java编程思想第四版第十三章字符串习题

第二题

package net.mindview.strings;

import java.util.ArrayList;

import java.util.List;

/**

 * 无限循环

 */

public class InfiniteRecursion {

    public InfiniteRecursion(){

    }

    @Override

    public String toString() {

        return " InfiniteRecursion address" + super.toString() + "\n";

    }

    public static void main(String[] args) {

        List<InfiniteRecursion> list = new ArrayList<InfiniteRecursion>();

        for(int i=; i<; i++){

            list.add(new InfiniteRecursion());

        }

        System.out.println(list);

    }

}

第四题

package net.mindview.strings;

import java.util.Formatter;

public class Receipt {

    private double total = ;

    private Formatter f = new Formatter(System.out);

    public final int ITEM_WIDTH = ;

    public final int QTY_WIDTH = ;

    public final int PRICE_WIDTH = ;

    public final int PRICISION_FLOAT_WIDHT = ;

    public final int PRICISION_String_WIDHT = ;

    public final String TITLE_FORMAT = "%-" + ITEM_WIDTH + "s %" + QTY_WIDTH

            + "s %" + PRICE_WIDTH + "s\n";

    public final String PRICE_FORMAT = "%-" + ITEM_WIDTH + "."

            + PRICISION_String_WIDHT + "s %" + QTY_WIDTH + "d %" + PRICE_WIDTH

            + "." + PRICISION_FLOAT_WIDHT + "f\n";

    public final String TOTAL_FORMAT = "%-" + ITEM_WIDTH + "s %" + QTY_WIDTH

            + "s %" + PRICE_WIDTH + "." + PRICISION_FLOAT_WIDHT + "f\n"; 

    //打印标题

    public void printTitle(){

        /*

         * 含义: 格式化字符串串以%开头

         * -: 表示左对齐

         * 15: 15表示宽度

         * s:表示数据的类型是String

         * .2f:表示浮点数保留的小数位数

         * .15s:表示字符串的长度最多15个字符

         */

        f.format(TITLE_FORMAT, "Item", "Qty", "Price");

        f.format(TITLE_FORMAT, "----", "---", "-----");

    }

    //正文的内容

    public void print(String name, int qty, double price){

        f.format(PRICE_FORMAT, name, qty, price);

        total += price;

    }

    //总价

    public void printTotal(){

        f.format(TOTAL_FORMAT, "Tax", "", total*0.06);

        f.format(TITLE_FORMAT, "", "", "-----");

        f.format(TOTAL_FORMAT, "Total", "", total*1.06);

    }

    public static void main(String[] args) {

        Receipt receipt = new Receipt();

        receipt.printTitle();

        receipt.print("Jack`s Magic Beans", , 4.25);

        receipt.print("Princess Peas", , 5.1);

        receipt.print("Three Bears Porridge", , 14.29);

        receipt.printTotal();

    }

}

运行结果：

Item              Qty      Price

----              ---      -----

Jack`s Magic Be            4.25

Princess Peas              5.10

Three Bears Por           14.29

Tax                         1.42

                           -----

Total                      25.06

第五题

package net.mindview.strings;

import java.util.Formatter;

public class Receipt {

    private double total = ;

    private Formatter f = new Formatter(System.out);

    public final int ITEM_WIDTH = ;

    public final int QTY_WIDTH = ;

    public final int PRICE_WIDTH = ;

    public final int PRICISION_FLOAT_WIDHT = ;

    public final int PRICISION_String_WIDHT = ;

    public final String TITLE_FORMAT = "%-" + ITEM_WIDTH + "s %" + QTY_WIDTH

            + "s %" + PRICE_WIDTH + "s\n";

    public final String PRICE_FORMAT = "%-" + ITEM_WIDTH + "."

            + PRICISION_String_WIDHT + "s %" + QTY_WIDTH + "d %" + PRICE_WIDTH

            + "." + PRICISION_FLOAT_WIDHT + "f\n";

    public final String TOTAL_FORMAT = "%-" + ITEM_WIDTH + "s %" + QTY_WIDTH

            + "s %" + PRICE_WIDTH + "." + PRICISION_FLOAT_WIDHT + "f\n"; 

    //打印标题

    public void printTitle(){

        /*

         * 含义: 格式化字符串串以%开头

         * -: 表示左对齐

         * 15: 15表示宽度

         * s:表示数据的类型是String

         * .2f:表示浮点数保留的小数位数

         * .15s:表示字符串的长度最多15个字符

         */

        f.format(TITLE_FORMAT, "Item", "Qty", "Price");

        f.format(TITLE_FORMAT, "----", "---", "-----");

    }

    //正文的内容

    public void print(String name, int qty, double price){

        f.format(PRICE_FORMAT, name, qty, price);

        total += price;

    }

    //总价

    public void printTotal(){

        f.format(TOTAL_FORMAT, "Tax", "", total*0.06);

        f.format(TITLE_FORMAT, "", "", "-----");

        f.format(TOTAL_FORMAT, "Total", "", total*1.06);

