projecteuler---->problem=8----Largest product in a series
title:
The four adjacent digits in the 1000-digit number that have the greatest product are 9
9
8
9 = 5832.
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?
翻译:
求出连续的13位数的积,使其最大
a="73167176531330624919225119674426574742355349194934"
a1="96983520312774506326239578318016984801869478851843"
a2="85861560789112949495459501737958331952853208805511"
a3="12540698747158523863050715693290963295227443043557"
a4="66896648950445244523161731856403098711121722383113"
a5="62229893423380308135336276614282806444486645238749"
a6="30358907296290491560440772390713810515859307960866"
a7="70172427121883998797908792274921901699720888093776"
a8="65727333001053367881220235421809751254540594752243"
a9="52584907711670556013604839586446706324415722155397"
a10="53697817977846174064955149290862569321978468622482"
a11="83972241375657056057490261407972968652414535100474"
a12="82166370484403199890008895243450658541227588666881"
a13="16427171479924442928230863465674813919123162824586"
a14="17866458359124566529476545682848912883142607690042"
a15="24219022671055626321111109370544217506941658960408"
a16="07198403850962455444362981230987879927244284909188"
a17="84580156166097919133875499200524063689912560717606"
a18="05886116467109405077541002256983155200055935729725"
a19="71636269561882670428252483600823257530420752963450"
a=a+a1+a2+a3+a4+a5+a6+a7+a8+a9+a10+a11+a12+a13+a14+a15+a16+a17+a18+a19
resu=0
for i in range(0,987):
s=1
for j in range(13):
s*=int(a[i+j])
if s > resu:
resu = s
print resu
projecteuler---->problem=8----Largest product in a series的更多相关文章
- projecteuler Problem 8 Largest product in a series
The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = ...
- Problem 8: Largest product in a series
先粘实现代码,以后需要再慢慢补充思路 s = ''' 73167176531330624919225119674426574742355349194934 9698352031277450632623 ...
- Largest product in a series
这个我开始理解错了,算错了. 我以为是求连续5个数的最大值,结果,是连接5个数相乘的最大值. 英语不好,容易吃亏啊. Find the greatest product of five consecu ...
- 【Project Euler 8】Largest product in a series
题目要求是: The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × ...
- Project Euler 8 Largest product in a series
题意:寻找这 1000 个数中相邻 13 个数相乘积最大的值 思路:首先想到的是暴力,但是还可以利用之前记录过的数值,什么意思呢?即在计算 2 - 14 后,再计算 3 - 15 时完全可以利用之前计 ...
- Largest product from 3 integers
https://github.com/Premiumlab/Python-for-Algorithms--Data-Structures--and-Interviews/blob/master/Moc ...
- Problem 4: Largest palindrome product
A palindromic number reads the same both ways. The largest palindrome made from the product of two 2 ...
- R语言学习——欧拉计划(11)Largest product in a grid
Problem 11 In the 20×20 grid below, four numbers along a diagonal line have been marked in red. 08 0 ...
- Largest product in a grid
这个比前面的要复杂点,但找对了规律,还是可以的. 我逻辑思维不强,只好画图来数数列的下标了. 分四次计算,存入最大值. 左右一次,上下一次,左斜一次,右斜一次. In the 2020 grid be ...
随机推荐
- Java 注解机制
一.注解中的信息已经在Class中了,我们应该如何读取出来 java.lang.reflect.AnnotatedElement接口: public Annotation[] getAnnotatio ...
- 我的Fedora22美化日记
首先我说一下,我命令是乱打的[不要打我],用之前先google 配置RPMFusion仓库 $ sudo dnf install --nogpgcheck http://download1.rpmfu ...
- 对discuz的代码分析学习(二)首页文件
如果当前地址栏存在查询字符,并且是一个数字,条件成立. 查询字符:www.baidu.com/index.php?aaa=bbb aaa=bbb就是查询字符如果条件成立,则把 ...
- 搭建Ubuntu环境中的Error [dpkg 被中断,您必须手工运行 sudo dpkg --configure -a 解决此问题][安装Flashplayer出错 ]
//解决方法如下: sudo rm /var/cache/apt/archives/lock sudo rm /var/lib/dpkg/lock sudo dpkg -r flashplugin-i ...
- RHEL4-Partition Image系统备份(软件版)
对于BBS,或Apache,PHP等相关网页的程序 备份: 1)/var/www/html目录,里面有PHP所写成的网页.此网页主要功能是从资料库中读取由信件存入的文章,或是使用者选择由网页输入资料时 ...
- [C/C++标准库]_[0基础]_[优先队列priority_queue的使用]
std::priority_queue 场景: 1. 对于一个任务队列,任务的优先级由任务的priority属性指明,这时候就须要优先级越高的先运行.而queue并没有排序功能,这时priority_ ...
- Linux学习笔记之权限与命令之间的关系(重要)及文件与文件夹知识总结
一.让使用者能进入某文件夹成为可工作文件夹的基本权限为何: 可使用的命令:比如 cd 等变换工作文件夹的命令. 文件夹所需权限:使用者对这个文件夹至少须要具有 x的权限 额外需求:假设使用者想要在这个 ...
- Linux 进程通信之 ——信号和信号量总结
如今最经常使用的进程间通信的方式有:信号,信号量,消息队列,共享内存. 所谓进程通信,就是不同进程之间进行一些"接触",这种接触有简单,也有复杂.机制不同,复杂度也不一 ...
- js柯里化的一个应用
听到同学说面试一道题目 add(1)(2)(3)(4); 查询了下资料 这是一个js里面的柯里化 现象 add_curry防范返回的是一个 retVal,并不是执行结果.这里的代码很想递归,但是不是 ...
- Webform之FileUpload(上传按钮控件)简单介绍及下载、上传文件时图片预览
1.FileUpload上传控件:(原文:http://www.cnblogs.com/hide0511/archive/2006/09/24/513201.html) FileUpload 控件显示 ...