【Gym 100971K】Palindromization

Mihahim has a string s. He wants to delete exactly one character from it so that the resulting string would be a palindrome. Determine if he can do it, and if he can, what character should be deleted.

Input

The input contains a string s of length (2 ≤ |s| ≤ 200000), consisting of lowercase Latin letters.

Output

If the solution exists, output «YES» (without quotes) in the first line. Then in the second line output a single integer x — the number of the character that should be removed from s so that the resulting string would be a palindrome. The characters in the string are numbered from 1. If there are several possible solutions, output any of them.

If the solution doesn't exist, output «NO» (without quotes).

Examples

input

evertree

output

YES
2

input

emerald

output

NO

input

aa

output

YES
2

从左右两边往中间移动，如果相同，l++，r--，如果不同，第一次循环i==0时，则让l++，第二次循环则让r--，最后判断不同的出现了几次。如果dif是0，l>=r代表本身就是回文，则去掉l位置的字符。

#include <cstring>
#include <cstdio>
#define N 100005
char s[N<<];
int len,l,r,dif,at;
int main() {
    scanf("%s",s);
    len=strlen(s);
    for(int i=;i<;i++){
        dif=;
        l=,r=len-;
        while(l<r){
            if(s[l]!=s[r]){
                dif++;
                if(i){
                    at=r;
                    r--;
                }else {
                    at=l;
                    l++;
                }
            }
            if(s[l]==s[r]){
                l++;
                r--;
            }
        }
        if(l>=r&&dif==)at=l;
        if(dif<){
            printf("YES\n%d\n",at+);
            break;
        }
    }
    if(dif>)puts("NO");
}