    }

    public static void main(String[] args) {

        Receipt receipt = new Receipt();

        receipt.printTitle();

        receipt.print("Jack`s Magic Beans", , 4.25);

        receipt.print("Princess Peas", , 5.1);

        receipt.print("Three Bears Porridge", , 14.29);

        receipt.printTotal();

    }

}

运行结果:

Item              Qty      Price

----              ---      -----

Jack`s Magic Be            4.25

Princess Peas              5.10

Three Bears Por           14.29

Tax                         1.42

                           -----

Total                      25.06

第七题:

package net.mindview.strings.test7;

public class Test7 {

    public static void main(String[] args) {

        //两种写法都可以

        String regex = "^[A-Z].*\\.$";

        String regex1 = "\\p{Upper}.*\\.$";

        String str = "D.";

        String str1 = "Dfasdfasfasfdasfdasfasfasdf.";

        String str2 = "Dfasdfasfasfdasfdasfasfasdf.E";

        System.out.println(str.matches(regex));

        System.out.println(str1.matches(regex));

        System.out.println(str2.matches(regex));

        System.out.println(str.matches(regex1));

        System.out.println(str1.matches(regex1));

        System.out.println(str2.matches(regex1));

    }

}

运行结果:

true

true

false

true

true

false

第八题

package net.mindview.strings;

import java.util.Arrays;

public class Splitting {

    public static String knights = "Then, when you have found the shrubbery, you must cut down the mightiest tree in the forest... with... a herring!";

    public static void split(String regex){

        System.out.println(Arrays.toString(knights.split(regex)));

    }

    public static void main(String[] args) {

        //表示的时按照空格分割字符串

        //运行结果:[Then,, when, you, have, found, the, shrubbery,, you, must, cut, down, the, mightiest, tree, in, the, forest..., with..., a, herring!]

        split(" ");

        //表示按照非单次字符分割字符串--这里的非单次字符是空格和,

        //运行结果:[Then, when, you, have, found, the, shrubbery, you, must, cut, down, the, mightiest, tree, in, the, forest, with, a, herring]

        split("\\W+");

        //这个表示:费单次字符之前带n的地方进行分割字符串 这里的分割符是n空格和n,

        //运行结果:[The, whe, you have found the shrubbery, you must cut dow, the mightiest tree i, the forest... with... a herring!]

        split("n\\W+");

    }

}

package net.mindview.strings.test8;

import net.mindview.strings.Splitting;

public class Test8 {

    public static void main(String[] args) {

        String regex = "the|you";

        Splitting.split(regex);

    }

}

第九题

package net.mindview.strings.test9;

import net.mindview.strings.Splitting;

public class Test9 {

    public static void main(String[] args) {

        String regex = "A|E|I|O|U|a|e|i|o|u";

        //通过嵌入式标志表达式  (?i) 也可以启用不区分大小写的匹配。

        String regex1 = "(?i)a|e|i|o|u";

        //[abc] 表示a或b或c

        String regex2 = "(?i)[aeiou]";

        System.out.println(Splitting.knights.replaceAll(regex, "_"));

        System.out.println(Splitting.knights.replaceAll(regex1, "_"));

        System.out.println(Splitting.knights.replaceAll(regex2, "_"));

    }

}

第十题

package net.mindview.strings.test10;

import java.util.regex.Matcher;

import java.util.regex.Pattern;

public class Test10 {

    public static void main(String[] args) {

        String str = "Java now has regular expressions";

        for(String arg: args){

            Pattern p = Pattern.compile(arg);

            Matcher m = p.matcher(str);

            while(m.find()){

                System.out.println("Match \"" + m.group() +"\" at positions " + m.start() + "-" + (m.end()-) );

            }

            System.out.println("\n");

        }

    }

}

输入参数:

^Java

\Breg.*

n.w\s+h(a|i)s

s?

s*

s+

s{}

s{}.

s{,}

输出结果

Match "Java" at positions -

Match "now has" at positions -

Match "" at positions --

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "s" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "s" at positions -

Match "s" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "s" at positions -

Match "" at positions -

Match "s" at positions -

Match "ss" at positions -

Match "s" at positions -

Match "s " at positions -

Match "ss" at positions -

Match "" at positions --

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "s" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "ss" at positions -

Match "" at positions -

Match "" at positions -

Match "" at positions -

Match "s" at positions -

Match "" at positions -

第十一题

package net.mindview.strings.test11;

import java.util.regex.Matcher;

import java.util.regex.Pattern;

public class Test11 {

    public static void main(String[] args) {

        Pattern p = Pattern.compile("(?i)((^[aeiou])|(\\s+[aeiou]))\\w+?[aeiou]\\b");

        Matcher m = p.matcher("Arline ate eight apples and " +

"one orange while Anita hadn't any");

        while(m.find()){

            System.out.println("Match \"" + m.group() +

                    "\" at positions " + m.start() + "-" +

                    (m.end() - ));

        }

    }

}

运行结果:

