hdoj 1002 A+B(2)

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 

Sample Input

2 1 2 112233445566778899 998877665544332211

 

Sample Output

Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110

 

 #include <stdio.h>
 #include <string.h>
 #include <math.h>
 #define N 1010
 int t;
 char str1[N], str2[N];
 int sum1[N], sum2[N];
 int main()
 {
     int len1, len2, num;
     scanf("%d", &t);
     //getchar();
     num = ;
     while(t--)
     {
         memset(sum1, , sizeof(sum1));
         memset(sum2, , sizeof(sum2));
         scanf("%s", str1);
         scanf("%s", str2);
         len1 = strlen(str1);
         len2 = strlen(str2);
         int i, j;
         for(i = len1-, j = ; i >= ; i--)
             sum1[j++] = sum1[j] + str1[i] - '';
         for(i = len2-, j = ; i >= ; i--)
             sum2[j++] = sum2[j] + str2[i] - '';
         for(i = ; i < N; i++)

         {
             sum2[i] += sum1[i];
             if(sum2[i] >= )
             {
                 sum2[i] -= ;
                 sum2[i+]++;
             }
         }
         for(i = N-; i>= && sum2[i]==; i--)
             ;
         printf("Case %d:\n", num++);
         printf("%s + %s = ", str1, str2);
         if(i>=)
         {
             for(; i >= ; i--)
                 printf("%d", sum2[i]);
         }
         else
             printf("");
         if(t)//注意格式
             printf("\n\n");
         else
             printf("\n");
     }
     return ;
 }