坑爹CF April Fools Day Contest题解
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
The input contains two integers a and
b (0 ≤ a, b ≤ 103), separated by a single space.
Output the sum of the given integers.
5 14
19
381 492
873
坑爹啊这题目,输出格式要求……我记得我年少无知时候刚打完各种A+B题目后参加比赛盼望A+B题目的出现..
今天看到了,WA了好多次。。重点就是输出后要多输个空格。。
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std; int main(){
int a,b;
cin>>a>>b;
cout<<a+b<<" "<<endl; return 0; }
1 second
256 megabytes
standard input
standard output
Two teams meet in The Game World Championship. Some scientists consider this game to be the most intellectually challenging game in the world. You are given two strings describing the teams' actions in the final battle. Figure out who became the champion.
The input contains two strings of equal length (between 2 and 20 characters, inclusive). Each line describes the actions of one team.
Output "TEAM 1 WINS" if the first team won, "TEAM 2 WINS" if the second team won, and "TIE" if there was a tie.
[]()[]8<
8<[]()8<
TEAM 2 WINS
8<8<()
[]8<[]
TIE
还是水题一道。原理很简单。
"8<" > " [] "
"[ ] " > " ()"
"() " > "8<"
我本来以为我这么天真的想法是肯定WA了,但是题目的信息量真心低啊……硬着头皮交了,AC了……
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
using namespace std; int main(){
string a,b;
int A,B;
A=0,B=0; cin>>a>>b;
for(int i=0;i<a.length();i+=2){
if(a[i]==b[i]){
continue;
}else{
if(a[i]=='8'&&b[i]=='['){
A++;
}else if(a[i]=='['&&b[i]=='('){
A++;
}else if(a[i]=='('&&b[i]=='8'){
A++; }else if(a[i]==b[i]){
A++;
B++;
}else{
B++;
} } }
if(A==B){cout<<"TIE"<<endl;}
else if(A>B){cout<<"TEAM 1 WINS"<<endl;}
else cout<<"TEAM 2 WINS"<<endl; return 0; }
Salve, mi amice.
Et tu quidem de lapis philosophorum. Barba non facit philosophum. Labor omnia vincit. Non potest creatio ex nihilo. Necesse est partibus.
Rp:
I Aqua Fortis
I Aqua Regia
II Amalgama
VII Minium
IV Vitriol
Misce in vitro et æstus, et nil admirari. Festina lente, et nulla tenaci invia est via.
Fac et spera,
Vale,
Nicolas Flamel
The first line of input contains several space-separated integers
ai (0 ≤ ai ≤ 100).
Print a single integer.
2 4 6 8 10
1
炼金术你懂不懂?真扯淡……题目写得无法读懂,是法文吗?反正我最多能看懂英文,中文,还有粤语~(没有粤语OJ啊!!!),百度了一下,就是炼金术的配方啊。。。
I Aqua Fortis 1分量的硝酸
I Aqua Regia 1分量的王水
II Amalgama 2分量的汞合金
VII Minium 7分量的四氧化三铅
IV Vitriol 4分量的硫酸盐
不知道我翻译错了没有,神配方啊!
给定ABCDE,求最多配出多少(?)。
这个41专场真心太坑。。
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
using namespace std; int main(){ int A,B,C,D,E; cin>>A>>B>>C>>D>>E; C>>=1;
D/=7;
E>>=2;
A= min(A,B);
A= min(A,E);
C= min(D,C);
C= min(A,C);
cout<<C<<endl; //cout<<res<<endl; return 0; }
You are given a mysterious language (codenamed "Secret") available in "Custom Invocation" tab. Figure out what this language is and write a program which prints its name. Note that the program must be written in this language.
This program has only one test (your program doesn't have to read anything).
Output the name of the mysterious language. Note that the name is case-sensitive and might contain digits and special characters.
Some scientists disagree on what should be considered as a language and what should be considered as a dialect.
这题目,必须先WA一次。看着CE来百度,发现是FORTRAN,写了N次,都是CE,无果,看别人AC代码,跪了。
write(*,*)"FORTRAN 77"
END
不能少缩紧啊!!!!前面的空格不能没有。
1 second
256 megabytes
standard input
standard output
Little Petya wanted to give an April Fools Day present to some scientists. After some hesitation he decided to give them the array that he got as a present in Codeforces Round #153 (Div.2). The scientists rejoiced at the gift and decided to put some important
facts to this array. Here are the first few of the facts:
- The highest mountain above sea level in the world is Mount Everest. Its peak rises to 8848 m.
- The largest board game tournament consisted of 958 participants playing chapaev.
- The largest online maths competition consisted of 12766 participants.
- The Nile is credited as the longest river in the world. From its farthest stream in Burundi, it extends 6695 km in length.
- While not in flood, the main stretches of the Amazon river in South America can reach widths of up to 1100 km at its widest points.
- Angel Falls is the highest waterfall. Its greatest single drop measures 807 m.
- The Hotel Everest View above Namche, Nepal — the village closest to Everest base camp – is at a record height of 31962 m
- Uranium is the heaviest of all the naturally occurring elements. Its most common isotope has a nucleus containing 146 neutrons.
- The coldest permanently inhabited place is the Siberian village of Oymyakon, where the temperature of -68°C was registered in the
twentieth century. - The longest snake held in captivity is over 25 feet long. Its name is Medusa.
- Colonel Meow holds the world record for longest fur on a cat — almost 134 centimeters.
- Sea otters can have up to 10000 hairs per square inch. This is the most dense fur in the animal kingdom.
- The largest state of USA is Alaska; its area is 663268 square miles
- Alaska has a longer coastline than all of the other 49 U.S. States put together: it is 154103 miles long.
