题目

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1
/ \
2 3

The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

题解

分析这道题,由根节点往叶节点方向走,就是从高位往地位加和的方向。也就是说,当遍历的节点往叶节点方向走一层的时候,该节点的值应为父节点的值*10+当前节点的值。

由此可以写出代码:

 1     int sumhelper(TreeNode root, int levelBase) {
 2         if(root == null)
 3             return 0;
 4             
 5         if(root.left == null && root.right == null) {
 6             return levelBase + root.val; 
 7         }
 8         
 9         int nextLevelBase = (levelBase + root.val)*10 ;
         int leftSubTreeSum = sumhelper(root.left, nextLevelBase);
         int rightSubTreeSum = sumhelper(root.right, nextLevelBase);
     
         return leftSubTreeSum + rightSubTreeSum;
     }
     
     public int sumNumbers(TreeNode root) {
         return sumhelper(root,0);
     }

Sum Root to Leaf Numbers leetcode java的更多相关文章

  1. Sum Root to Leaf Numbers——LeetCode

    Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number ...

  2. Sum Root to Leaf Numbers [LeetCode]

    Problem description: http://oj.leetcode.com/problems/sum-root-to-leaf-numbers/ Basic idea: To store ...

  3. LeetCode: Sum Root to Leaf Numbers 解题报告

    Sum Root to Leaf Numbers Given a binary tree containing digits from 0-9 only, each root-to-leaf path ...

  4. Leetcode之深度优先搜索(DFS)专题-129. 求根到叶子节点数字之和(Sum Root to Leaf Numbers)

    Leetcode之深度优先搜索(DFS)专题-129. 求根到叶子节点数字之和(Sum Root to Leaf Numbers) 深度优先搜索的解题详细介绍,点击 给定一个二叉树,它的每个结点都存放 ...

  5. 【LeetCode】129. Sum Root to Leaf Numbers 解题报告(Python)

    [LeetCode]129. Sum Root to Leaf Numbers 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/pr ...

  6. 【LeetCode】129. Sum Root to Leaf Numbers (2 solutions)

    Sum Root to Leaf Numbers Given a binary tree containing digits from 0-9 only, each root-to-leaf path ...

  7. LeetCode解题报告—— Sum Root to Leaf Numbers & Surrounded Regions & Single Number II

    1. Sum Root to Leaf Numbers Given a binary tree containing digits from 0-9 only, each root-to-leaf p ...

  8. 23. Sum Root to Leaf Numbers

    Sum Root to Leaf Numbers Given a binary tree containing digits from 0-9 only, each root-to-leaf path ...

  9. Java for LeetCode 129 Sum Root to Leaf Numbers

    Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number ...

随机推荐

  1. windows系统,联系人文件。个性化。

    韩梦飞沙  韩亚飞  313134555@qq.com  yue31313  han_meng_fei_sha ======= 文件下载链接:

  2. BZOJ4239 : 巴士走读

    考虑按时刻从早到晚模拟,计算出 f[i]:到达i点的最晚出发时间 g[i]:为了赶上第i辆车的最晚出发时间 然后将所有到达n号点的巴士按到达时间排序,查询的时候二分查找即可. 时间复杂度$O(n\lo ...

  3. ELASTIC 5.2部署并收集nginx日志

    elastic 5.2集群安装笔记   设计架构如下: nginx_json_log ->filebeat ->logstash ->elasticsearch ->kiban ...

  4. Eclipse 正则表达式 查找与替换

    CTRL + space in the textboxes gives you all kinds of suggestions for regular expression writing. 查找 ...

  5. 谨慎注意WebBrowser控件的DocumentCompleted事件

    引言 WebBrowser控件的DocumentCompleted事件一般就被认定为是在页面完全加载完毕后产生,而注释中也是这么写的: 但事实却并非如此. 首先它不一定会在完全加载完毕时才触发,有时就 ...

  6. Modbus TCP和Modbus Rtu协议的区别 转

    http://blog.csdn.net/educast/article/details/9177679   Modbus rtu和Modbus tcp两个协议的本质都是MODBUS协议,都是靠MOD ...

  7. Windows Phone本地数据库(SQLCE):11、使用LINQ查询数据库(翻译) (转)

    这是“windows phone mango本地数据库(sqlce)”系列短片文章的第十一篇. 为了让你开始在Windows Phone Mango中使用数据库,这一系列短片文章将覆盖所有你需要知道的 ...

  8. SpringBoot配置多数据源

    原文:https://www.jianshu.com/p/033e0ebeb617 项目中用到了两个数据库,分别是Oracle和Mysql,涉及到了多数据源问题,这里做下记录 官方讲解:https:/ ...

  9. Android Service总结04 之被绑定的服务 -- Bound Service

    Android Service总结04 之被绑定的服务 -- Bound Service 版本 版本说明 发布时间 发布人 V1.0 添加了Service的介绍和示例 2013-03-17 Skywa ...

  10. 【gitlab】首次提交本次代码到gitlab上,报错:Updates were rejected because the remote contains work that you do

    首次提交本次代码到gitlab上,报错:Updates were rejected because the remote contains work that you do 报错情况如下: 错误原因: ...