const char *转化为char *的方法

直接将const char *赋值给char *是错误的，编译器不允许这种操作。

#include "stdio.h"
#include "string.h"
int main()
{
    //方式1 strcpy
    //方式1.1
    //const char *cpCh = "const char";
    //char ch[64]={0};
    //char *pCh = ch;　　//是不是画蛇添足啊??
    //strcpy(pCh, cpCh);

    //方式1.2
    const char *cpCh = "const char";
    int nLen = strlen(cpCh);
    char *pCh = new char[nLen + ];
    strcpy(pCh, cpCh);

    //方式2 const_cast<>()
    //const char *cpCh = "const char";
    //char *pCh = const_cast<char *>(cpCh);//DO not forget '()'

    printf("%s", pCh);
    return ;
}