ZOJ 2476 Total Amount

题目链接：http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2476

Time Limit: 2 Seconds                                    Memory Limit: 65536 KB

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Given a list of monetary amounts in a standard format, please calculate the   total amount.

We define the format as follows:

1. The amount starts with '$'.

2. The amount could have a leading '0' if and only if it is less then 1.

3. The amount ends with a decimal point and exactly 2 following digits.

4. The digits to the left of the decimal point are separated into groups of   three by commas (a group of one or two digits may appear on the left).

Input

The input consists of multiple tests. The first line of each test contains   an integer N (1 <= N <= 10000) which indicates the number of amounts.   The next N lines contain N amounts. All amounts and the total amount are between   $0.00 and $20,000,000.00, inclusive. N=0 denotes the end of input.

Output

For each input test, output the total amount.

Sample Input

2
  $1,234,567.89
  $9,876,543.21
  3
  $0.01
  $0.10
  $1.00
  0

Sample Output

$11,111,111.10
  $1.11

 #include<stdio.h>
 #include<cstring>.
 #include<iostream>
 using namespace std;
 long long f(int n)
 {
     long long res=;
     while(n--)
         res*=;
     return res;
 }
 char ans[];
 void change(long long a)
 {
     int i,j;
     if(a==)
     {
         cout<<"";
         return;
     }
     for(i=,j=;i<;i++,j++)
     {
         if(a<)break;
         ans[i]=''+(a%);
         a/=;
         if(j%==)
         {
             i++;
             ans[i]=',';
         }
     }
     int len=i;
     for(i=len-;i>=;i--)
     {
         if(i==len-&&ans[i]==',');
         else cout<<ans[i];
     }
 }
 int main()
 {
     int n,len,i,j;
     long long resz;
     int resf;
     char s[];
     while(cin>>n&&n)
     {
         resz=;
         resf=;
         while(n--)
         {
             cin>>s;
             len=strlen(s);
             resf+=s[len-]-'';
             resf+=(s[len-]-'')*;
             while(resf>=)
             {
                 resz+=;
                 resf-=;
             }
             for(i=len-,j=;i>=;i--)
             {
                 if(s[i]>=''&&s[i]<='')
                 {
                     resz+=(s[i]-'')*f(j);
                     j++;
                 }
             }
         }
         cout<<"$";
         change(resz);
         cout<<".";
         if(resf<)cout<<""<<resf<<endl;
         else cout<<resf<<endl;
     }
     return ;
 }