AtCoder Beginner Contest 116 C题 【题意:可以在任意区间【L,R】上加1,求通过最少加1次数得到题目给定的区间】】{思维好题}
C - Grand Garden
In a flower bed, there are NN flowers, numbered 1,2,......,N1,2,......,N. Initially, the heights of all flowers are 00. You are given a sequence h={h1,h2,h3,......}h={h1,h2,h3,......} as input. You would like to change the height of Flower kk to hkhk for all kk (1≤k≤N)(1≤k≤N), by repeating the following "watering" operation:
- Specify integers ll and rr. Increase the height of Flower xx by 11 for all xx such that l≤x≤rl≤x≤r.
Find the minimum number of watering operations required to satisfy the condition.
Constraints
- 1≤N≤1001≤N≤100
- 0≤hi≤1000≤hi≤100
- All values in input are integers.
Input
Input is given from Standard Input in the following format:
NN h1h1 h2h2 h3h3 ............ hNhN
Output
Print the minimum number of watering operations required to satisfy the condition.
Input
Output
Input
Output
题意:可以任意在区间【L,R】上加1,求通过最少次数得到题目给定的区间的值】
AC代码:
#include<bits/stdc++.h>
using namespace std;
#define int long long
];
signed main(){
;
int n;
cin>>n;
;i<=n;i++)
scanf("%lld",&arr[i]);
];
;i<=n;i++){
if(i==n){ // 特判一下
ans+=max(arr[i],temp);
}else{
if(arr[i]>=temp){
temp=arr[i];
}else{
ans+=abs(arr[i]-temp);// 需要减去多加的数
temp=arr[i];
}
}
}
cout<<ans;
;
}
代码2
#include<bits/stdc++.h>
using namespace std;
#define N 515155
int arr[N];
int main(){
int n;
cin>>n;
;
scanf(]);
){
cout<<arr[];
;
}
];
;i<=n;i++){
scanf("%d",&arr[i]);
if(i==n){
ans+=max(temp,arr[i]);
break;
}
if(arr[i]<temp){
ans+=temp-arr[i];
temp=arr[i];
}else{
temp=arr[i];
}
}
cout<<ans;
;
}
AtCoder Beginner Contest 116 C题 【题意:可以在任意区间【L,R】上加1,求通过最少加1次数得到题目给定的区间】】{思维好题}的更多相关文章
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