HackerRank "Bike Racer"
Just for study from its editorial~
Lesson learnt: an optimized Hungarian Algorithm: Hopcroft-Karp Algorithm (a batched version of Hungarian)
A very good article on it (in Chinese): https://www.renfei.org/blog/bipartite-matching.html
The basic idea of Hungarian is: find all augment pathes and flip (matched\unmatched toggled) them, recursively.
And Hopcroft-Karp is a batched version of Hungarian: we simply check all edges at each node.
#include <cmath>
#include <cstdio>
#include <vector>
#include <queue>
#include <iostream>
#include <algorithm>
#include <unordered_map>
#include <unordered_set>
using namespace std; #define MAX 2001 typedef long long LL; int N, M, K;
vector<int> edges[MAX]; // edges of left side
vector<bool> visited(MAX);
vector<int> Left(MAX), Right(MAX);
vector<vector<LL>> dist(MAX, vector<LL>(MAX)); /*
* Hopcroft-Karp Algorithm: optimized(batched) Hungarian Algorithm
* Complexity: E*sqrt(V)
*/ // True: augment path flipped
// False:augment path stay the same
//
bool dfs(int u)
{
if(visited[u]) return false; visited[u] = true; // Flip input u-v pairs
for(auto v : edges[u])
{
if(Right[v] == -) // u-v not matched
{
// then match u-v
Right[v] = u, Left[u] = v;
return true;
}
} // Given all input u-v are matched then match deeper pathes
for(auto v : edges[u])
{
if(dfs(Right[v])) // flipped deeper?
{
// then flip current edge too
Right[v] = u, Left[u] = v;
return true;
}
}
return false;
} int match()
{
// Cleanup work
Left.assign(MAX, -);
Right.assign(MAX, -); int i, ret = ;
bool done = true;
do
{
done = true; // for the new aug. path
visited.assign(MAX, ); for(int i = ; i <= N; i ++)
if(Left[i] == - && dfs(i))
done = false; // augment-able? again.. }while(!done); // Count no. of matched edges
for(int i = ; i <= N; i ++)
ret += Left[i] != -;
return ret;
}
/**********************************************/ bool check(LL val)
{
// Pick reasonable edges
for( int i= ; i<=N ; i++)
for( int j= ; j<=M ; j++)
if(dist[i][j] <= val)
edges[i].push_back(j); // Run Hopcroft-Karp
LL num_match = match(); // Clean for the next check
for(int i= ; i<= N ; i++)
edges[i].clear(); return num_match >= K;
} int main()
{
cin >> N >> M >> K; // Get input array
vector<pair<LL, LL>> P(N + ), Q(M + );
for(int i = ; i <= N; i ++)
cin >> P[i].first >> P[i].second;
for(int i = ; i <= M; i ++)
cin >> Q[i].first >> Q[i].second; // Calculate distances
for(int i= ; i<=N ; i++)
for(int j= ; j<=M ; j++)
{
LL a = P[i].first - Q[j].first;
LL b = P[i].second - Q[j].second;
dist[i][j] = a * a + b * b;
} // Binay Search the min matching result for K
LL low = , high = ;
while(low < high)
{
LL mid = (low + high) >> ;
if(check(mid)) high = mid;
else low = mid + ;
}
cout << low << endl;
return ;
}
HackerRank "Bike Racer"的更多相关文章
- Hackerrank 2020 February 2014 解题报告
Hackerrank 2020 February 2014 解题报告 比赛链接 Sherlock and Watson (20分) 题意:给定一个数组,向右平移K次,然后有Q个询问,问第x位置上是几 ...
- Rust初步(三):使用atom搭配racer进行rust编程
在rust.cc社区中有一个关于rust编辑器的讨论(话说很多人要学一个新语言,都会立即考虑编辑器的问题,包括我在内),主要关注的是,智能提示(这个真的太重要了).大家讨论下来有几个选择 1. ecl ...
- UVALive 6908---Electric Bike(DP或记录型深搜)
题目链接 https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_ ...
- 日常小测:颜色 && Hackerrank Unique_colors
题目传送门:https://www.hackerrank.com/challenges/unique-colors 感谢hzq大神找来的这道题. 考虑点分治(毕竟是路经统计),对于每一个颜色,它的贡献 ...
- HackerRank "Square Subsequences" !!!
Firt thought: an variation to LCS problem - but this one has many tricky detail. I learnt the soluti ...
- HackerRank "Minimum Penalty Path"
It is about how to choose btw. BFS and DFS. My init thought was to DFS - TLE\MLE. And its editorial ...
- HackerRank "TBS Problem" ~ NPC
It is marked as a NPC problem. However from the #1 code submission (https://www.hackerrank.com/Charl ...
- HackerRank Extra long factorials
传送门 今天在HackerRank上翻到一道高精度题,于是乎就写了个高精度的模板,说是模板其实就只有乘法而已. Extra long factorials Authored by vatsalchan ...
- HackerRank "Lucky Numbers"
Great learning for me:https://www.hackerrank.com/rest/contests/master/challenges/lucky-numbers/hacke ...
随机推荐
- JVM监控命令详解(转)
JVM监控命令基本就是 jps.jstack.jmap.jhat.jstat 几个命令的使用就可以了 JDK本身提供了很多方便的JVM性能调优监控工具,除了集成式的VisualVM和jConsole外 ...
- ucsc工具集合
wget http://hgdownload.cse.ucsc.edu/admin/jksrc.zip 解压后所有工具在kent目录里 发现个更方便的.... http://hgdownload.cs ...
- python 函数性能分析
1 使用profile分析函数性能示例1, 以profile为例: import profile def profileTest(): Total =1; for i in range(10): To ...
- 几个有用的SAP安全配置的用户参数配置列表
转自http://blog.sina.com.cn/s/blog_4f913cf80100mksj.html Parameter Brief Description login/min_passwor ...
- [JSP] c:forEach 输出序号 每行自动生成序号
关键在于<c:forEach>的varStatus属性,具体代码如下: <table width="500" border="0" cells ...
- 信頼済みサイト对window.open窗体大小影响原因之一
如果某站点被添加进去之后,这个站点窗体限制被决定了,window.open里面,status bar 无效的设置不再起作用.而且,如果原来status bar被 任务栏挡住的话,这个时候它就会被显示出 ...
- leetcode 147. Insertion Sort List ----- java
Sort a linked list using insertion sort. 插入排序. /** * Definition for singly-linked list. * public cla ...
- JavaWeb学习记录(六)——用户登录功能之Session与验证码验证功能的实现
一.产生验证码的工具类 package blank.util; import java.awt.Color;import java.awt.Graphics;import java.awt.image ...
- php支付接口,代付、感悟
支付接口: 1.验证用户登录信息 2.验证参数.用加密串来匹配,开信息是否被篡改 3.如果有必要可以仿造购物城 建立购物车列表 4.建立和请求方的关联表 5.进行订单生成.支付流程.各种判断.验证. ...
- Android——ListView
1.ArryAdapter: arry_adapter的layout文件: <?xml version="1.0" encoding="utf-8"?&g ...