Oracle11g R2创建PASSWORD_VERIFY_FUNCTION对应密码复杂度验证函数步骤

运行测试环境:数据库服务器Oracle Linux 5.8 + Oracle 11g R2数据库

相关工具:PL/SQL软件(连接Linux下的Oracle数据库),SecureCRT软件(远程连接Linux服务器)

详细步骤:

1、连接上Linux数据库服务器,切换到Oracle数据库用户桌面,打开终端,进入到环境变量$ORACLE_HOME目录

Last login: Fri Dec 11 13:26:18 2015 from 192.168.1.100
[root@Linux主机名 ~]# su - oracle
[oracle@Linux主机名 dbhome_1]$ cd $ORACLE_HOME/rdbms/admin
[oracle@Linux主机名 admin]$

2、查看Oracle11g数据库提供的默认密码复杂度函数脚本(Oracle安装目录下的/rdbms/admin/utlpwdmg.sql文件)

[oracle@Linux主机名 admin]$ cat $ORACLE_HOME/rdbms/admin/utlpwdmg.sql

脚本详细内容详见文章末尾

3、登录Oracle数据库并执行Oracle11g数据库提供的默认密码复杂度函数脚本

[oracle@Linux主机名 admin]$ sqlplus /nolog

SQL*Plus: Release 11.2.0.1.0 Production on Fri Dec 11 13:33:58 2015

Copyright (c) 1982, 2009, Oracle.  All rights reserved.

SQL> conn /as sysdba
Connected.
SQL> @?/rdbms/admin/utlpwdmg.sql

Function created.

Profile altered.

Function created.

SQL>

4、在PL/SQL中创建用户的资源文件,执行下面语句

CREATE PROFILE 资源文件名 LIMIT 
  SESSIONS_PER_USER UNLIMITED 
  CPU_PER_SESSION UNLIMITED 
  CPU_PER_CALL UNLIMITED 
  CONNECT_TIME UNLIMITED 
  IDLE_TIME 600  --10小时连续不活动的话系统自动断开连接
  LOGICAL_READS_PER_SESSION UNLIMITED 
  LOGICAL_READS_PER_CALL UNLIMITED 
  COMPOSITE_LIMIT UNLIMITED 
  PRIVATE_SGA UNLIMITED 
  FAILED_LOGIN_ATTEMPTS 10  --指定锁定用户的登录失败次数为10次,超过10次则系统被自动锁定
  PASSWORD_LIFE_TIME 180  --指定用户同一密码锁允许使用的天数为180天
  PASSWORD_REUSE_TIME UNLIMITED 
  PASSWORD_REUSE_MAX UNLIMITED 
  PASSWORD_LOCK_TIME 1  --指定用户被锁定天数为1天
  PASSWORD_GRACE_TIME 10 --数据库发出警告到登录失效前的宽限天数 
  PASSWORD_VERIFY_FUNCTION verify_function_11G
 
5、测试更新用户密码

--创建用户并使用自定义的配置文件
create user 用户名 identified by 密码 default tablespace 默认表空间名 temporary tablespace 临时表空间名 profile 资源文件名;

--用户授权
grant connect,resource,exp_full_database,imp_full_database to 用户名;

--更新用户密码为简单的字符串
alter user 用户名 identified by 123456;

--更新用户密码为复杂的字符串
alter user 用户名 identified by Csdn_20151211;

