载压缩包. http://cassandra.apache.org/download/ 我下载的是最新的 apache-cassandra-2.1.2-bin.tar.gz 另外:语言支持 ...