Time Limit: 2 Seconds      Memory Limit: 65536 KB

Over the years, the people of the great city of Pittsburgh have repeatedly demonstrated a collective expertise at football second to none. Recently a spy has discovered the true source of the city's football power-a wizard known only as "Myron," who is infallible at selecting the proper position at which each player will excel.

Now that you know the source of Pittsburgh's wisdom, you are determined to provide your school's football team with a computer program that matches the wisdom of "Myron." You have consulted with the best football minds you can find, and they have dispensed their wisdom on the slowest speed, minimum weight, and minimum strength required to play each position.

Position

Slow.Speed

Min.Weight

Min.Strength

Wide Receiver

4.5

150

200

Lineman

6.0

300

500

Quarterback

5.0

200

300

Using this knowledge, you will develop a program that reads in several players physical attributes and outputs what position(s) they are able to play.

 

Input

Each line of the input file will list the attributes for one player:

<speed> <weight> <strength>

Each number will be a real-valued number. The file will end with a line reading "0 0 0".

 

Output

For each player, you will output one line listing the positions that player can play. A player can play a position if each of their attributes is greater or equal to the minimum for weight and strength, and less than or equal to the slowest speed. If a player can play multiple positions, output them in the order listed above, separated by whitespace. You can not leave an extra space at the end of the line. If a player can play no positions, write "No positions" on the line.

 

Sample Input

4.4 180 200
5.5 350 700
4.4 205 350
5.2 210 500
0 0 0

 

Sample Output

Wide Receiver
Lineman
Wide Receiver Quarterback
No positions

Source: Mid-Atlantic USA 2004

 

#include<iostream>

#include<map>

#include<string>

 

using
namespace
std;

 

class
Position

{

private:

    string
name;

    double
lowestSpeed;

    double
minWeight;

    double
minStrength;

public:

    Position(){}

 

    string
GetName()

    {

        return
this->name;

    }

    Position(string
name,
double
lowestSpeed,
double
minWeight,
double
minStrength)

    {

        this->name=name;

        this->lowestSpeed
=
lowestSpeed;

        this->minWeight
=
minWeight;

        this->minStrength
=
minStrength;

    }

 

    bool
MathPosition(double
speed,
double
weight,
double
strength)

    {

        return
(weight
>=
this->minWeight
&&
strength
>=
this->minStrength
&&
speed
<=
this->lowestSpeed);

    }

};

int
main()

{

    Position
**p
=
new
Position*[3];

 

    *p
=
new
Position("Wide Receiver",
4.5,
150,
200);

    *(p+1)
=
new
Position("Lineman",
6.0,
300,
500);

    *(p+2)
=
new
Position("Quarterback",
5.0,
200,
300);

 

    double
s,
w,
str;

    while(cin>>s>>w>>str
&&
(s
!=
0
||
w
!=
0
||
str
!=
0))

    {

        int
matchCount
=
0;

        if((*p)->MathPosition(s,w,str)){

            cout<<(*p)->GetName();

            matchCount++;

        }

        if((*(p+1))->MathPosition(s,w,str)){

            if(matchCount
!=
0)

                cout<<" ";

            cout<<(*(p+1))->GetName();

            matchCount++;

        }

        if((*(p+2))->MathPosition(s,w,str)){

            if(matchCount
!=
0)

                cout<<" ";

            cout<<(*(p+2))->GetName();

            matchCount++;

        }

        if(matchCount
==
0)

            cout<<"No positions";

        cout<<endl;

    }

 

    

    delete[]
p;

    p
=
NULL;

 

    return
0;

}

ZOJ Problem Set – 2321 Filling Out the Team的更多相关文章

  1. ZOJ Problem Set - 1394 Polar Explorer

    这道题目还是简单的,但是自己WA了好几次,总结下: 1.对输入的总结,加上上次ZOJ Problem Set - 1334 Basically Speaking ac代码及总结这道题目的总结 题目要求 ...

  2. ZOJ Problem Set - 1025解题报告

    ZOJ Problem Set - 1025 题目分类:基础题 原题地址:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=10 ...

