「BJWC2012」冻结

传送门

Luogu

解题思路

分层图最短路，层与层之间的边的边权减半，然后就是板子了。

细节注意事项

• 咕咕咕。

参考代码

#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdio>
#include <cctype>
#include <cmath>
#include <ctime>
#include <queue>
#define rg register
using namespace std;
template < class T > inline void read(T& s) {
	s = 0; int f = 0; char c = getchar();
	while (!isdigit(c)) f |= c == '-', c = getchar();
	while (isdigit(c)) s = s * 10 + c - 48, c = getchar();
	s = f ? -s : s;
}

const int _ = 52 * 52;
const int __ = 1002 + 52 * 2002;

int tot, head[_], nxt[__ << 1], ver[__ << 1], w[__ << 1];
inline void Add_edge(int u, int v, int d)
{ nxt[++tot] = head[u], head[u] = tot, ver[tot] = v, w[tot] = d; }

int n, m, k, vis[_], dis[_];

inline int id(int u, int x) { return u + x * n; }

inline void Dijkstra() {
	static priority_queue < pair < int, int > > Q;
	memset(dis + 1, 0x3f, sizeof (int) * (n * (k + 1)));
	dis[1] = 0, Q.push(make_pair(0, 1));
	while (!Q.empty()) {
		int u = Q.top().second; Q.pop();
		if (vis[u]) continue; vis[u] = 1;
		for (rg int i = head[u]; i; i = nxt[i]) {
			int v = ver[i];
			if (dis[v] > dis[u] + w[i])
				dis[v] = dis[u] + w[i], Q.push(make_pair(-dis[v], v));
		}
	}
}

int main() {
#ifndef ONLINE_JUDGE
	freopen("cpp.in", "r", stdin);
	freopen("cpp.out", "w", stdout);
#endif
	read(n), read(m), read(k);
	for (rg int u, v, d; m--; ) {
		read(u), read(v), read(d);
		Add_edge(u, v, d), Add_edge(v, u, d);
		for (rg int i = 1; i <= k; ++i) {
			Add_edge(id(u, i), id(v, i), d);
			Add_edge(id(v, i), id(u, i), d);
			Add_edge(id(u, i - 1), id(v, i), d >> 1);
			Add_edge(id(v, i - 1), id(u, i), d >> 1);
		}
	}
	Dijkstra();
	int ans = 2147483647;
	for (rg int i = 0; i <= k; ++i)
		ans = min(ans, dis[id(n, i)]);
	printf("%d\n", ans);
	return 0;
}

完结撒花 \(qwq\)