The 14th Zhejiang Provincial Collegiate Programming Contest Sponsored by TuSimple

What Kind of Friends Are You?

Time Limit: 1 Second Memory Limit: 65536 KB

Japari Park is a large zoo home to extant species, endangered species, extinct species, cryptids and some legendary creatures. Due to a mysterious substance known as Sandstar, all the animals have become anthropomorphized into girls known as Friends.

Kaban is a young girl who finds herself in Japari Park with no memory of who she was or where she came from. Shy yet resourceful, she travels through Japari Park along with Serval to find out her identity while encountering more Friends along the way, and eventually discovers that she is a human.

However, Kaban soon finds that it's also important to identify other Friends. Her friend, Serval, enlightens Kaban that she can use some questions whose expected answers are either "yes" or "no" to identitfy a kind of Friends.

To be more specific, there are n Friends need to be identified. Kaban will ask each of them q same questions and collect their answers. For each question, she also gets a full list of animals' names that will give a "yes" answer to that question (and those animals who are not in the list will give a "no" answer to that question), so it's possible to determine the name of a Friends by combining the answers and the lists together.

But the work is too heavy for Kaban. Can you help her to finish it?

Input

There are multiple test cases. The first line of the input is an integer T (1 ≤ T ≤ 100), indicating the number of test cases. Then T test cases follow.

The first line of each test case contains two integers n (1 ≤ n ≤ 100) and q (1 ≤ q ≤ 21), indicating the number of Friends need to be identified and the number of questions.

The next line contains an integer c (1 ≤ c ≤ 200) followed by c strings p₁, p₂, ... , p_c (1 ≤ |p_i| ≤ 20), indicating all known names of Friends.

For the next q lines, the i-th line contains an integer m_i (0 ≤ m_i ≤ c) followed by m_i strings s_{i, 1}, s_{i, 2}, ... , s_{i, m_i} (1 ≤ |s_i, j| ≤ 20), indicating the number of Friends and their names, who will give a "yes" answer to the i-th question. It's guaranteed that all the names appear in the known names of Friends.

For the following n lines, the i-th line contains q integers a_{i, 1}, a_{i, 2}, ... , a_i, q (0 ≤ a_i, j ≤ 1), indicating the answer (0 means "no", and 1 means "yes") to the j-th question given by the i-th Friends need to be identified.

It's guaranteed that all the names in the input consist of only uppercase and lowercase English letters.

Output

For each test case output n lines. If Kaban can determine the name of the i-th Friends need to be identified, print the name on the i-th line. Otherwise, print "Let's go to the library!!" (without quotes) on the i-th line instead.

Sample Input

2

3 4

5 Serval Raccoon Fennec Alpaca Moose

4 Serval Raccoon Alpaca Moose

1 Serval

1 Fennec

1 Serval

1 1 0 1

0 0 0 0

1 0 0 0

5 5

11 A B C D E F G H I J K

3 A B K

4 A B D E

5 A B K D E

10 A B K D E F G H I J

4 B D E K

0 0 1 1 1

1 0 1 0 1

1 1 1 1 1

0 0 1 0 1

1 0 1 1 1

Sample Output

Serval

Let's go to the library!!

Let's go to the library!!

Let's go to the library!!

Let's go to the library!!

B

Let's go to the library!!

K

Hint

The explanation for the first sample test case is given as follows:

As Serval is the only known animal who gives a "yes" answer to the 1st, 2nd and 4th question, and gives a "no" answer to the 3rd question, we output "Serval" (without quotes) on the first line.

As no animal is known to give a "no" answer to all the questions, we output "Let's go to the library!!" (without quotes) on the second line.

Both Alpaca and Moose give a "yes" answer to the 1st question, and a "no" answer to the 2nd, 3rd and 4th question. So we can't determine the name of the third Friends need to be identified, and output "Let's go to the library!!" (without quotes) on the third line.

题意：t组数据 n个需要判断的人 q个问题 n个名字 q个问题的询问对象 n个人对q个问题的回答情况判断能否唯一的确定姓名可以则输出姓名否则输出"Let's go to the library!!"

题解：STL

 #include<bits/stdc++.h>

 using namespace std;

 int t;

 int n,q;

 int s;

 map<string,vector<int> > mp;

 map<int,string> st;

 int ve[];

 char a[];

 int main()

 {

     string str;

     scanf("%d",&t);

     for(int i=;i<=t;i++)

     {

         mp.clear();

         st.clear();

         scanf("%d %d",&n,&q);

         scanf("%d",&s);

         for(int j=;j<=s;j++){

             scanf("%s",a);

             str.assign(a);

             st[j]=str;

             }

         for(int k=;k<=q;k++)

         {

             int ww;

             scanf("%d",&ww);

             for(int j=;j<=ww;j++)

             {

                  scanf("%s",a);

                  str.assign(a);

                  mp[str].push_back(k);

             }

         }

         int exm;

         for(int k=;k<=n;k++)

         {

             int zha=;

             for(int j=;j<=q;j++)

             {

                 scanf("%d",&exm);

                 if(exm==)

                    ve[zha++]=j;

             }

             int judge=;

             string  ans;

             for(int e=;e<=s;e++)

             {

                 if(mp[st[e]].size()==zha)

                 {

                     int len=zha;

                     int zong=;

                     for(int r=;r<len;r++)

                     {

                         if(mp[st[e]][r]==ve[r])

                             zong++;

                     }

                     if(zong==len){

                         judge++;

                         ans=st[e];

                         }

                 }

             }

             if(judge==)

                 cout<<ans<<endl;

             else

                 printf("Let's go to the library!!\n");

         }

     }

     return ;

 }