ZOJ2477 Magic Cube

题目：

This is a very popular game for children. In this game, there's a cube, which consists of 3 * 3 * 3 small cubes. We can unwrap the cube, it will become like this:

      w w w
      w w w
      w w w
r r r g g g b b b o o o
r r r g g g b b b o o o
r r r g g g b b b o o o
      y y y
      y y y
      y y y

The letters means the color on the small cubes. For example, 'r' means red, 'g' means green, 'y' means yellow....The goal for this game is to rotate the faces of the cube to make each of the faces contains only one color. Note there're exact 6 kind of colors on the cube and there're exact 9 small rectangles totally in any time in the game.

Do you know how to rotate the faces? I think most of you have known it. But I would like to show it again. When a face is rotated, the configuration of colors in all the adjacent faces changes. For the cube above, after we rotate the green face clock-wise, the last line of 'w' face will become the left column of 'b' face, the left column of 'b' face will become the top line of 'y' face, etc. As you may know, reaching the final position from a scrambled configuration can be quite challenging.

In this problem, you are given a configuration of the cube, and asked to give a way to reach the final position. To reduce the difficulty, the steps required will never be greater than 5.

输入：

The input contains an integer in the first line, which indicates the number of the test cases. In each test case, there're exact 10 lines. The first line is an empty line. The next 9 lines contain a configuration. The format can be seen in the sample input. For simplicity, we give an index to each face as follows:

    /---\
    |   |
    | 4 |
    |   |
/---+---+---+---\
|   |   |   |   |
| 0 | 1 | 2 | 3 |
|   |   |   |   |
\---+---+---+---/
    |   |
    | 5 |
    |   |
    \---/

Note that there's a space between two adjacent letters.

输出：

For each test case, the first line of the output is the smallest count N of the steps to reach the winning position. If the winning position can't be reached in 5 steps, print -1 in this line. Otherwise print each step in one line in the following N lines. A step contains two integers, the first one means the face index, and the second one means the direction. 1 means clock-wise and -1 means counter clock-wise. If the given position is the winning position, print 0 for such test case simply. If there're multiple solutions, any one is acceptable.

样例：

分析：我。。。自闭了两天竟然是没有写>5输出-1(°ཀ°)，为什么我会默认测试点必然可以在5步内实现啊(#`Д´)ﾉ

只能说这个模拟太恶心了！！！

用IDA*优化，思路是计算每一个面有几个和中心方格颜色不一样的方格，6个面的总数除12并向上取整是最少剩余需要的步数（如果最理想的情况加上已走步数仍然大于5那肯定没戏啊）

模拟写得相当丑(灬ºωº灬)

 #include<iostream>

 #include<sstream>

 #include<cstdio>

 #include<cstdlib>

 #include<string>

 #include<cstring>

 #include<algorithm>

 #include<functional>

 #include<iomanip>

 #include<numeric>

 #include<cmath>

 #include<queue>

 #include<vector>

 #include<set>

 #include<cctype>

 #define PI acos(-1.0)

 const int INF = 0x3f3f3f3f;

 const int NINF = -INF - ;

 typedef long long ll;

 using namespace std;

 char cube[][];

 struct node

 {

     char maze[][];

 };

 struct cur

 {

     char maze[][];

 };

 node clockwise(node temp)

 {

     char gtm[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     memcpy(temp.maze, gtm, sizeof(temp.maze));

     return temp;

 }

 node cclockwise(node temp)

 {

     char gtm[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     gtm[][] = temp.maze[][];

     memcpy(temp.maze, gtm, sizeof(temp.maze));

     return temp;

 }

 int bol, ans;

 pair<int, int> P[];

 void print()

 {

     for (int i = ; i < ans; ++i)

         cout << P[i].first << ' ' << P[i].second << endl;

 }

 int hx(cur trans)

 {

     double sum = ;

     for (int i = ; i < ; ++i)

     {

         for (int j = ; j < ; j += )

             if (trans.maze[i][j] != trans.maze[][]) sum++;

     }

     for (int i = ; i < ; ++i)

     {

         for (int j = ; j < ; j += )

             if (trans.maze[i][j] != trans.maze[][]) sum++;