Match "Arline" at positions -

Match " ate" at positions -

Match " one" at positions -

Match " orange" at positions -

Match " Anita" at positions -

sfa
f
a
fda
sdf
af
a
fd
af
as
fd
asfd
af
da
f
df
as
fa
sf
asf
a
sf
af
asf

java编程思想第四版第十三章字符串习题的更多相关文章

java编程思想第四版第十三章字符串总结
1. String和StringBulider的使用通过书中介绍, 我们得知如下结论: 当使用+连接符将字符串进行拼接的时候, 编译器会进行自动优化为使用StringBuilder连接字符串. 当在 ...
java编程思想第四版第三章要点习题
使用"简短的" 和正常的打印语句来编写一个程序 package net.mindview.util; public class Print { /** * 不带有回车 * @pa ...
java编程思想第四版第十一章习题
第一题 package net.mindview.holding.test1; import java.util.ArrayList; import java.util.List; /** * 沙鼠 ...
Java编程思想第四版*第七章*个人练习
欢迎加群:239063848 成团的笔记:该组仅用于技术共享和交流,问题和答案公布潘基聊天.禁止广告.禁止招聘-- 练习1:(2)创建一个简单的类.第二个类中,将一个引用定义为第一个类的对象.运用惰 ...
java编程思想第四版第六章习题
(略) (略) 创建两个包:debug和debugoff,他们都包含一个相同的类,该类有一个debug()方法,第一个版本显示发送给控制台的String参数,而第二版本什么也不做,使用静态import ...
java编程思想第四版第六章总结
1. 代码重构为什么f要代码重构第一次代码不一定是完美的, 总会发现更优雅的写法. 代码重构需要考虑的问题类库的修改不会破坏客户端程序员的代码. 源程序方便扩展和优化 2. 包创建一个独一无二 ...
java编程思想第四版第五章习题
创建一个类, 它包含一个未初始化的String引用.验证该引用被Java初始化成了null package net.mindview.initialization; public class Test ...
java编程思想第四版第六章个人练习
欢迎加群:239063848 进群须知:本群仅用于技术分享与交流.问题公布与解答禁止闲聊.非诚勿扰练习1:(1)在某个包中创建一个类,在这个类所处的包的外部创建该类的一个实例. import mi ...
java编程思想第四版第十一章总结
1. 容器类被分为两类:Collection和Map Collection是一个接口:包括: List接口: ArrayList:按照被插入顺序保存元素, 查询快, 增删改慢 LinkedList:按 ...

随机推荐

CVE-2019-0708(非蓝屏poc)远程桌面代码执行漏洞复现
玩了几天刚回成都玩电脑复现一下~ 内核漏洞原理暂时没看懂别问 ,问就是不懂 0x01 复现环境和Exp准备漏洞影响范围 Windows 7 Windows Server 2008 R2 W ...
POJ 3020 Antenna Placement(二分图匈牙利算法)
题目网址: http://poj.org/problem?id=3020 题意: 用椭圆形去覆盖给出所有环(即图上的小圆点),有两种类型的椭圆形,左右朝向和上下朝向的,一个椭圆形最多可以覆盖相邻的两 ...
POJ 1753 Flip Game(状态压缩+BFS)
题目网址:http://poj.org/problem?id=1753 题目: Flip Game Description Flip game is played on a rectangular 4 ...
查看java内存情况的几个常用命令
java 命令简单查看jvm内存使用状况 jinfo:可以输出并修改运行时的java 进程的opts. jps:与unix上的ps类似,用来显示本地的java进程,可以查看本地运行着几个java程序, ...
vue 自定义侧边栏递归无限子级菜单
有很多网站会涉及到导航栏,我自己在开发中用的是element导航组件,并且自定义事件,给大家分享一下. 1.使用递归方法,无限循环子级菜单. 2.使用组件封装,维护方便. 3.使用index作为路由跳 ...
Linux常用命令-不定时记录
文件移动命令命令格式:mv [-fiv] source destination 参数说明:-f:force,强制直接移动而不询问-i:若目标文件(destination)已经存在,就会询问是否覆盖- ...
PowerBI开发第十五篇：Power BI的行级安全
Power BI支持行级安全(Row-Level Security,RLS)的权限控制,用于限制用户对Dashboard.报表和DataSet的访问.用户浏览的报表是相同的,但是看到的数据却是不同的. ...
call方法和apply方法
1.call 语法 call([thisObj[,arg1[, arg2[, [,.argN]]]]]) 参数 thisObj 可选项.将被用作当前对象的对象. arg1,arg2, , argN ...
（四）适配器Adapter
只对简单应用进行描述.适配器与ListView配合使用可以快速生成item,效果如下例所示一.简单模式方式一 xml <ListView android:id="@+id/lv_t ...
游图邦YOTUBANG是如何搭建生态系统的？
现在的我们最关心的一个问题就是任何一个行业,如果没有办法很好的落地,就算描绘的非常美好,那也只是空中楼阁.昙花一现而已,它无法实现长久的一个发展.互联网时代呢,就是一个流量为王的一个时代,谁拥有庞大的 ...

java编程思想第四版第十三章字符串 习题

java编程思想第四版第十三章字符串 习题的更多相关文章

随机推荐

热门专题

java编程思想第四版第十三章字符串习题

java编程思想第四版第十三章字符串习题的更多相关文章