PAT 1009 Product of Polynomials
This time, you are supposed to find A×B where A and B are two polynomials.
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:
K N1 aN1 N2 aN2 ... NK aNK
where K is the number of nonzero terms in the polynomial, Ni and aNi (,) are the exponents and coefficients, respectively. It is given that 1, 0.
Output Specification:
For each test case you should output the product of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate up to 1 decimal place.
Sample Input:
2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output:
3 3 3.6 2 6.0 1 1.6
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define maxnum 100005 double a[] = {};
double b[] = {};
double c[maxnum] = {}; int main(){
int n;cin >> n;
int t;
for(int i=;i < n;i++){
int x;double y;
cin >> x >> y;
a[x] = y;
if(!i)t = x;
}
int m;cin >> m;
int start;
for(int i=;i < m;i++){
int x;double y;
cin >> x >> y;
b[x] = y;
if(!i) start = x;
} for(int i=;i < t+;i++){
for(int j=;j < start+;j++){
c[i+j] += a[i]*b[j];
}
} int cnt = ;
for(int i=;i < maxnum;i++)if(c[i])cnt++;
cout << cnt; for(int i=maxnum-;i>=;i--){
if(c[i]) printf(" %d %.1lf",i,c[i]);
} return ;
}
空间开的有点小炸,做了一下优化就好了,再一次理解错了提议,K<10,不一定就项系数<10,还好这题没出毒瘤卡边界数据,在超过1e5的地方直接放弃了。。
PAT 1009 Product of Polynomials的更多相关文章
- PAT 1009 Product of Polynomials (25分) 指数做数组下标,系数做值
题目 This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: E ...
- PAT 1009 Product of Polynomials 模拟
This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each ...
- PAT甲 1009. Product of Polynomials (25) 2016-09-09 23:02 96人阅读 评论(0) 收藏
1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...
- PAT 甲级 1009 Product of Polynomials (25)(25 分)(坑比较多,a可能很大,a也有可能是负数,回头再看看)
1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two ...
- pat 甲级 1009. Product of Polynomials (25)
1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...
- PTA (Advanced Level) 1009 Product of Polynomials
1009 Product of Polynomials This time, you are supposed to find A×B where A and B are two polynomial ...
- 1009 Product of Polynomials (25 分)
1009 Product of Polynomials (25 分) This time, you are supposed to find A×B where A and B are two pol ...
- PATA 1009. Product of Polynomials (25)
1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...
- 1009 Product of Polynomials (25分) 多项式乘法
1009 Product of Polynomials (25分) This time, you are supposed to find A×B where A and B are two po ...
随机推荐
- jquery.form.js实现将form提交转为ajax方式提交的方法
本文实例讲述了jquery.form.js实现将form提交转为ajax方式提交的方法.分享给大家供大家参考.具体分析如下: 这个框架集合form提交.验证.上传的功能. 这个框架必须和jquery完 ...
- HashMap的实现原理-----哈希讲解
哈希,英文名Hash.他就像是一个隔壁家的孩子一样,伴随着码工们的成长.听到他们的名字,我们都觉得很高大上. 在写程序的时候,一般我们都是这样被教育的:这个事情搞不定?用哈希呀! 在面试的时候,一般是 ...
- vscode已有64位版本。
我的操作系统是win10 Family版本. vscode不知道什么鬼,只要开启没动任何操作,cpu就占到30%. 于是我打开任务管理器,选中vscode进程->转到详细信息->结束cpu ...
- Add Two Numbers ,使用链表参数
# Definition for singly-linked list. class ListNode(object): def __init__(self, x): self.val = x sel ...
- python网络编程基础之socket粘包现象
粘包现象两种 登陆 #服务端import json import socket server=socket.socket()#创建socket对象 ip_port=('127.0.0.1',8001) ...
- Android多线程模型
作为开发者,我们都知道在开发过程中遇到耗时操作那是不可避免的,例如网络请求.文件读写.数据库操作等等.Android是单线程模型,这意味着Android UI操作并不是线程安全的并 ...
- 力扣(LeetCode)500. 键盘行
给定一个单词列表,只返回可以使用在键盘同一行的字母打印出来的单词.键盘如下图所示. 示例: 输入: ["Hello", "Alaska", "Dad& ...
- ubuntu 配置sublime text3
1安装st3(http://blog.csdn.net/zhaoyu106/article/details/52858962) sudo apt-get update sudo apt-get ins ...
- pandas的时间戳
pandas时间: p1=pd.Timestamp(2018, 2, 3) p1输出:2018-02-03 00:00:00 p1输出类型:<class 'pandas._libs.tslib. ...
- eclipse 快捷键Open Implementation 直接退出
遇到eclipse 快捷键Open Implementation 非正常退出.直接关闭的现象. 网查了一下 碰到一篇博客说 和google 输入法有关 卸载了google 输入法就好了 半信 ...