6、结论:发现简单密码无法更新,复杂的密码更新成功。

附:$ORACLE_HOME/rdbms/admin/utlpwdmg.sql脚本源文件内容

Rem
Rem $Header: utlpwdmg.sql 02-aug-2006.08:18:05 asurpur Exp $
Rem
Rem utlpwdmg.sql
Rem
Rem Copyright (c) 2006, Oracle. All rights reserved. 
Rem
Rem    NAME
Rem      utlpwdmg.sql - script for Default Password Resource Limits
Rem
Rem    DESCRIPTION
Rem      This is a script for enabling the password management features
Rem      by setting the default password resource limits.
Rem
Rem    NOTES
Rem      This file contains a function for minimum checking of password
Rem      complexity. This is more of a sample function that the customer
Rem      can use to develop the function for actual complexity checks that the
Rem      customer wants to make on the new password.
Rem
Rem    MODIFIED   (MM/DD/YY)
Rem    asurpur     05/30/06 - fix - 5246666 beef up password complexity check
Rem    nireland    08/31/00 - Improve check for username=password. #1390553
Rem    nireland    06/28/00 - Fix null old password test. #1341892
Rem    asurpur     04/17/97 - Fix for bug479763
Rem    asurpur     12/12/96 - Changing the name of password_verify_function
Rem    asurpur     05/30/96 - New script for default password management
Rem    asurpur     05/30/96 - Created
Rem

-- This script sets the default password resource parameters
-- This script needs to be run to enable the password features.
-- However the default resource parameters can be changed based
-- on the need.
-- A default password complexity function is also provided.
-- This function makes the minimum complexity checks like
-- the minimum length of the password, password not same as the
-- username, etc. The user may enhance this function according to
-- the need.
-- This function must be created in SYS schema.
-- connect sys/<password> as sysdba before running the script

CREATE OR REPLACE FUNCTION verify_function_11G
(username varchar2,
  password varchar2,
  old_password varchar2)
  RETURN boolean IS
   n boolean;
   m integer;
   differ integer;
   isdigit boolean;
   ischar  boolean;
   ispunct boolean;
   db_name varchar2(40);
   digitarray varchar2(20);
   punctarray varchar2(25);
   chararray varchar2(52);
   i_char varchar2(10);
   simple_password varchar2(10);
   reverse_user varchar2(32);

BEGIN
   digitarray:= '0123456789';
   chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';

-- Check for the minimum length of the password
   IF length(password) < 8 THEN
      raise_application_error(-20001, 'Password length less than 8');
   END IF;

-- Check if the password is same as the username or username(1-100)
   IF NLS_LOWER(password) = NLS_LOWER(username) THEN
     raise_application_error(-20002, 'Password same as or similar to user');
   END IF;
   FOR i IN 1..100 LOOP
      i_char := to_char(i);
      if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN
        raise_application_error(-20005, 'Password same as or similar to user name ');
      END IF;
    END LOOP;

-- Check if the password is same as the username reversed
  
   FOR i in REVERSE 1..length(username) LOOP
     reverse_user := reverse_user || substr(username, i, 1);
   END LOOP;
   IF NLS_LOWER(password) = NLS_LOWER(reverse_user) THEN
     raise_application_error(-20003, 'Password same as username reversed');
   END IF;

-- Check if the password is the same as server name and or servername(1-100)
   select name into db_name from sys.v$database;
   if NLS_LOWER(db_name) = NLS_LOWER(password) THEN
      raise_application_error(-20004, 'Password same as or similar to server name');
   END IF;
   FOR i IN 1..100 LOOP
      i_char := to_char(i);
      if NLS_LOWER(db_name)|| i_char = NLS_LOWER(password) THEN
        raise_application_error(-20005, 'Password same as or similar to server name ');
      END IF;
    END LOOP;

-- Check if the password is too simple. A dictionary of words may be
   -- maintained and a check may be made so as not to allow the words
   -- that are too simple for the password.
   IF NLS_LOWER(password) IN ('welcome1', 'database1', 'account1', 'user1234', 'password1', 'oracle123', 'computer1', 'abcdefg1', 'change_on_install') THEN
      raise_application_error(-20006, 'Password too simple');
   END IF;

-- Check if the password is the same as oracle (1-100)
    simple_password := 'oracle';
    FOR i IN 1..100 LOOP
      i_char := to_char(i);
      if simple_password || i_char = NLS_LOWER(password) THEN
        raise_application_error(-20007, 'Password too simple ');
      END IF;
    END LOOP;

