Problem 1: Bovine Ballet [Brian Dean, 2013]

In an attempt to challenge the stereotypical perception of cows as awkward
creatures, Farmer John's prize cow Bessie has signed up for an introductory
ballet class. Her final performance is next week, and FJ wants to help her
by building a rectangular stage large enough so that she can perform her
entire dance without falling off the edges.

Bessie's dance will take place on a rectangular stage consisting of a grid
of 1 x 1 square cells. Bessie's four feet are described concisely as follows:

FR: Front right foot
FL: Front left foot
RR: Rear right foot
RL: Rear left foot

Her four feet start out in 4 adjacent cells forming a square as follows,
with Bessie facing north.

FL FR
RL RR

Bessie's dance follows a series of N instructions (1 <= N <= 1000), where
each instruction tells her to either move one foot by one cell or to pivot
90 degrees clockwise.

Instructions to move a foot consist of 3 characters, the first two
identifying the foot to move, and the final character specifying the
direction of movement (F = forward, B = back, R = right, L = left). For
example, "FRF" means Bessie should move her front right foot forward one
cell, and "RLR" means she should move her rear left foot right one cell.
Of course, the direction of movement is relative to the direction Bessie is
facing.

Instruction to pivot are also 3 characters, the first two specifying the
single foot that Bessie keeps planted, around which she rotates 90 degrees
clockwise. The last character is "P" (for pivot). For example, the
instruction "FRP" means Bessie should pivot 90 degrees clockwise about her
stationary front right foot. This means that if her feet are currently
situated as follows (with Bessie facing north)

.. .. ..
.. .. FR
.. FL ..
.. RL RR

then the after the instruction "FRP" her feet will be located as follows,
with Bessie now facing east:

RL FL ..
RR .. FR
.. .. ..
.. .. ..

Given the N instructions in Bessie's dance, please compute the minimum area
of a rectangular stage necessary contain her feet during the entire dance.

If Bessie clumsily ever moves one foot onto the same cell as another foot,
she will trip and fail to complete the dance; in this case, please output
-1. Note that this is the only case where Bessie will trip; she has become
quite flexible after all her practice, and can easily move her feet into
rather strange configurations (for example, with her back feet farther
forward than her front feet).

PROBLEM NAME: ballet

INPUT FORMAT:

* Line 1: The integer N.

* Lines 2..1+N: Each line contains one of the 3-character instructions
in Bessie's dance.

SAMPLE INPUT (file ballet.in):

3
FRF
FRP
RLB

INPUT DETAILS:

Bessie's dance consists of the instructions "front right foot forward",
"front right foot pivot", and "rear left foot back".

OUTPUT FORMAT:

* Line 1: The minimum area of a rectangular stage necessary to contain
Bessie's feet during the entire dance, or -1 if Bessie trips.

SAMPLE OUTPUT (file ballet.out):

16

OUTPUT DETAILS:

Bessie needs a 4 x 4 stage to complete her dance. Her feet move as follows:

.. .. .. ..
.. .. .. .. (facing north)
.. .. FL FR
.. .. RL RR

After FRF:

.. .. .. ..
.. .. .. FR (facing north)
.. .. FL ..
.. .. RL RR

After FRP:

.. RL FL ..
.. RR .. FR (facing east)
.. .. .. ..
.. .. .. ..

After RLB:

RL .. FL ..
.. RR .. FR (facing east)
.. .. .. ..
.. .. .. ..

Usaco_Contest_2013_Open_Bovine Problem 1. Bovine Ballet的更多相关文章

  1. 洛谷P3611 [USACO17JAN]Cow Dance Show奶牛舞蹈

    题目描述 After several months of rehearsal, the cows are just about ready to put on their annual dance p ...

  2. 1675: [Usaco2005 Feb]Rigging the Bovine Election 竞选划区(题解第二弹)

    1675: [Usaco2005 Feb]Rigging the Bovine Election 竞选划区 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit:  ...

