使用Python通过SMTP发送邮件

有些业务可能由于各种各样的原因并不适用于Zabbix监控，这时如果要做到系统出问题能立即发送邮件，就需要自己来写监控脚本了，出问题要实时通过邮件报警，以下案例使用Python脚本实现通过SMTP协议发送邮件，一般可用于自定义报警

Python代码

方案一

#!/usr/bin/python
#-*- coding: UTF-8 -*-
import sys,os,string,time,datetime,re
from sys import stdout
import poplib
import smtplib
from email.header import decode_header
from email.mime.text import MIMEText
import email

def send_mail(sender, receiver,strsubject,strcontent):
        _user = "xxx@163.com"
        _pwd  = "xxx"
        sent =smtplib.SMTP_SSL('smtp.163.com',465)
        sent.login(_user, _pwd)
        to = receiver.split(";")
        content=MIMEText(strcontent,'html',_charset='UTF-8')
        content['Subject']=strsubject
        content['From']=sender
        content['To']=','.join(to)
        sent.sendmail('xxx@163.com',to,content.as_string())
        sent.close()

## main ##
if __name__=='__main__':
## get the path in the config file
        if len(sys.argv) != 4:
                print "sender,receiver,subject"
                sys.exit(1)
        sender=sys.argv[1]
        receiver=sys.argv[2]
        subject=sys.argv[3]
        content =sys.stdin.read()
        send_mail(sender, receiver, subject, content);

方案二

#!/usr/bin/python
#coding:utf-8
import smtplib
from email.mime.text import MIMEText
from sys import argv

mailto_list=[]
mail_host="smtp.163.com:25"  #设置服务器
mail_user="xxx@163.com"     #发件用户名(换成自己的)
mail_pass="xxx"   #口令（换成自己的）
#mail_postfix="163.com"  #发件箱的后缀
debug_level=0       #是否开启debug

def send_mail(to_list,sub,content):
    me=mail_user
    msg = MIMEText(content,_subtype='plain',_charset='utf-8')
    msg['Subject'] = sub
    msg['From'] = me
    msg['To'] = ";".join(to_list)
    try:
        server = smtplib.SMTP()
        server.set_debuglevel(debug_level)
        server.connect(mail_host)
        server.login(mail_user,mail_pass)
        server.sendmail(me, to_list, msg.as_string())
        server.close()
        return True
    except Exception as e:
        print('except:',e)
        return False
if __name__ == '__main__':
    try:
        mailto_list=argv[1].split(';')
        sub=argv[2]
        content=argv[3]
    except:
        print("python send_mail.py 'user1@xx.com;user2@xx.com' sub content")
        exit()

    if send_mail(mailto_list,sub,content):
        print("发送成功")
    else:
        print("发送失败")