-- Check if the password contains at least one letter, one digit
   -- 1. Check for the digit
   isdigit:=FALSE;
   m := length(password);
   FOR i IN 1..10 LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(digitarray,i,1) THEN
            isdigit:=TRUE;
             GOTO findchar;
         END IF;
      END LOOP;
   END LOOP;

IF isdigit = FALSE THEN
      raise_application_error(-20008, 'Password must contain at least one digit, one character');
   END IF;
   -- 2. Check for the character
   <<findchar>>
   ischar:=FALSE;
   FOR i IN 1..length(chararray) LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(chararray,i,1) THEN
            ischar:=TRUE;
             GOTO endsearch;
         END IF;
      END LOOP;
   END LOOP;
   IF ischar = FALSE THEN
      raise_application_error(-20009, 'Password must contain at least one \
              digit, and one character');
   END IF;

<<endsearch>>
   -- Check if the password differs from the previous password by at least
   -- 3 letters
   IF old_password IS NOT NULL THEN
     differ := length(old_password) - length(password);

differ := abs(differ);
     IF differ < 3 THEN
       IF length(password) < length(old_password) THEN
         m := length(password);
       ELSE
         m := length(old_password);
       END IF;

FOR i IN 1..m LOOP
         IF substr(password,i,1) != substr(old_password,i,1) THEN
           differ := differ + 1;
         END IF;
       END LOOP;

IF differ < 3 THEN
         raise_application_error(-20011, 'Password should differ from the \
            old password by at least 3 characters');
       END IF;
     END IF;
   END IF;
   -- Everything is fine; return TRUE ;  
   RETURN(TRUE);
END;
/

-- This script alters the default parameters for Password Management
-- This means that all the users on the system have Password Management
-- enabled and set to the following values unless another profile is
-- created with parameter values set to different value or UNLIMITED
-- is created and assigned to the user.

ALTER PROFILE DEFAULT LIMIT
PASSWORD_LIFE_TIME 180
PASSWORD_GRACE_TIME 7
PASSWORD_REUSE_TIME UNLIMITED
PASSWORD_REUSE_MAX UNLIMITED
FAILED_LOGIN_ATTEMPTS 10
PASSWORD_LOCK_TIME 1
PASSWORD_VERIFY_FUNCTION verify_function_11G;

-- Below is the older version of the script

-- This script sets the default password resource parameters
-- This script needs to be run to enable the password features.
-- However the default resource parameters can be changed based
-- on the need.
-- A default password complexity function is also provided.
-- This function makes the minimum complexity checks like
-- the minimum length of the password, password not same as the
-- username, etc. The user may enhance this function according to
-- the need.
-- This function must be created in SYS schema.
-- connect sys/<password> as sysdba before running the script

CREATE OR REPLACE FUNCTION verify_function
(username varchar2,
  password varchar2,
  old_password varchar2)
  RETURN boolean IS
   n boolean;
   m integer;
   differ integer;
   isdigit boolean;
   ischar  boolean;
   ispunct boolean;
   digitarray varchar2(20);
   punctarray varchar2(25);
   chararray varchar2(52);

BEGIN
   digitarray:= '0123456789';
   chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
   punctarray:='!"#$%&()``*+,-/:;<=>?_';

-- Check if the password is same as the username
   IF NLS_LOWER(password) = NLS_LOWER(username) THEN
     raise_application_error(-20001, 'Password same as or similar to user');
   END IF;

-- Check for the minimum length of the password
   IF length(password) < 4 THEN
      raise_application_error(-20002, 'Password length less than 4');
   END IF;

-- Check if the password is too simple. A dictionary of words may be
   -- maintained and a check may be made so as not to allow the words
   -- that are too simple for the password.
   IF NLS_LOWER(password) IN ('welcome', 'database', 'account', 'user', 'password', 'oracle', 'computer', 'abcd') THEN
      raise_application_error(-20002, 'Password too simple');
   END IF;