     }

     for (int i = ; i < ; ++i)

     {

         for (int j = ; j < ; j += )

             if (trans.maze[i][j] != trans.maze[][]) sum++;

     }

     for (int i = ; i < ; ++i)

     {

         for (int j = ; j < ; j += )

             if (trans.maze[i][j] != trans.maze[][]) sum++;

     }

     for (int i = ; i < ; ++i)

     {

         for (int j = ; j < ; j += )

             if (trans.maze[i][j] != trans.maze[][]) sum++;

     }

     for (int i = ; i < ; ++i)

     {

         for (int j = ; j < ; j += )

             if (trans.maze[i][j] != trans.maze[][]) sum++;

     }

     return ceil(sum / );

 }

 void dfs(int rec, char pos[][], int deep)

 {

     if (rec > deep) return;

     cur trans;

     memcpy(trans.maze, pos, sizeof(trans.maze));

     int h = hx(trans);

     //cout << "test:" << h << endl;

     if (h == )

     {

         ans = rec;

         cout << rec << endl;

         bol = ;

         return;

     }

     if (h + rec > deep) return;

     for (int i = ; i < ; ++i)

     {

         char tmp[][];

         memcpy(tmp, pos, sizeof(tmp));

         /*for (int j = 0; j < 9; ++j)

             cout << tmp[j] << endl;

         return;*/

         node temp;

         if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = clockwise(temp);

             /*for (int m = 0; m < 3; ++m)

             {

                 for (int n = 0; n < 3; ++n)

                     cout << temp.maze[m][n] << ' ';

                 cout << endl;

             }*/

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = cclockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = clockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = cclockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = clockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = cclockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = clockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = cclockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = clockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = cclockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = clockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         else if (i == )

         {

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     temp.maze[m][n] = tmp[k][j];

             }

             temp = cclockwise(temp);

             for (int k = , m = ; k < , m < ; ++k, ++m)

             {

                 for (int j = , n = ; j < , n < ; j += , ++n)

                     tmp[k][j] = temp.maze[m][n];

             }

             char cpy[][];

             memcpy(cpy, tmp, sizeof(cpy));

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             cpy[][] = tmp[][];

             memcpy(tmp, cpy, sizeof(tmp));

             /*for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

             return;*/

         }

         /*if (i == 1 && deep == 2)

         {

             cout << "first" << endl;

             for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

         }

         if (i == 2 && deep == 2)

         {

             cout << "second" << endl;

             for (int k = 0; k < 9; ++k)

                 cout << tmp[k] << endl;

         }*/

         dfs(rec + , tmp, deep);

         //if (i == 1) return;

         if (bol)

         {

             P[rec].first = i / ;

             if (i %  == ) P[rec].second = ;

             else P[rec].second = -;

             return;

         }

     }

 }

 int main()

 {

     int T;

     cin >> T;

     while (T--)

     {

         string nul;

         getline(cin, nul);

         for (int i = ; i < ; ++i)

         {

             char ss;

             int num = ;

             while ((ss = getchar()) != '\n')

             {

                 if (ss != ' ') cube[i][num++] = ss;

                 else cube[i][num++] = ' ';

             }

             cube[i][num] = '\0';

         }

         /*for (int i = 0; i < 9; ++i)

             cout << cube[i] << endl;*/

         /*for (int i = 0; i < 3; ++i)

         {

             for (int j = 6; j < 11; j += 2)

             {

                 cout << cube[i][j] << ' ';

             }

             cout << endl;

         }*/

         /*cur gat;

         memcpy(gat.maze, cube, sizeof(gat.maze));

         int p = judge(gat);

         cout << p << endl;*/

         bol = , ans = ;

         for (int i = ; i <= ; ++i)

         {

             //cout << "deep:" <<  i << endl;

             dfs(, cube, i);

             if (bol)

             {

                 print();

                 break;

             }

         }

         if (!bol) cout << - << endl;

     }

     return ;

