v.size() return size_t not int 返回无符号整型数

In the C++ STL, the vector size() function return size_t, which is unsigned int, not int. So imagine this, define an empty vector<int> v, and v.size() should be 0, and you have a for loop, and has an end condition is v.size() - 1, which is 4294967295 actually, not -1. This might cause problem when i = 0, which can enter the for loop, but actually was supposed not entering it.

vector<int> v;
cout << v.size() << endl;      //
cout << v.size() -  << endl;  // 4294967295
cout << v.size() -  << endl;  //

cout << v.size() << endl;           //
cout << int(v.size() - ) << endl;  // -1
cout << int(v.size() - ) << endl;  // -2