how convert large HEX string to binary

I have a string with 14 characters . This is a hex represantation of 7bytes. I want to convert it to binary.

int32_t Hex2Bin( uint8_t * pHexString, uint8_t * pBinArray )
{
int o = ;
int i = ; while ( pHexString[ i ] != 0x00 )
{
switch ( pHexString[ i ] )
{
case '':
pBinArray[ o ] = 0x00;
break;
case '':
pBinArray[ o ] = 0x10;
break;
case '':
pBinArray[ o ] = 0x20;
break;
case '':
pBinArray[ o ] = 0x30;
break;
case '':
pBinArray[ o ] = 0x40;
break;
case '':
pBinArray[ o ] = 0x50;
break;
case '':
pBinArray[ o ] = 0x60;
break;
case '':
pBinArray[ o ] = 0x70;
break;
case '':
pBinArray[ o ] = 0x80;
break;
case '':
pBinArray[ o ] = 0x90;
break;
case 'A':
case 'a':
pBinArray[ o ] = 0xa0;
break;
case 'B':
case 'b':
pBinArray[ o ] = 0xb0;
break;
case 'C':
case 'c':
pBinArray[ o ] = 0xc0;
break;
case 'D':
case 'd':
pBinArray[ o ] = 0xd0;
break;
case 'E':
case 'e':
pBinArray[ o ] = 0xe0;
break;
case 'F':
case 'f':
pBinArray[ o ] = 0xf0;
break;
default:
return -;
} if ( pHexString[ i + ] == 0x00 )
return -; switch ( pHexString[ i + ] )
{
case '':
pBinArray[ o ] |= 0x00;
break;
case '':
pBinArray[ o ] |= 0x01;
break;
case '':
pBinArray[ o ] |= 0x02;
break;
case '':
pBinArray[ o ] |= 0x03;
break;
case '':
pBinArray[ o ] |= 0x04;
break;
case '':
pBinArray[ o ] |= 0x05;
break;
case '':
pBinArray[ o ] |= 0x06;
break;
case '':
pBinArray[ o ] |= 0x07;
break;
case '':
pBinArray[ o ] |= 0x08;
break;
case '':
pBinArray[ o ] |= 0x09;
break;
case 'A':
case 'a':
pBinArray[ o ] |= 0x0a;
break;
case 'B':
case 'b':
pBinArray[ o ] |= 0x0b;
break;
case 'C':
case 'c':
pBinArray[ o ] |= 0x0c;
break;
case 'D':
case 'd':
pBinArray[ o ] |= 0x0d;
break;
case 'E':
case 'e':
pBinArray[ o ] |= 0x0e;
break;
case 'F':
case 'f':
pBinArray[ o ] |= 0x0f;
break;
default:
return -;
} i += ;
o++;
} return o;
}

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