 }

ZOJ2477 Magic Cube的更多相关文章

ZOJ 2477 Magic Cube（魔方）
ZOJ 2477 Magic Cube(魔方) Time Limit: 2 Seconds Memory Limit: 65536 KB This is a very popular gam ...
ZOJ 2477 Magic Cube 暴力,模拟难度:0
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1477 用IDA*可能更好,但是既然时间宽裕数据简单,而且记录状态很麻烦,就直接 ...
magic cube
搜索题, 每个状态能扩展出12种状态,最多进行5次旋转12^5 要用到iddfs,或者我看到网上其他人用的ida* 我也是参考了别人的代码,而且这个题vj上有点问题,我看数据看了半天,愣是没看明白第二 ...
2019杭电多校二 F. Fantastic Magic Cube (FWT)
大意: 给定$N^3$立方体, 每个单位立方体权值为三个坐标异或, 每次沿坐标轴切一刀, 得分为两半内权值和的乘积, 求切成$n^3$块的最大得分. 可以发现得分与切法无关, 假设每个点权值为$a_i ...
sdutoj 2606 Rubik’s cube
http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=2606 Rubik’s cube Time Li ...
USACO 3.2 Magic Squares
Magic SquaresIOI'96 Following the success of the magic cube, Mr. Rubik invented its planar version, ...
用DirectX实现魔方（一）
关于魔方魔方英文名字叫做Rubik's Cube,是由匈牙利建筑学教授和雕塑家Ernő Rubik于1974年发明,最初叫做Magic Cube(这大概也是中文名字的来历吧),1980年Ideal ...
一位学长的ACM总结（感触颇深）
发信人: fennec (fennec), 信区: Algorithm 标题: acm 总结 by fennec 发信站: 吉林大学牡丹园站 (Wed Dec 8 16:27:55 2004) AC ...
ZOJ - 2477 dfs [kuangbin带你飞]专题二
注意输入的处理,旋转操作打表.递增枚举可能步数,作为限制方便找到最短路. AC代码:90ms #include<cstdio> #include<cstring> char m ...

随机推荐

pycharm执行代码可以跑，但放到linux跑就报文件找不到
代码中包含当前路径使用pycharm执行python,当前路径就是pycharm项目所在的路径,所以不会报错但使用shell执行python,当前路径就会从shell所在的路径去找文件,所以找不到 ...
【HTTP/S】透明代理、匿名代理、混淆代理、高匿代理有什么区别？
这4种代理,主要是在代理服务器端的配置不同,导致其向目标地址发送请求时,REMOTE_ADDR, HTTP_VIA,HTTP_X_FORWARDED_FOR三个变量不同. 1.透明代理(Transpa ...
redis中关于使用string类型还是hash类型
前篇:最近在做一个将redis中大数据量进行合并缩减优化的工作,其中一项按月将数据进行合并.将一个月的数据放入一个key-value键值对中. 例:p2d20180901-3.p2d20180902- ...
Maven pom 配置简介
1. groupId artifactId version 2. dependencies 3. plugins http://shmilyaw-hotmail-com.iteye.com/blog/ ...
在Docker上构建mysql容器
1.查看docker上的镜像是否有 mysql,如果没有下载则列表中没有 [root@holly holly]# docker images; 如果没有只会看到如下结构 REPOSITORY TA ...
hdu2013 蟠桃记【C++】
蟠桃记 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submiss ...
使用git bash向github远程仓库提交代码
1.登录github,创建仓库. 2.切换到要提交的文件目录下. 3.打开git bash 3.1.初始化仓库 git init 3.2.将本地仓库与远程仓库关联 git remote add ori ...
swift2.0学习之拓展
拓展:和oc的拓展方法功能差点儿相同.就是给已经存在的类,结构体.枚举,协议类型添加新的方法拓展语法: 用extensionkeyword声明: extension SomeType { // ne ...
飘逸的python - 实现一个极简的优先队列
一个队列至少满足2个方法,put和get. 借助最小堆来实现. 这里按"值越大优先级越高"的顺序. #coding=utf-8 from heapq import heappush ...
改动mysqlpassword
1.假设没有password,则 mysql -u root mysql> SET PASSWORD FOR 'root'@'localhost' = PASSWORD('newpass'); ...

ZOJ2477 Magic Cube

ZOJ2477 Magic Cube的更多相关文章

随机推荐

热门专题