Codeforces Round #356 (Div. 2) A. Bear and Five Cards 水题

A. Bear and Five Cards

题目连接：

http://www.codeforces.com/contest/680/problem/A

Description

A little bear Limak plays a game. He has five cards. There is one number written on each card. Each number is a positive integer.

Limak can discard (throw out) some cards. His goal is to minimize the sum of numbers written on remaining (not discarded) cards.

He is allowed to at most once discard two or three cards with the same number. Of course, he won't discard cards if it's impossible to choose two or three cards with the same number.

Given five numbers written on cards, cay you find the minimum sum of numbers on remaining cards?

Input

The only line of the input contains five integers t1, t2, t3, t4 and t5 (1 ≤ ti ≤ 100) — numbers written on cards.

Output

Print the minimum possible sum of numbers written on remaining cards.

Sample Input

7 3 7 3 20

Sample Output

7 3 7 3 20

Hint

题意

你现在有五张牌，你可以删去相同的两张，或者三张，问你删去之后，这五张牌最小的和是多少？

题解：

模拟一遍就好了，模拟删除哪几张就行了……

代码

#include<bits/stdc++.h>
using namespace std;

int n,x,sum,ans;
map<int,int>H;
int main()
{
    n=5;
    for(int i=0;i<n;i++){
        scanf("%d",&x);
        H[x]++;
        sum+=x;
    }
    ans=sum;
    for(auto v:H){
        if(v.second>2)
            ans=min(ans,sum-3*v.first);
        if(v.second>1)
            ans=min(ans,sum-2*v.first);
    }
    cout<<ans<<endl;
}