LeetCode: Longest Common Prefix 解题报告
Longest Common Prefix
Write a function to find the longest common prefix string amongst an array of strings.
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SOLUTION 1:
解法很直观。先找到最小长度,然后逐个字母遍历,同时逐个遍历所有的字符串。注意各种小细节:
1. break的时候,应该返回上一个索引指向的子串。
2. 如果没有break,表示minlen长度的字串就是最大pre.
public class Solution {
//http://blog.csdn.net/fightforyourdream/article/details/14642079
public String longestCommonPrefix(String[] strs) {
if (strs == null || strs.length == ) {
// bug 2: should not return null.
return "";
}
// Find out the shortest length.
String s0 = strs[];
int len = s0.length();
for (String s: strs) {
len = Math.min(len, s.length());
}
// The index of the character which is examing.
// Bug 3: 当不会break的时候,结果是错的
// Bug 4: forget to add int i = 0;
for (int i = ; i < len; i++) {
// Bug 1: forget to write charAt(i);
char c = s0.charAt(i);
for (int j = ; j < strs.length; j++) {
if (strs[j].charAt(i) != c) {
// Bug 5: write substring to sbustring
return s0.substring(, i);
}
}
}
// Never break, means strs[0].0-len is the solution.
return s0.substring(, len);
}
}
2015.1.2 redo:
public class Solution {
public String longestCommonPrefix(String[] strs) {
String ret = "";
if (strs == null || strs.length == 0) {
return ret;
}
int minLen = Integer.MAX_VALUE;
for (String str: strs) {
minLen = Math.min(str.length(), minLen);
}
for (int i = 0; i < minLen; i++) {
for (int j = 1; j < strs.length; j++) {
if (strs[0].charAt(i) != strs[j].charAt(i)) {
return strs[0].substring(0, i);
}
}
}
return strs[0].substring(0, minLen);
}
}
GITHUB:
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