  3. 1675: [Usaco2005 Feb]Rigging the Bovine Election 竞选划区(题解第一弹)

    1675: [Usaco2005 Feb]Rigging the Bovine Election 竞选划区 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit:  ...

  4. 1199 Problem B: 大小关系

    求有限集传递闭包的 Floyd Warshall 算法(矩阵实现) 其实就三重循环.zzuoj 1199 题 链接 http://acm.zzu.edu.cn:8000/problem.php?id= ...

  5. No-args constructor for class X does not exist. Register an InstanceCreator with Gson for this type to fix this problem.

    Gson解析JSON字符串时出现了下面的错误: No-args constructor for class X does not exist. Register an InstanceCreator ...

  6. C - NP-Hard Problem(二分图判定-染色法)

    C - NP-Hard Problem Crawling in process... Crawling failed Time Limit:2000MS     Memory Limit:262144 ...

  7. Time Consume Problem

    I joined the NodeJS online Course three weeks ago, but now I'm late about 2 weeks. I pay the codesch ...

  8. Programming Contest Problem Types

        Programming Contest Problem Types Hal Burch conducted an analysis over spring break of 1999 and ...

  9. hdu1032 Train Problem II (卡特兰数)

    题意: 给你一个数n,表示有n辆火车,编号从1到n,入站,问你有多少种出站的可能.    (题于文末) 知识点: ps:百度百科的卡特兰数讲的不错,注意看其参考的博客. 卡特兰数(Catalan):前 ...

随机推荐

  1. 集群环境(session多服务器共享的方案梳理)

    目前业界解决session共享的几种思路,我总结如下: 第一种办法:把原来存储在服务器磁盘上的session数据存储到客户端的cookie中去. 这样子,就不需要涉及到数据共享了.a客户端请求的时候, ...

  2. 基于IAR6或者IAR7建立STM32开发工程(通过实际测试,使用IAR6.30.4)

    IAR和keil两个开发平台都是arm开发当中比较流行的平台,keil4的版本之间,可以兼容,但是版本4和版本5还是不兼容的,但是IAR的兼容性更加差,好像6.30.x之间是能够兼容的吧,没有实测过, ...

  3. Java监听器Listener使用说明

    转载:http://blog.csdn.net/meng2602956882/article/details/13511587 1.什么是Java监听器 监听器也叫Listener,是Servlet的 ...

  4. virtual function c++

    之前一直不明白为什么要用虚函数,我只知道这样的规则, Base b = new derived(); b->do(); 调用的是子类的do(): virtue class只是一个虚拟的,调用的是 ...

  5. Android 标题栏(2)

    本文来自网易云社区 作者:孙圣翔 添加ActionProvider 1.在menu菜单中添加app:actionProviderClass属性: <item     android:id=&qu ...

  6. Selenium WebDriver- 操作JavaScript的confirm弹窗

    #encoding=utf-8 import unittest import time from selenium import webdriver from selenium.webdriver i ...

  7. Selenium WebDriver-actionchain模拟鼠标右键操作

    #encoding=utf-8 import unittest import time from selenium import webdriver from selenium.webdriver i ...

  8. Selenium WebDriver-通过键盘事件操作浏览器

    #encoding=utf-8 import unittest import time import chardet from selenium import webdriver class Visi ...

  9. 2.新手必须掌握的Linux命令

    第2章 新手必须掌握的Linux命令 章节简述: 本章首先介绍系统内核和Shell终端的关系与作用,然后介绍Bash解释器的4大优势并学习Linux命令的执行方法.经验丰富的运维人员可以通过合理地组合 ...

  10. django 的序列化

    关于Django中的序列化主要应用在将数据库中检索的数据返回给客户端用户,特别的Ajax请求一般返回的为Json格式. 我们从数据库取出数据的格式有三种:1.all()返回的是QuerySet对象:2 ...