  3. ZOJ Problem Set - 3829Known Notation(贪心)

    ZOJ Problem Set - 3829Known Notation(贪心) 题目链接 题目大意:给你一个后缀表达式(仅仅有数字和符号),可是这个后缀表达式的空格不幸丢失,如今给你一个这种后缀表达 ...

  4. ZOJ Problem Set - 2563 Long Dominoes 【如压力dp】

    称号:ZOJ Problem Set - 2563 Long Dominoes 题意:给出1*3的小矩形.求覆盖m*n的矩阵的最多的不同的方法数? 分析:有一道题目是1 * 2的.比較火.链接:这里 ...

  5. ZOJ Problem Set - 3593 拓展欧几里得 数学

    ZOJ Problem Set - 3593 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3593 One Person ...

  6. ZOJ Problem Set - 2297 Survival 【状压dp】

    题目:ZOJ Problem Set - 2297 Survival 题意:给出一些怪,有两个值,打他花费的血和能够添加的血,然后有一个boss,必须把小怪全部都打死之后才干打boss,血量小于0会死 ...

  7. ZOJ Problem Set - 3820 Building Fire Stations 【树的直径 + 操作 】

    题目:problemId=5374" target="_blank">ZOJ Problem Set - 3820 Building Fire Stations 题 ...

  8. ZOJ Problem Set - 3229 Shoot the Bullet 【有上下界网络流+流量输出】

    题目:problemId=3442" target="_blank">ZOJ Problem Set - 3229 Shoot the Bullet 分类:有源有汇 ...

  9. ZOJ Problem Set - 3822Domination(DP)

    ZOJ Problem Set - 3822Domination(DP) problemCode=3822">题目链接 题目大意: 给你一个n * m的棋盘,每天都在棋盘上面放一颗棋子 ...

随机推荐

  1. word-wrap/word-break/white-space

    word-wrap语法: word-wrap : normal | break-word normal : 默认值,单词如果单词超长,会冲出边界(单个单词超长,在当前行显示) break-word : ...

  2. Java中的语法树结构

    1.JCTypeParameter class B<T extends CA&IA&IB> { ...} 截图如下: 接口继承了StatementTree接口,而实现类实现 ...

  3. Javac之inner与nested类

    One way declared types in Java differ from one another is whether the type is a class (which include ...

  4. Strut2 ognl取出存放在request,session,application和对象栈的中的值

    1.取出request,session,applicaiton中的值 a.往里面加入request,session,application中加入值 public String testServlet( ...

  5. WP的万能小应用时钟表

    哎,只能说现在是越来越不行了,已经近一年没写C#的代码了,我居然隐隐有看不懂自己代码的趋势了,真伤! 我突然想起当年寒假里面为了,准备微软创新杯大赛所做的一些小应用,哈哈,于是我就拿出来显摆一下喽! ...

  6. TP2.1 加载扩展配置文件参数

    维护老项目真的恶心!!!!!!!!! TP3.2好像有这样一个配置参数,可以设置有那些扩展配置文件,系统会自动加载. 方法一: 'LOAD_EXT_CONFIG' => 'user,db',// ...

  7. 自定义ContentTypeHandler在struts2-rest-2.3.16.2不生效

    需要使用自定义的ContentHandler格式化json中的时间类型为指定模式. 在struts.xml中增加了自定义的ContentHandler,但不会生效. http://blog.csdn. ...

  8. WINFORM如何实现无聚焦框的Button按钮

    当我们将一个button按钮设置如下属性时,总有一个聚焦框来困扰着我们 button1.FlatStyle = FlatStyle.Flat; 我们想要的效果是这样的: 但当使用了Tab切换焦点时 发 ...

  9. Swift函数_外部参数名,

    //1________________ /** *没使用外部参数名的函数 */ func inputScore(name:String,score1:Int,score2:Int) { } /** * ...

  10. 五、standalone运行模式

    在上文中我们知道spark的集群主要有三种运行模式standalone.yarn.mesos,其中常被使用的是standalone和yarn,本文了解一下什么是standalone运行模式,它的运行流 ...