[Leetcode] Palindrome Partitioning
Given a string s, partition s such that every substring of the partition is a palindrome.
Return all possible palindrome partitioning of s.
For example, given s = "aab",
Return
[
["aa","b"],
["a","a","b"]
]
Solution:
public class Solution {
public List<List<String>> partition(String s) {
List<List<String>> result=new ArrayList<List<String>>();
List<String> temp=new ArrayList<String>();
dfs(result,temp,s);
return result;
}
private void dfs(List<List<String>> result, List<String> temp, String s) {
// TODO Auto-generated method stub
if(s.length()==0){
result.add(new ArrayList<String>(temp));
return;
}
for(int i=1;i<=s.length();++i){
String str=s.substring(0, i);
if(isPalindrome(str)){
temp.add(str);
dfs(result, temp, s.substring(i));
temp.remove(temp.size()-1);
}
}
}
private boolean isPalindrome(String str) {
// TODO Auto-generated method stub
int end=str.length()-1;
int start=0;
while(start<end){
if(str.charAt(start)!=str.charAt(end))
return false;
start++;
end--;
}
return true;
}
}
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