-- Check if the password contains at least one letter, one digit and one
   -- punctuation mark.
   -- 1. Check for the digit
   isdigit:=FALSE;
   m := length(password);
   FOR i IN 1..10 LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(digitarray,i,1) THEN
            isdigit:=TRUE;
             GOTO findchar;
         END IF;
      END LOOP;
   END LOOP;
   IF isdigit = FALSE THEN
      raise_application_error(-20003, 'Password should contain at least one digit, one character and one punctuation');
   END IF;
   -- 2. Check for the character
   <<findchar>>
   ischar:=FALSE;
   FOR i IN 1..length(chararray) LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(chararray,i,1) THEN
            ischar:=TRUE;
             GOTO findpunct;
         END IF;
      END LOOP;
   END LOOP;
   IF ischar = FALSE THEN
      raise_application_error(-20003, 'Password should contain at least one \
              digit, one character and one punctuation');
   END IF;
   -- 3. Check for the punctuation
   <<findpunct>>
   ispunct:=FALSE;
   FOR i IN 1..length(punctarray) LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(punctarray,i,1) THEN
            ispunct:=TRUE;
             GOTO endsearch;
         END IF;
      END LOOP;
   END LOOP;
   IF ispunct = FALSE THEN
      raise_application_error(-20003, 'Password should contain at least one \
              digit, one character and one punctuation');
   END IF;

<<endsearch>>
   -- Check if the password differs from the previous password by at least
   -- 3 letters
   IF old_password IS NOT NULL THEN
     differ := length(old_password) - length(password);

IF abs(differ) < 3 THEN
       IF length(password) < length(old_password) THEN
         m := length(password);
       ELSE
         m := length(old_password);
       END IF;

differ := abs(differ);
       FOR i IN 1..m LOOP
         IF substr(password,i,1) != substr(old_password,i,1) THEN
           differ := differ + 1;
         END IF;
       END LOOP;

IF differ < 3 THEN
         raise_application_error(-20004, 'Password should differ by at \
         least 3 characters');
       END IF;
     END IF;
   END IF;
   -- Everything is fine; return TRUE ;  
   RETURN(TRUE);
END;
/

-- This script alters the default parameters for Password Management
-- This means that all the users on the system have Password Management
-- enabled and set to the following values unless another profile is
-- created with parameter values set to different value or UNLIMITED
-- is created and assigned to the user.

-- Enable this if you want older version of the Password Profile parameters
-- ALTER PROFILE DEFAULT LIMIT
-- PASSWORD_LIFE_TIME 60
-- PASSWORD_GRACE_TIME 10
-- PASSWORD_REUSE_TIME 1800
-- PASSWORD_REUSE_MAX UNLIMITED
-- FAILED_LOGIN_ATTEMPTS 3
-- PASSWORD_LOCK_TIME 1/1440
-- PASSWORD_VERIFY_FUNCTION verify_function;

Oracle11g R2创建PASSWORD_VERIFY_FUNCTION对应密码复杂度验证函数步骤的更多相关文章

  1. Oracle11g R2创建PASSWORD_VERIFY_FUNCTION相应password复杂度验证函数步骤

    Oracle11g R2创建PASSWORD_VERIFY_FUNCTION相应密码复杂度验证函数步骤 运行測试环境:数据库服务器Oracle Linux 5.8 + Oracle 11g R2数据库 ...

  2. oracle 11g/12c 密码复杂度验证设置

    ############################################################################### ###### 11g ###### ## ...

  3. Win7 32位安装Oracle11g R2 图解示例

    Win7 32位操作系统安装Oracle11g R2 图解示例.废话不说了,直接上图. 1.下载的两个oracle 11gR2压缩包解压到单独的文件夹中. 2.找到解压的database文件夹中的Se ...

  4. ORACLE11g R2【RAC+ASM→单实例FS】

    ORACLE11g R2[RAC+ASM→单实例FS] 11g R2 RAC+ASMà单实例FS的DG,建议禁用OMF. 本演示案例所用环境:   primary standby OS Hostnam ...

