UWP 读取XML文件

一、读取本地XML文件时要将xxx.xml文件的“生成操作”改为“嵌入的资源”会比较好，在手机上运行的话需要改为“内容”

<?xml version="1.0" encoding="utf-8"?>
<DataSet xmlns="http://WebXml.com.cn/">
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
    <Area xmlns="">
      <AreaList diffgr:id="AreaList1" msdata:rowOrder="0">
        <areaID>-4</areaID>
        <Area>数字电视</Area>
        <Zone>数字</Zone>
      </AreaList>
      <AreaList diffgr:id="AreaList2" msdata:rowOrder="1">
        <areaID>-3</areaID>
        <Area>海外电视</Area>
        <Zone>海外</Zone>
      </AreaList>
</diffgr:diffgram>
</DataSet>

前台用一个ListView显示

后台的读取方式为

XDocument xdoc = XDocument.Load("Resources/AreaDataSet.xml");//   文件夹/文件
var dataInfo = from query in xdoc.Descendants("AreaList")
                           select new Model
                           {
                               areaID = (string)query.Element("areaID"),
                               Area = (string)query.Element("Area")
                           };

还有一个Model类来存取数据

二、若是存储在流中，那么读取方式是

Stream stream = response.GetResponseStream();
StreamReader reader = new StreamReader(stream);

string contents = reader.ReadToEnd();
listInfo = new List<TVprogram>();
XElement _xml = XElement.Parse(contents);
var res = from x in _xml.DescendantsAndSelf("TvStation") select x;
foreach (var item in res)
{
    TVprogram dataInfo = new TVprogram();
    dataInfo.tvStationID = item.Element("tvStationID").Value.Trim();
    dataInfo.tvStationName = item.Element("tvStationName").Value.Trim();
    listInfo.Add(dataInfo);
}