HDU 1704 Rank
Rank
This problem will be judged on HDU. Original ID: 1704
64-bit integer IO format: %I64d Java class name: Main
ZJPCPC Sunny Cup 2007 is coming, and lcy want to select some excellent ACMers to attend the contest. There have been M matches since the last few days(No two ACMers will meet each other at two matches, means between two ACMers there will be at most one match). lcy also asks"Who is the winner between A and B?" But sometimes you can't answer lcy's query, for example, there are 3 people, named A, B, C.and 1 match was held between A and B, in the match A is the winner, then if lcy asks "Who is the winner between A and B", of course you can answer "A", but if lcy ask "Who is the winner between A and C", you can't tell him the answer.
As lcy's assistant, you want to know how many queries at most you can't tell lcy(ask A B, and ask B A is the same; and lcy won't ask the same question twice).
Input
The first line has one integer,represent the number of test cases.
Each case first contains two integers N and M(N , M <= 500), N is the number of ACMers in HDU team, and M is the number of matchs have been held.The following M lines, each line means a match and it contains two integers A and B, means A wins the match between A and B.And we define that if A wins B, and B wins C, then A wins C.
Output
Sample Input
3
3 3
1 2
1 3
2 3
3 2
1 2
2 3
4 2
1 2
3 4
Sample Output
0
0
4
in the case3, if lcy ask (1 3 or 3 1) (1 4 or 4 1) (2 3 or 3 2) (2 4 or 4 2), then you can't tell him who is the winner.
Source
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <climits>
#include <vector>
#include <queue>
#include <cstdlib>
#include <string>
#include <set>
#include <stack>
#define LL long long
#define pii pair<int,int>
#define INF 0x3f3f3f3f
using namespace std;
const int maxn = ;
int n,m;
bool mp[maxn][maxn];
void Floyd(){
for(int k = ; k <= n; k++){
for(int i = ; i <= n; i++){
for(int j = ; mp[i][k]&&j <= n; j++)
mp[i][j] |= mp[i][k]&mp[k][j];
}
}
}
int main() {
int t,u,v,ans;
scanf("%d",&t);
while(t--){
scanf("%d %d",&n,&m);
memset(mp,false,sizeof(mp));
for(int i = ; i < m; i++){
scanf("%d %d",&u,&v);
mp[u][v] = true;
}
Floyd();
ans = ;
for(int i = ; i <= n; i++){
for(int j = i+; j <= n; j++)
if(mp[i][j] == && mp[j][i] == ) ans++;
}
printf("%d\n",ans);
}
return ;
}
HDU 1704 Rank的更多相关文章
- hdu 1704 Rank (floyd闭包)
Rank Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submis ...
- hdu - 1704 Rank(简单dfs)
http://acm.hdu.edu.cn/showproblem.php?pid=1704 遇到标记过的就dfs,把隐含的标记,最后计数需要注意. #include <cstdio> # ...
- HDU 1704 Rank【传递闭包】
解题思路:给出n个选手,m场比赛,问不能判断胜负的询问最多有多少种 用传递闭包即可 但是如果直接用3重循环会超时 在判断d[i][j]=d[i][k]||d[k][j]是否连通的时候 可以加一个if语 ...
- ACM: hdu 1811 Rank of Tetris - 拓扑排序-并查集-离线
hdu 1811 Rank of Tetris Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & % ...
- Rank HDU - 1704 【传递闭包水题】
there are N ACMers in HDU team.ZJPCPC Sunny Cup 2007 is coming, and lcy want to select some excellen ...
- hdu 1718 Rank
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1718 Rank Description Jackson wants to know his rank ...
- hdu 1811 Rank of Tetris - 拓扑排序 - 并查集
自从Lele开发了Rating系统,他的Tetris事业更是如虎添翼,不久他遍把这个游戏推向了全球. 为了更好的符合那些爱好者的喜好,Lele又想了一个新点子:他将制作一个全球Tetris高手排行榜, ...
- hdu 1704 (Floyd 传递闭包)
Rank Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submis ...
- HDU 1811 Rank of Tetris(并查集按秩合并+拓扑排序)
Rank of Tetris Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) T ...
随机推荐
- Python基础--正則表達式基本的语法以及re模块
正则是个非常牛逼的东西,python中当然也不会缺少. 所以今天的Python就跟大家一起讨论一下python中的re模块. re模块包括对正則表達式的支持. 什么是正则: 正則表達式是能够匹配文本片 ...
- 解析HTTP协议六种请求方法
标准Http协议支持六种请求方法,即: 1,GET 2,HEAD 3,PUT 4,DELETE 5,POST 6,OPTIONS 但其实我们大部分情况下只用到了GET和POST.如果想设计一个符合RE ...
- GDI+学习之------色彩与图像
色彩 在GDI+中.色彩是通过Color类来描写叙述的.不是用RGB类.用RGB构造会出错.GDI+中的色彩信息值是由一个32位的数据来表示的,它包含8位alpha值和各8位的R.G.B值,对于alp ...
- JS容易犯错的this和作用域
var someuser = { name: 'byvoid', func: function() { console.log(this.name); } }; var foo = { name: ' ...
- 学界| UC Berkeley提出新型分布式框架Ray:实时动态学习的开端—— AI 应用的系统需求:支持(a)异质、并行计算,(b)动态任务图,(c)高吞吐量和低延迟的调度,以及(d)透明的容错性。
学界| UC Berkeley提出新型分布式框架Ray:实时动态学习的开端 from:https://baijia.baidu.com/s?id=1587367874517247282&wfr ...
- glance rabbit
- Constructing Roads In JGShining's Kingdom(LIS)
http://acm.hdu.edu.cn/showproblem.php?pid=1025 题意:富人路与穷人路都分别有从1到n的n个点,现在要在富人点与穷人点之间修路,但是要求路不能交叉,问最多能 ...
- hdu3652B-number(数位dp)
B-number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Su ...
- 指令重排序所带来的问题及使用volatile关键字解决问题
首先看下如下代码: 指令重排序和优化后代码如下:if(!stop)while(true){}volatile最适合使用的是一个线程写.其他线程读的场合,如果有多个线程并发写操作,仍然需要使用锁或者线程 ...
- HTML基础练习
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/stri ...