- Lake Baikal is the largest freshwater lake in the world. It reaches 1642 meters in depth and contains around one-fifth of the world’s unfrozen fresh water.
- The most colorful national flag is the one of Turkmenistan, with 106 colors.
The input will contain a single integer between 1 and 16.
Output a single integer.
据官方解释,这是一题判别每个事件的正确性,没耐心,直接看答案过了算了。。。
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
using namespace std; int main(){ int A;
int B[]={0,1,0,0,1,0,1,0,1,1,1,0,0,1,0,1,0};
cin>>A; cout<<B[A]<<endl; //cout<<res<<endl; return 0; }
The input contains a single integer a (1 ≤ a ≤ 64).
Output a single integer.
2
1
4
2
27
5
42
6
第一次做没有题目详情的题目……
我相信绝大多部分人都跟我一样,看成是ceil(log(n)/log(n))的题目,之后陷入无限WA。。。
这个世界有一个A000001数列……
巨坑。。
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
using namespace std; int main(){ int A;
int B[]={0,1, 1, 1, 2, 1, 2, 1, 5, 2, 2, 1, 5,
1, 2, 1, 14, 1, 5, 1, 5, 2, 2, 1, 15,
2, 2, 5, 4, 1, 4, 1, 51, 1, 2, 1, 14,
1, 2, 2, 14, 1, 6, 1, 4, 2, 2, 1, 52,
2, 5, 1, 5, 1, 15, 2, 13, 2, 2, 1, 13,
1, 2, 4, 267, 1, 4, 1, 5, 1, 4, 1, 50,
1, 2, 3, 4, 1, 6, 1, 52, 15, 2, 1, 15,
1, 2, 1, 12, 1, 10, 1, 4, 2 };
cin>>A; cout<<B[A]<<endl; //cout<<res<<endl; return 0; }
今天算是放松放松,开心开心,41专场真坑。。。
坑爹CF April Fools Day Contest题解的更多相关文章
- CF #April Fools Day Contest 2016 E Out of Controls
题目连接:http://codeforces.com/problemset/problem/656/E 愚人节专场的E,整个其实就是个Floyd算法,但是要求代码中不能包含 definedoforfo ...
- April Fools Day Contest 2014
April Fools Day Contest 2014 A.C.H三道题目 ============================================================= ...
- April Fools Day Contest 2014 H. A + B Strikes Back
H. A + B Strikes Back time limit per test 1 second memory limit per test 256 megabytes input standar ...
- April Fools Day Contest 2016 D. Rosetta Problem
D. Rosetta Problem 题目连接: http://www.codeforces.com/contest/656/problem/D Description ++++++++[>+& ...
- April Fools Day Contest 2016 G. You're a Professional
G. You're a Professional 题目连接: http://www.codeforces.com/contest/656/problem/G Description A simple ...
- April Fools Day Contest 2016 F. Ace It!
F. Ace It! 题目连接: http://www.codeforces.com/contest/656/problem/F Description Input The only line of ...
- April Fools Day Contest 2016 E. Out of Controls
E. Out of Controls 题目连接: http://www.codeforces.com/contest/656/problem/E Description You are given a ...
- April Fools Day Contest 2016 C. Without Text 信号与系统
C. Without Text 题目连接: http://www.codeforces.com/contest/656/problem/C Description You can preview th ...
- April Fools Day Contest 2016 B. Scrambled
B. Scrambled 题目连接: http://www.codeforces.com/contest/656/problem/B Description Btoh yuo adn yuor roo ...
随机推荐
- Kafka系列(二)特性和常用命令
Kafka中Replicas复制备份机制 kafka将每个partition数据复制到多个server上,任何一个partition有一个leader和多个follower(可以没有),备份的个数可以 ...
- mmsql 查询每个分类的前3条数据
select * from (select *,row_number() over(partition by PropertyRoofBeamID order by PropertyRoomID de ...
- js 复制网页内容,兼容各浏览器
因需要做一个js单击,复制当前网页url的功能.使用的是如下的方法,但是只能在ie浏览器下正常使用. 方法如下: function copyURL(){ var clipBoardContent=&q ...
- wechat客户端修改
1. src/ui/adapter/FriendCardAdapter.java @Override public View getView(int position, View conver ...
- 简洁 Abstract Factory模式(3.1)
镇楼 在某些书中使用了二维图说明抽象工厂模式.非常好,可是yqj2065不喜欢他们的产品族/产品等级,改成品牌/产品类型. 抽象工厂模式(abstract factory pattern)较工厂方法模 ...
- Android内存、性能是程序永恒的话题
内存.性能是程序永恒的话题,实际开发中关于卡顿.OOM也经常是打不完的两只老虎,关于卡顿.OOM的定位方法和工具比较多,这篇文章也不打算赘述了,本章主要是来整理一下JVM的内存模型以及Java对象的生 ...
- Linux系统及应用问题分析排查工具
linux 阿里技术协会 摘要: Linux服务器上经常遇到一些系统和应用上的问题,如何分析排查,需要利器,下面总结列表了一些常用工具.trace tool:最后也列举了最近hadoop社区在开发发展 ...
- uuid_short() 源代码
/* uuid_short handling. The short uuid is defined as a longlong that contains the following bytes: B ...
- 使用new分配内存的类需要自己定义拷贝构造函数
13.22 假定我们希望HasPtr的行为像一个值.即,对于对象所指向的string成员,每个对象都有一份自己的拷贝. #include<iostream> #include<str ...
- 动作-CCActionInterval之CCActionEase家族
补间动作也是一个包装器(之前叫补间动画,从字面上讲,叫动作更合适一些.).你也可以叫他缓释动作. 1.含义 补间动作改变的是,内部动作的执行速率(注意,并没有改变执行的最终效果,和执行的时间.)关于这 ...