A1089. Insert or Merge
According to Wikipedia:
Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there. It repeats until no input elements remain.
Merge sort works as follows: Divide the unsorted list into N sublists, each containing 1 element (a list of 1 element is considered sorted). Then repeatedly merge two adjacent sublists to produce new sorted sublists until there is only 1 sublist remaining.
Now given the initial sequence of integers, together with a sequence which is a result of several iterations of some sorting method, can you tell which sorting method we are using?
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<=100). Then in the next line, N integers are given as the initial sequence. The last line contains the partially sorted sequence of the N numbers. It is assumed that the target sequence is always ascending. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print in the first line either "Insertion Sort" or "Merge Sort" to indicate the method used to obtain the partial result. Then run this method for one more iteration and output in the second line the resulting sequence. It is guaranteed that the answer is unique for each test case. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.
Sample Input 1:
10
3 1 2 8 7 5 9 4 6 0
1 2 3 7 8 5 9 4 6 0
Sample Output 1:
Insertion Sort
1 2 3 5 7 8 9 4 6 0
Sample Input 2:
10
3 1 2 8 7 5 9 4 0 6
1 3 2 8 5 7 4 9 0 6
Sample Output 2:
Merge Sort
1 2 3 8 4 5 7 9 0 6
#include<cstdio>
#include<iostream>
#include<algorithm>
using namespace std;
void merge(int num[], int low1, int high1, int low2, int high2){
int temp[];
int index = , i = low1, j = low2;
while(i <= high1 && j <= high2){
if(num[i] < num[j])
temp[index++] = num[i++];
else
temp[index++] = num[j++];
}
while(i <= high1)
temp[index++] = num[i++];
while(j <= high2)
temp[index++] = num[j++];
for(int k = ; k < index; k++)
num[low1 + k] = temp[k];
}
int comp(int num1[], int num2[], int len){
for(int i = ; i < len; i++){
if(num1[i] != num2[i])
return ;
}
return ;
}
void mergeSort(int num[], int num2[], int len){
int isSame = , show = ;
for(int step = ; step / <= len; step *= ){
for(int i = ; i < len; i += step){
int mid = i + step / - ;
merge(num, i, mid, mid + , min(i + step - , len - ));
}
isSame = comp(num, num2, len);
if(isSame == ){
show = ;
continue;
}
if(show == ){
printf("Merge Sort\n");
printf("%d", num[]);
for(int i = ; i < len; i++)
printf(" %d", num[i]);
return;
}
}
}
void inser(int num[], int num2[], int len){
int isSame = , show = ;
for(int i = ; i < len; i++){
int temp = num[i];
int j = i - ;
while(j >= && temp < num[j]){
num[j + ] = num[j];
j--;
}
num[j + ] = temp;
isSame = comp(num, num2, len);
if(isSame == ){
show = ;
continue;
}
if(show == ){
printf("Insertion Sort\n");
printf("%d", num[]);
for(int i = ; i < len; i++)
printf(" %d", num[i]);
return;
}
}
}
int main(){
int N, num1[], num1_[], num2[];
scanf("%d", &N);
for(int i = ; i < N; i++){
scanf("%d", &num1[i]);
num1_[i] = num1[i];
}
for(int i = ; i < N; i++){
scanf("%d", &num2[i]);
}
mergeSort(num1, num2, N);
inser(num1_, num2, N);
cin >> N;
return ;
}
总结:
1、归并排序, 合并函数:
void merge(int num[], int low1, int high1, int low2, int high2){
int temp[];
int index = , i = low1, j = low2;
while(i <= high1 && j <= high2){
if(num[i] < num[j])
temp[index++] = num[i++];
else
temp[index++] = num[j++];
}
while(i <= high1)
temp[index++] = num[i++];
while(j <= high2)
temp[index++] = num[j++];
for(int k = ; k < index; k++)
num[low1 + k] = temp[k];
}
非递归写法:
void mergeSort(int num[], int len){
for(int step = ; step <= len; step *= ){ //初始步长为2, 逐步变为4、8、16
for(int i = ; i < len; i += step){ //i + step为每个子区间的首部
int mid = i + step / - ;
merge(num, i, mid, mid + , min(i + step - , len - ));
}
}
}
2、插入排序:将a[0]至a[i]视作有序序列,将a[i + 1]插入a[0]至a[i]中,使之有序。
void inser(int num[], int len){
for(int i = ; i < len; i++){
int temp = num[i];
int j = i - ;
while(j >= && temp < num[j]){
num[j + ] = num[j];
j--;
}
num[j + ] = temp;
}
}
3、注意,排序用的num数组需要两个,归并排序之后num数组已经改变,不可再用于插入排序。
A1089. Insert or Merge的更多相关文章
- A1089 Insert or Merge (25 分)
一.技术总结 看到是一个two pointers问题,核心是要理解插入排序和归并排序的实现原理,然后判断最后实现 可以知道a数组和b数组怎么样判断是插入排序还是归并排序,因为插入排序是来一个排一个,所 ...
