Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

贪心策略:两端设置围栏,无论如何注水,水只要不超过其中较短的那一根围栏即可,中间的柱子可以忽略。

相继缩短距离,较短一端的柱子换成向里的一根。

例如: height[left] <= height[right] :  left = left+1;

        反之, right = right-1;

 class Solution {
public:
int maxArea(vector<int> &height) {
int ans=,left=,right=height.size()-,contain;
while(left<right)
{
contain = (right-left)*min(height[right],height[left]);
ans = max(contain, ans);
height[left]<=height[right]?left++:right--;
}
return ans;
}
};

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