poj1811 Prime Test
http://poj.org/problem?id=1811
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <ctime>
using namespace std;
typedef __int64 LL;
const int times = ;
LL minf, n; LL random(LL n){
return (double)rand() / RAND_MAX * n + 0.5;
} LL multi(LL a, LL b, LL mod){
a %= mod, b %= mod;
LL ans = ;
while(b){
if(b & ) ans += a, ans %= mod;
b >>= ;
a <<= ;
a %= mod;
}
return ans;
} LL power(LL a, LL p, LL mod){
a %= mod;
LL ans = ;
while(p){
if(p & ) ans = multi(ans, a, mod);
p >>= ;
a = multi(a, a, mod);
}
return ans;
} LL gcd(LL a, LL b){
if(!b) return a;
return gcd(b, a % b);
} bool witness(LL a, LL n){
LL u = n - ;
while(!(u & )) u >>= ;
LL t = power(a, u, n);
while(u != n - && t != && t != n - ){
t = multi(t, t, n);
u <<= ;
}
return t == n - || u & ;
} bool miller_rabin(LL n){
if(n == ) return ;
if(n < || !(n & )) return ;
//test for odd numbers larger than 2
for(int i = ; i < times; i++){
LL p = random(n - ) + ;
if(!witness(p, n)) return ;
}
return ;
} LL pollard_rho(LL n, LL t){
LL x = random(n - ) + ;
LL y = x;
LL i = , k = , d;
while(){
++i;
x = (multi(x, x, n) + t) % n;
d = gcd(y - x, n);
if( < d && d < n) return d;
if(x == y) return n;
if(i == k){
y = x;
k <<= ;
}
}
} void fact(LL n, LL t){
if(n == ) return;
if(miller_rabin(n)){
minf = min(minf, n);
return;
}
LL p = n;
while(p >= n) p = pollard_rho(p, t--);
fact(p, t);
fact(n / p, t);
} void solve(){
//if n is prime
if(miller_rabin(n)){
puts("Prime");
return;
}
//try to factorize n
//initialize the minimum non trival factor of n
minf = n;
fact(n, );
printf("%I64d\n", minf);
} int main(){
//freopen("in.txt", "r", stdin);
int T;
scanf("%d", &T);
while(T--) scanf("%I64d", &n), solve();
return ;
}
poj1811 Prime Test的更多相关文章
- POJ1811 Prime Test(miller素数判断&&pollar_rho大数分解)
http://blog.csdn.net/shiyuankongbu/article/details/9202373 发现自己原来的那份模板是有问题的,而且竟然找不出是哪里的问题,所以就用了上面的链接 ...
- [poj1811]Prime Test(Pollard-Rho大整数分解)
问题描述:素性测试兼质因子分解 解题关键:pollard-rho质因数分解,在RSA的破译中也起到了很大的作用 期望复杂度:$O({n^{\frac{1}{4}}})$ #include<cst ...
- 【POJ1811】【miller_rabin + pollard rho + 快速乘】Prime Test
Description Given a big integer number, you are required to find out whether it's a prime number. In ...
- 【POJ1811】Prime Test
[题目大意] 若n是素数,输出“Prime”,否则输出n的最小素因子,(n<=2^54) [题解] 和bzoj3667差不多,知识这道题没那么坑. 直接上Pollord_Rho和Rabin_Mi ...
- Java 素数 prime numbers-LeetCode 204
Description: Count the number of prime numbers less than a non-negative number, n click to show more ...
- Prime Generator
Peter wants to generate some prime numbers for his cryptosystem. Help him! Your task is to generate ...
- POJ 2739. Sum of Consecutive Prime Numbers
Sum of Consecutive Prime Numbers Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20050 ...
- UVa 524 Prime Ring Problem(回溯法)
传送门 Description A ring is composed of n (even number) circles as shown in diagram. Put natural numbe ...
- Sicily 1444: Prime Path(BFS)
题意为给出两个四位素数A.B,每次只能对A的某一位数字进行修改,使它成为另一个四位的素数,问最少经过多少操作,能使A变到B.可以直接进行BFS搜索 #include<bits/stdc++.h& ...
随机推荐
- Java基础之泛型——使用通配符类型参数(TryWildCard)
控制台程序 使用通配符类型参数可以设定方法的参数类型,其中的代码对于泛型类的实际类型参数不能有任何依赖.如果将方法的参数类型设定为Binary<?>,那么方法可以接受BinaryTree& ...
- 学习CSS3BUTTON(二)
今天,继续学习其源代码: button { margin-left: 0; margin-right: 0; *padding: 5px 5px 3px 5px; } /*margin-left:设定 ...
- sql server常见服务
根据您决定安装的组件,SQL Server 安装程序将安装以下服务: SQL Server Database Services - 用于 SQL Server 关系数据库引擎的服务. 可执行文件为 & ...
- interesting js
[5/3/2016 4:18 PM] Calos Chen: function a(b,e){var a=0;a+=b;if(e){console.log(b+e);return;} retur ...
- 每天一个shell知识--数组
1.shell中数组的定义: 数组名=(value value1 value2 ) 也可以单独的设定数组的分量: arrayL[0]=value arrayL[1]=value1 2.${arrayL ...
- HDU 3681 Prison Break(BFS+二分+状态压缩DP)
Problem Description Rompire is a robot kingdom and a lot of robots live there peacefully. But one da ...
- DataFrame使用mysql数据
错误提示: Exception in thread "main" java.sql.SQLException: No suitable driver found for jdbc ...
- paper 88:人脸检测和识别的Web服务API
本文汇总了全球范围内提供基于Web服务的人脸检测和识别的API,便于网络中快速部署和人脸相关的一些应用. 1:从How-old的火爆说起 最开始,网站的开发者只是给一个几百人的群发送email,请他们 ...
- rails创建项目,部署,测试流程(rails5.0+ruby2.3.1)
rails new test_app --skip-test-unit 不生成默认的test,稍后用rspeccd test_app 修改Gemfile(大部分为自动生成) source 'https ...
- 夺命雷公狗ThinkPHP项目之----企业网站21之网站前台二级分类显示名称(TP自定义函数展示无限极分类)
我们实现网站二级分类的显示的时候,先要考虑的是直接取出顶级栏目,控制器代码如下所示: <?php namespace Home\Controller; use Think\Controller; ...