hdu 2085

PS:递推题..  a[n]=a[n-1]*3+2*b[n-1]  b[n]=a[n-1]+b[n-1]

代码:

#include "stdio.h"
long long a[];
long long b[];
int main(){
    int i,c;
    a[]=;
    b[]=;
    for(i=;i<;i++){
        a[i]=*a[i-]+*b[i-];
        b[i]=b[i-]+a[i-];
    }
    while(~scanf("%d",&c)){
        if(c==-) return ;
        printf("%lld, %lld\n",a[c],b[c]);
    }
    return ;
}