Hastiness

Problem Description

How many problems did you AC?
When you read this problem, don’t hasty and careless, this is also simple, haha, I didn’t cheat you.
The game over soon, WisKey starts using English begin countdown. He not only have no gene in math, but also bad in English. Fortunately, He met you who have gift in programming. So please help him to translate. 

 

Input

Give you an integer T, output T in English, and note that all of words are lower case. (0<=T<=9999)

 

Output

One answer One line.
Details see sample.

 

Sample Input

2034

1234

123

24

0

 

Sample Output

two thousand and thirty-four

one thousand and two hundred and thirty-four

one hundred and twenty-three

twenty-four

zero

 

 #include <stdio.h>
 #include <string.h>

 int main(){
     int number;
     int a;
     int b;
     int c;
     char digit[][];
     char ten[][];
     int flag=;

     strcpy(digit[],"zero");
     strcpy(digit[],"one");
     strcpy(digit[],"two");
     strcpy(digit[],"three");
     strcpy(digit[],"four");
     strcpy(digit[],"five");
     strcpy(digit[],"six");
     strcpy(digit[],"seven");
     strcpy(digit[],"eight");
     strcpy(digit[],"nine");
     strcpy(digit[],"ten");
     strcpy(digit[],"eleven");
     strcpy(digit[],"twelve");
     strcpy(digit[],"thirteen");
     strcpy(digit[],"fourteen");
     strcpy(digit[],"fifteen");
     strcpy(digit[],"sixteen");
     strcpy(digit[],"seventeen");
     strcpy(digit[],"eighteen");
     strcpy(digit[],"nineteen");
     strcpy(digit[],"twenty");

     strcpy(ten[],"twenty");
     strcpy(ten[],"thirty");
     strcpy(ten[],"forty");
     strcpy(ten[],"fifty");
     strcpy(ten[],"sixty");
     strcpy(ten[],"seventy");
     strcpy(ten[],"eighty");
     strcpy(ten[],"ninety");

     while(scanf("%d",&number)!=EOF){
         a=number/;
         b=number/%;
         c=number%;

         if(a!=){    //当千位不为0时才打印
             flag=;
             printf("%s thousand",digit[a]);

             if(b!= || c!=)   //后面不为0才打印"and"
                 printf(" and ");
         }

         if(b!=){
             flag=;
             printf("%s hundred",digit[b]);

             if(c!=)
                 printf(" and ");
         }

         if(c<=){
             if(flag== && c==)  //前面已经打印，此时的0不打印
                 ;

             else if(flag== && c==)  //前面没有打印，此时的0打印
                 printf("zero");

             else
                 printf("%s",digit[c]);   //不为0直接打印
         }

         else{
             printf("%s",ten[c/]);  //打印十位数

             if(c%!=)   //如果还有个位数，打印"-"和个位数
                 printf("-%s",digit[c%]);
         }

         printf("\n");

     }

     return ;
 }