方法有三种:1.通过java代码batch方式,xml文件只需一条update语句。java代码繁琐

2.xml使用foreach,“;”分割多条update语句,要求:jdbc的url需加上allowMultiQueries=true。速度慢

3.xml使用foreach进行代码拼接,用了case...when...then...end,oracle好像不支持这种写法,mysql和sqlserver是可以的

xml文件:

<mapper namespace="com.dao.EmployeeDao">
<!--可以通过改变实体类的字段来验证映射-->
<update id="updateFirstWay">
update employee set employee_name = #{employeeName},
employee_gender = #{employeeGender},
employee_salary = #{employeeSalary},
dept_id = #{deptId}
where employee_id = #{employeeId}
</update> <update id="updateSecondWay">
<foreach collection="list" item="emp" separator=";">
update employee set employee_name = #{emp.employeeName},
employee_gender = #{emp.employeeGender},
employee_salary = #{emp.employeeSalary},
dept_id = #{emp.deptId}
where employee_id = #{emp.employeeId}
</foreach>
</update> <update id="updateThirdWay">
update employee set
employee_name= case employee_id
<foreach collection="list" item="emp">
when #{emp.employeeId} then #{emp.employeeName}
</foreach>
end, employee_gender= case employee_id
<foreach collection="list" item="emp">
when #{emp.employeeId} then #{emp.employeeGender}
</foreach>
end, employee_salary= case employee_id
<foreach collection="list" item="emp">
when #{emp.employeeId} then #{emp.employeeSalary}
</foreach>
end,dept_id= case employee_id
<foreach collection="list" item="emp">
when #{emp.employeeId} then #{emp.deptId}
</foreach>
end
where
<foreach collection="list" item="emp" separator="or">
employee_id = #{emp.employeeId}
</foreach>
</update>
</mapper>

  实体类:

package com.entity;

import java.math.BigDecimal;

public class Employee {

    private Integer employeeId;
private String employeeName;
private int employeeGender;
private BigDecimal employeeSalary;
private Integer deptId; public Employee() {
} public Employee(Integer employeeId, String employeeName, int employeeGender, BigDecimal employeeSalary, Integer deptId) {
this.employeeId = employeeId;
this.employeeName = employeeName;
this.employeeGender = employeeGender;
this.employeeSalary = employeeSalary;
this.deptId = deptId;
} @Override
public String toString() {
return "Employee{" +
"employeeId=" + employeeId +
", employeeName='" + employeeName + '\'' +
", employeeGender=" + employeeGender +
", employeeSalary=" + employeeSalary +
", deptId='" + deptId + '\'' +
'}';
} public Integer getEmployeeId() {
return employeeId;
} public void setEmployeeId(Integer employeeId) {
this.employeeId = employeeId;
} public String getEmployeeName() {
return employeeName;
} public void setEmployeeName(String employeeName) {
this.employeeName = employeeName;
} public int getEmployeeGender() {
return employeeGender;
} public void setEmployeeGender(int employeeGender) {
this.employeeGender = employeeGender;
} public BigDecimal getEmployeeSalary() {
return employeeSalary;
} public void setEmployeeSalary(BigDecimal employeeSalary) {
this.employeeSalary = employeeSalary;
} public Integer getDeptId() {
return deptId;
} public void setDeptId(Integer deptId) {
this.deptId = deptId;
}
}

  EmployeeDao.class:

void updateFirstWay(Employee employee);
int updateSecondWay(List<Employee> employees);
int updateThirdWay(List<Employee> employees);

  test代码:

@Test
public void testUpdateFirstWay() {
List<Employee> employees = new ArrayList<>();
employees.add(new Employee(10,"傲慢", 1, new BigDecimal(9999), 1));
employees.add(new Employee(11,"色欲", 0, new BigDecimal(8888), 2));
employees.add(new Employee(12,"怠惰", 1, new BigDecimal(7777), 3));
employees.add(new Employee(13,"贪婪", 1, new BigDecimal(6666), 4));
employees.add(new Employee(14,"愤怒", 1, new BigDecimal(5555), 5));
SqlSessionFactory sqlSessionFactory = SqlSessionFactoryUtil.getSqlSessionFactory();
SqlSession sqlSession = sqlSessionFactory.openSession(ExecutorType.BATCH);
EmployeeDao mapper = sqlSession.getMapper(EmployeeDao.class);
try {
for (int i = 0; i < employees.size(); i ++) {
mapper.updateFirstWay(employees.get(i));
if (i % 2 == 0 || i == employees.size() - 1) {
sqlSession.commit();
}
}
} catch (Exception e) {
sqlSession.rollback();
} finally {
sqlSession.close();
}
} @Test
public void testUpdateSecondWay() {
List<Employee> employees = new ArrayList<>();
employees.add(new Employee(15,"傲慢", 1, new BigDecimal(9999), 1));
employees.add(new Employee(16,"色欲", 1, new BigDecimal(8888), 2));
employees.add(new Employee(17,"怠惰", 1, new BigDecimal(7777), 3));
employees.add(new Employee(18,"贪婪", 0, new BigDecimal(6666), 4));
employees.add(new Employee(19,"愤怒", 1, new BigDecimal(5555), 5));
EmployeeDao employeeDao = MapperFactory.generateMapper(EmployeeDao.class);
employeeDao.updateSecondWay(employees);
} @Test
public void testUpdateThirdWay() {
List<Employee> employees = new ArrayList<>();
employees.add(new Employee(1,"傲慢", 1, new BigDecimal(9999), 1));
employees.add(new Employee(2,"色欲", 1, new BigDecimal(8888), 2));
EmployeeDao employeeDao = MapperFactory.generateMapper(EmployeeDao.class);
employeeDao.updateThirdWay(employees);
}

  总结:#{}里面写的是实体类的字段,已经测试过了。

最后:根据实际要求,每个字段是要判断是否为空的,例

<update id="updateFirstWay">
update employee set
<if test="b != null and b != ''">
employee_name = #{b},
</if>
<if test="c != null and c != ''">
employee_gender = #{c},
</if>
<if test="d != null and d != ''">
employee_salary = #{d},
</if>
<if test="e != null and e !=''">
dept_id = #{e}
</if>
where employee_id = #{a}
</update>

  因为当只修改部分数据库的列的值,而不是全部列的时候,就需要将不要修改的字段跳过。上面的代码有漏洞,当所有列都不修改的时候会出错,修改代码的话以后再说,累了

有个bug:数据库的binary类型,实体类写的Integer,但是写在ongl里面判断x != null and x != '',如果是0的话,那么这句话会跳过,false

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