python匹配ip正则

python匹配ip正则

#！/usr/bin/env python
# -*- coding:utf-8 -*-
import re
ip_str = "asdad1.1.1.1sdfwe2.6.5.7sdfsf2.3.94.5sdf200.198.25.0"
res = []
for i in range(1):  

    ip_t = True
    m_ind = 0
    while ip_t:
        m = re.search(r"(((2([0-4]\d|5[0-5])|((1\d|[1-9])?\d)|\d)\.){3}(2([0-4]\d|5[0-5])|(1\d|[1-9])?\d|\d))",ip_str[m_ind:])
        if m:
            msum = m.group()
            res.append(msum)
            m_ind = ip_str.index(msum) + len(msum) -1
        else:
            ip_t = False  

print(res)
#print(msum,m_ind)  

思路

图片有错误，但思路正确，代码和图片对比，放这个是为了对比思路，赞这个图片的人的思路，着实牛

shell grep 过滤所有ip

cat abc | grep -Po "(^10\.(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|[0-9])\.(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|[0-9])\.(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|[0-9])$)|(^172\.(1[6789]|2[0-9]|3[01])\.(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|[0-9])\.(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|[0-9])$)|(^192\.168\.(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|[0-9])\.(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|[0-9])$)"