java输入一个字符串，打印出该字符串中字符的所有排列,随机打乱排序

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class Test7
{
    private static String s="";
    
    public static void main(String[] args)
    {
        String str = "我是谁";
        System.out.println(permutation(str.toCharArray(), 0));
    }
    
    //随机打乱一个字符串的排序方式
      public static String shuffleForSortingString(String s) {
            char[] c = s.toCharArray();
            List<Character> lst = new ArrayList<Character>();
            for (int i = 0; i < c.length; i++) {
                lst.add(c[i]);
            }
            System.out.println(lst);
            Collections.shuffle(lst);
            System.out.println(lst);
            String resultStr = "";
            for (int i = 0; i < lst.size(); i++) {
                resultStr += lst.get(i);
            }
            System.out.println(resultStr);
            return resultStr;
        }
        
        
　　//打印字符串中所有排序（包含单个的）
        public static void execute(char[] array, List<String> list) {
            for (int i = 0; i < array.length; i++) {
                if (list.contains(array[i])) {
                    continue;
                }
                list.add(array[i]+"");
                if (list.size() == array.length) {
                    String str = "";
                    for (int n = 0; n < list.size(); n++) {
                        str += list.get(n);
                    }
                    System.out.println(str);
                } else {
                    execute(array, list);
                }
            
                list.remove(list.size() - 1);
            }
        }

//打印字符串中所有排序（就是一个字符串中的排序方式）
     public static String permutation(char[] str, int i) {
         if (i>= str.length)
             return s;
         if (i == str.length - 1) {
             s+="'"+String.valueOf(str)+"',";
             System.out.println(String.valueOf(str));
         } else {
             for (int j = i; j < str.length; j++) {
                 char temp = str[j];
                 str[j] = str[i];
                 str[i] = temp;
                 permutation(str, i + 1);
                 temp = str[j];
                 str[j] = str[i];
                 str[i] = temp;
             }
         }
         return s!=""?"select * from tableName where name in("+s.substring(0,s.length()-1)+")":s;
     }
    
}