题目链接

King's Cake

Time Limit: 2000/1000 MS (Java/Others)    

Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 79    Accepted Submission(s): 69

Problem Description
It is the king's birthday before the military parade . The ministers prepared a rectangle cake of size n×m(1≤n,m≤10000) . The king plans to cut the cake himself. But he has a strange habit of cutting cakes. Each time, he will cut the rectangle cake into two pieces, one of which should be a square cake.. Since he loves squares , he will cut the biggest square cake. He will continue to do that until all the pieces are square. Now can you tell him how many pieces he can get when he finishes.
 
Input
The first line contains a number T(T≤1000), the number of the testcases.

For each testcase, the first line and the only line contains two positive numbers n,m(1≤n,m≤10000).

 
Output
For each testcase, print a single number as the answer.
 
Sample Input
2
2 3
2 5
 
Sample Output
3
4
AC代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
int n,m;
scanf("%d%d",&n,&m);
int ans=,mmin,mmax;
while(n&&m)
{
if(n>m)
{
n-=m;
}
else
{
m-=n;
}
ans++;
}
cout<<ans<<"\n"; }
return ;
}

hdu-5640 King's Cake (水题)的更多相关文章

  1. HDU 5640 King's Cake GCD

    King's Cake 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5640 Description It is the king's birthd ...

  2. HDU 5640 King's Cake

    King's Cake Problem Description It is the king's birthday before the military parade . The ministers ...

  3. hdu 5640 King's Cake(BestCoder Round #75)

    King's Cake Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total ...

  4. hdu 5640 King's Cake(模拟)

    Problem Description   It is the king's birthday before the military parade . The ministers prepared ...

  5. HDU 5640 King's Cake【模拟】

    题意: 给定长方形,每次从中切去一个最大的正方形,问最终可以得到多少正方形. 分析: 过程类似求gcd,每次减去最小的边即可. 代码: #include <cstdio> #include ...

  6. HDU 5578 Friendship of Frog 水题

    Friendship of Frog Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.ph ...

  7. HDU 5590 ZYB's Biology 水题

    ZYB's Biology Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid ...

  8. HDU 5538 L - House Building 水题

    L - House Building Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.ph ...

  9. Codeforces Round #343 (Div. 2) A. Far Relative’s Birthday Cake 水题

    A. Far Relative's Birthday Cake 题目连接: http://www.codeforces.com/contest/629/problem/A Description Do ...

随机推荐

  1. Linux守护进程简单介绍和实例具体解释

    Linux守护进程简单介绍和实例具体解释 简单介绍 守护进程(Daemon)是执行在后台的一种特殊进程.它独立于控制终端而且周期性地执行某种任务或等待处理某些发生的事件.守护进程是一种非常实用的进程. ...

  2. php编译参数选项 具体参数含义可以用./configure --help来查看

    php编译参数选项  PHP_INSTALL_PATH=/data/web/php MYSQL_INSTALL_PATH=/data/web/mysql ./configure --prefix=${ ...

  3. OGEngine教程:字体工具使用

    1.打开 BitmapFont tool,在红框中输入你要显示的字. 2.写完后保存字体文件 watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvT3Jhbmdl ...

  4. 反素数ant(数学题)

    1053: [HAOI2007]反素数ant Time Limit: 10 Sec  Memory Limit: 162 MBSubmit: 2872  Solved: 1639[Submit][St ...

  5. 成功扩展live555支持ipv6,同时支持RTSPServer & RTSPClient

    live555对ipv6的扩展 从live555的官网看live555的发展历史,实在是历史悠久,保守估计已经发展了至少16年以上了,同时,这也导致了live555在很多架构和考虑上面不能满足现代化的 ...

  6. But what exactly do we mean by "gets closer to"?

    https://rdipietro.github.io/friendly-intro-to-cross-entropy-loss/ [将输入转化为输出:概率分布] When we develop a ...

  7. HTML 与 SGML关系

    HTML :超文本标记语言,“超文本”就是指页面内可以包含图片.链接,甚至音乐.程序等非文字元素 SGML:标准通用标记语言 HTML 是SGML下的一个应用

  8. Effective Java 读书笔记(一):使用静态工厂方法代替构造器

    这是Effective Java第2章提出的第一条建议: 考虑用静态工厂方法代替构造器 此处的静态工厂方法并不是设计模式,主要指static修饰的静态方法,关于static的说明可以参考之前的博文&l ...

  9. [luogu3393]逃离僵尸岛

    [luogu3393]逃离僵尸岛 luogu 先把被禁止的点和新建的虚点n+1连0边 跑最短路,dis<=s的点价格为Q,否则为P, 再建图跑最短路 #define ll long long # ...

  10. 我的Android进阶之旅------>Android颜色值(RGB)所支持的四种常见形式

    Android中颜色值是通过红(Red).绿(Green).蓝(Blue)三原色,以及一个透明度(Alpha)值来表示的,颜色值总是以井号(#)开头,接下来就是Alpha-Red-Green-Blue ...