贪心。。

#include<iostream>
#include<string.h>
#include<math.h>
#include <stdio.h>
#include <algorithm> using namespace std; struct node
{
int s,t;
int m;
}; node a[]; int cmp(node a,node b)
{
return a.m<b.m;
} int main()
{
int n;
int i,j;
int now;
while(scanf("%d",&n)!=EOF)
{
if(n==)
break;
for(i=;i<n;i++)
{
scanf("%d%d",&a[i].s,&a[i].t);
if((a[i].t-a[i].s)%==)
a[i].m=a[i].s+(a[i].t-a[i].s)/-;
else
a[i].m=a[i].s+(a[i].t-a[i].s)/;
}
sort(a,a+n,cmp);
now=;
int flag=;
int cnt=;
for(i=;i<n;i++)
{
if(now>a[i].m)
{
flag=;
break;
}
else if(now<=a[i].s)
now=a[i].s+(a[i].t-a[i].s)/+;
else if(now>a[i].s)
now=now+(a[i].t-a[i].s)/+;
cnt++;
} if(flag)
printf("NO\n");
else
{
if(cnt==n)
printf("YES\n");
else
printf("NO\n");
}
}
return ;
}

HDU 2491 Priest John's Busiest Day的更多相关文章

  1. HDU 2491 Priest John's Busiest Day(贪心)(2008 Asia Regional Beijing)

    Description John is the only priest in his town. October 26th is the John's busiest day in a year be ...

  2. 图论(2-sat):Priest John's Busiest Day

    Priest John's Busiest Day   Description John is the only priest in his town. September 1st is the Jo ...

  3. POJ 3683 Priest John's Busiest Day / OpenJ_Bailian 3788 Priest John's Busiest Day(2-sat问题)

    POJ 3683 Priest John's Busiest Day / OpenJ_Bailian 3788 Priest John's Busiest Day(2-sat问题) Descripti ...

  4. 【POJ3683】Priest John's Busiest Day

    题目 John is the only priest in his town. September 1st is the John's busiest day in a year because th ...

  5. poj 3686 Priest John's Busiest Day

    http://poj.org/problem?id=3683 2-sat 问题判定,输出一组可行解 http://www.cnblogs.com/TheRoadToTheGold/p/8436948. ...

  6. POJ 3683 Priest John's Busiest Day (2-SAT)

    Priest John's Busiest Day Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6900   Accept ...

  7. POJ 3683 Priest John's Busiest Day(2-SAT+方案输出)

    Priest John's Busiest Day Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 10010   Accep ...

  8. Priest John's Busiest Day(POJ 3683)

    原题如下: Priest John's Busiest Day Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 12162   ...

  9. POJ 3683 Priest John's Busiest Day(2-SAT 并输出解)

    Description John is the only priest in his town. September 1st is the John's busiest day in a year b ...

随机推荐

  1. 公司mysql数据库设计与优化培训ppt

    cnblogs无法上传附件. http://pan.baidu.com/s/1kVGqMn9

  2. Eclipse 出现Some sites could not be found. See the error log for more detail.错误 解决方法

    Eclipse 出现Some sites could not be found.  See the error log for more detail.错误 解决方法 Some sites could ...

  3. swift学习笔记之-构造过程

    //构造过程 import UIKit /* 构造过程(Initialization): 1.构造过程是使用类.结构体或枚举类型的一个实例的准备过程.在新实例可用前必须执行这个过程,具体操作包括设置实 ...

  4. swift学习笔记之-继承

    //继承 import UIKit /* 继承(Inheritance): 1.一个类可以继承(inherit)另一个类的方法(methods).属性(properties)和其它特性.当一个类继承其 ...

  5. jquery操作radio单选按钮、checked复选框。

    一.radio 取值: $('input[name=radio]:checked').val(); 二.checked 判断checked是否被选中 $("input[type='check ...

  6. AT NEW F、AT END OF F注意事项

    1.F只能是内表的第一个字段 2.AT NEW F.AT END OF F使用F之后内表内容会变为* 解决出现*的办法: FIELD-SYMBOLS:<ITAB> LIKE  ITAB L ...

  7. IOS数组NSArray与NSMutableArray知识点

    此文是对数组NSArray与NSMutableArray知识点的总结,主要是一些常见的操作,别外一些操作见其相应的文档,下面的代码部分还运用的第三方插件BlocksKit相结合: a:Foundati ...

  8. 异步post请求之代理方法

    #import "ViewController.h" #import "Header.h" @interface ViewController ()<NS ...

  9. CollectionView 简用

    创建一个CollectionView 分为几个步骤 1.先创建布局FlowLayout 设置布局格式 2.创建CollectionView 并使用布局Flowlayout  -initWithFram ...

  10. iOS 学习 - 1.代理传值

    代理的目的是改变或传递控制链.允许一个类在某些特定时刻通知到其他类,而不需要获取到那些类的指针.可以减少框架复杂度.
另外一点,代理可以理解为java中的回调监听机制的一种类似 优点:1.避免子类化带 ...