  5. ORACLE11g R2【单实例 FS→单实例FS】

    ORACLE11g R2[单实例 FS→单实例FS] 本演示案例所用环境:   primary standby OS Hostname pry std OS Version RHEL6.5 RHEL6 ...

  6. ORACLE11g R2【RAC+ASM→RAC+ASM】

    ORACLE11g R2[RAC+ASM→RAC+ASM] 本演示案例所用环境:RAC+ASM+OMF   primary standby OS Hostname node1,node2 dgnode ...

  7. centos7远程安装oracle11g R2详细教程-解决一切问题

    相关链接与资源: sqldevelper(各种操作系统的oracle客户端) http://www.oracle.com/technetwork/cn/developer-tools/sql-deve ...

  8. Oracle 11g R2创建数据库之手工建库方式

    在之前的博文当中梳理了关于DBCA静默方式创建数据库的过程,本文就手工通过SQL*PLUS客户端采用CREATE DATABASE语句创建数据库.这种建库方式就是完全使用手工SQL语句创建数据库,通常 ...

  9. Oracle11g手动创建数据库方法

    Oracle11g手动创建数据库方法 参考网页http://www.th7.cn/db/Oracle/201311/36926.shtml 安装路径 我的安装路径是:E:\app\admin\prod ...

随机推荐

  1. angularjs bind与model配合双向绑定 表达式方法输出

    <!doctype html><html lang="en"><head> <meta charset="UTF-8" ...

  2. 一起做orb-slam(2)

    1.ushort用法? USHORT is a macro which is not part of the official C++ language (it's probably defined ...

  3. css 的一些知识点的整理

    css的一些标签整理   background-attachment: scroll;背景图可滚动 background-attachment: fixed; 固定背景的位置,不随着滚动条移动而移动 ...

  4. 模板 AC自动机

    题目描述 有$N$ 个由小写字母组成的模式串以及一个文本串$T$ .每个模式串可能会在文本串中出现多次.你需要找出哪些模式串在文本串$T$ 中出现的次数最多. 输入输出格式 输入格式: 输入含多组数据 ...

  5. [SHOI2008]小约翰的游戏John

    Description 小约翰经常和他的哥哥玩一个非常有趣的游戏:桌子上有n堆石子,小约翰和他的哥哥轮流取石子,每个人取 的时候,可以随意选择一堆石子,在这堆石子中取走任意多的石子,但不能一粒石子也不 ...

  6. [HNOI2013]比赛

    题目描述 沫沫非常喜欢看足球赛,但因为沉迷于射箭游戏,错过了最近的一次足球联赛.此次联 赛共N支球队参加,比赛规则如下: (1) 每两支球队之间踢一场比赛. (2) 若平局,两支球队各得1分. (3) ...

  7. LOJ #6119. 「2017 山东二轮集训 Day7」国王

    Description 在某个神奇的大陆上,有一个国家,这片大陆的所有城市间的道路网可以看做是一棵树,每个城市要么是工业城市,要么是农业城市,这个国家的人认为一条路径是 exciting 的,当且仅当 ...

  8. [SPOJ 287] Smart Network Administrator 二分答案+网络流

    The citizens of a small village are tired of being the only inhabitants around without a connection ...

  9. ●POJ 2007 Scrambled Polygon

    题链: http://poj.org/problem?id=2007 题解: 计算几何,极角排序 按样例来说,应该就是要把凸包上的i点按 第三像限-第四像限-第一像限-第二像限 的顺序输出. 按 叉积 ...

  10. UVA12186

    给出一个树状关系图,公司里只有一个老板编号为0,其他人员从1开始编号.除了老板,每个人都有一个直接上司,没有下属的员工成为工人. 工人们想写一份加工资的请愿书,只有当不少于员工的所有下属的T%人递交请 ...