- PAT甲级——A1089 Insert or Merge
According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and gr ...
- PAT_A1089#Insert or Merge
Source: PAT A1089 Insert or Merge (25 分) Description: According to Wikipedia: Insertion sort iterate ...
- PTA Insert or Merge
According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and gr ...
- 60. Insert Interval && Merge Intervals
Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals ( ...
- 【题解】【区间】【二分查找】【Leetcode】Insert Interval & Merge Intervals
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessa ...
- PAT甲级1089. Insert or Merge
PAT甲级1089. Insert or Merge 题意: 根据维基百科: 插入排序迭代,消耗一个输入元素每次重复,并增加排序的输出列表.每次迭代,插入排序从输入数据中删除一个元素,在排序列表中找到 ...
- PAT 1089 Insert or Merge[难]
1089 Insert or Merge (25 分) According to Wikipedia: Insertion sort iterates, consuming one input ele ...
- PAT1089. Insert or Merge
PAT1089. Insert or Merge 题目大意 给定一个初始序列src, 一个排序当中的序列tar, 问排序方式是 Insert Sort, 或者 Merge Sort. 并输出下一次迭代 ...
随机推荐
- [UWP 自定义控件]了解模板化控件(4):TemplatePart
1. TemplatePart TemplatePart(部件)是指ControlTemplate中的命名元素.控件逻辑预期这些部分存在于ControlTemplate中,并且使用protected ...
- LVM : 快照
LVM 机制还提供了对 LV 做快照的功能,也就是说可以给文件系统做一个备份,这也是设计 LVM 快照的主要目的.LVM 的快照功能采用写时复制技术(Copy-On-Write,COW),这比传统的备 ...
- 分布式监控系统Zabbix3.4-针对MongoDB性能监控操作笔记
公司在IDC机房的一台服务器上部署了MongoDB,由于所存储的业务数据比较重要,所以对MongoDB的监控显得尤为重要!Zabbix监控MongoDB性能的原理:通过echo "db.se ...
- http 概念
什么是回调? 什么是同步/异步? 什么是I/O? 什么是单线/多线程? 什么是阻塞/非阻塞? 什么是事件? 什么是事件驱动? 什么是基于事件驱动的回调? 什么是事件循环?
- hashContext
java.lnag.Object中对hashCode的约定: 1. 在一个应用程序执行期间,如果一个对象的equals方法做比较所用到的信息没有被修改的话,则对该对象调用hashCode方法多次,它必 ...
- 《linux内核设计与实现》第三章
1.进程 进程就是正在执行的程序代码的实时结果,不仅包含可执行代码,还包括其他资源,比如:打开的文件,挂起的信号,内核内部数据结构,处理器状态,一个或多个具有内存映射的内存地址空间及一个或多个执行线程 ...
- 《Linux及安全》课程实践二
编译生成新内核 一.实践原理 Linux模块是一些可以作为独立程序来编译的函数和数据类型的集合.之所以提供模块机制,是因为Linux本身是一个单内核.单内核由于所有内容都集成在一起,效率很高,但可扩展 ...
- github个人心得和链接
github使用心得: 在本次github使用过程中,我总结了git常用命令,都有哪些功能? git常用命令: git config :配置git git add:更新working director ...
- 在-for 循环里面如何利用ref 操作dom
由于dom 元素是在渲染之后才能操作,所以如果想取到dom元素,要放到mounted()这个生命周期函数里面,并且还要用this.$nextTick(function () {})
- NullPointerException-----开发中遇到的空指针异常
1.使用CollectionUtils.isEmpty判断空集合 public class TestIsEmpty { static class Person{} static class Girl ...