HDU 2222 Keywords Search(瞎搞)
Keywords Search
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 50451 Accepted Submission(s): 16236
Wiskey also wants to bring this feature to his image retrieval system.
Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched.
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match.
Each case will contain two integers N means the number of keywords and N keywords follow. (N <= 10000)
Each keyword will only contains characters 'a'-'z', and the length will be not longer than 50.
The last line is the description, and the length will be not longer than 1000000.
5
she
he
say
shr
her
yasherhs
/* ***********************************************
Author :guanjun
Created Time :2016/5/26 22:17:48
File Name :2222.cpp
************************************************ */
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <stdio.h>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <iomanip>
#include <list>
#include <deque>
#include <stack>
#define ull unsigned long long
#define ll long ling
#define mod 90001
#define INF 0x3f3f3f3f
#define maxn 250010
#define cle(a) memset(a,0,sizeof(a))
const ull inf = 1LL << ;
const double eps=1e-;
using namespace std; struct ACauto{
int ch[maxn][];
int sz;
int f[maxn],last[maxn],val[maxn],cnt[maxn];
void init(){
sz=;
memset(ch[],,sizeof ch[]);
memset(cnt,,sizeof cnt);
}
int idx(char c){
return c-'a';
}
void add(char *s,int v){
int u=,len=strlen(s);
for(int i=;i<len;i++){
int c=idx(s[i]);
if(!ch[u][c]){
memset(ch[sz],,sizeof ch[sz]);
val[sz]=;
ch[u][c]=sz++;
}
u=ch[u][c];
}
val[u]=v;
}
void getfail(){
queue<int>q;
f[]=;
for(int c=;c<;c++){
int u=ch[][c];
if(u){
f[u]=;
q.push(u);
last[u]=;
}
}
while(!q.empty()){
int r=q.front();q.pop();
for(int c=;c<;c++){
int u=ch[r][c];
if(!u){
ch[r][c]=ch[f[r]][c];
continue;
}
q.push(u);
f[u]=ch[f[r]][c];
last[u]=val[f[u]]?f[u]:last[f[u]];
}
}
}
void print(int j){
if(j){
cnt[val[j]]++;
print(last[j]);
}
}
void Find(char *T){
int n=strlen(T);
int j=;
for(int i=;i<n;i++){
int c=idx(T[i]);
while(j&&!ch[j][c])j=f[j];
j=ch[j][c];
if(val[j])print(j);
else if(last[j])print(last[j]);
}
}
}ac;
char s[][],T[];
int BKDRHash(char* s)
{
long long seed=;
long long hash=;
while(*s=='')s++;
while(*s)
{
hash=hash*seed+(*s++);
}
return (hash & 0x7FFFFFFF);
}
map<int ,int>mp;
int main()
{
#ifndef ONLINE_JUDGE
freopen("in.txt","r",stdin);
#endif
//freopen("out.txt","w",stdout);
int t,n;
cin>>t;
while(t--){
ac.init();
mp.clear();
scanf("%d",&n);
for(int i=;i<=n;i++){
scanf("%s",s[i]);
ac.add(s[i],i);
int x=BKDRHash(s[i]);
mp[x]++;
}
ac.getfail();
scanf("%s",T);
ac.Find(T);
int ans=;
for(int i=;i<=n;i++){
int x=ac.cnt[i];
int y=BKDRHash(s[i]);
if(x>){
ans+=mp[y];
}
}
printf("%d\n",ans);
}
return ;
}
HDU 2222 Keywords Search(瞎搞)的更多相关文章
- HDU 2222 Keywords Search(查询关键字)
HDU 2222 Keywords Search(查询关键字) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K ...
- HDU 2222 Keywords Search(AC自动机模版题)
Keywords Search Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others ...
- hdu 2222 Keywords Search ac自己主动机
点击打开链接题目链接 Keywords Search Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Ja ...
- hdu 2222 Keywords Search 模板题
Keywords Search Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others ...
- hdu 2222 Keywords Search - Aho-Corasick自动机
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submissio ...
- hdu 2222 Keywords Search
链接:http://acm.hdu.edu.cn/showproblem.php?pid=2222 思路:裸AC自动机,直接贴代码做模板 #include<stdio.h> #includ ...
- hdu 2222 Keywords Search ac自动机入门
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2222 题意:有N(N <= 10000)个长度不超过50的模式串和一个长度不超过1e6的文本串. ...
- HDU 2222 Keywords Search(AC自动机模板题)
http://acm.hdu.edu.cn/showproblem.php?pid=2222 题意:给出多个单词,最后再给出一个模式串,求在该模式串中包含了多少个单词. 思路: AC自动机的模板题. ...
- 【刷题】HDU 2222 Keywords Search
Problem Description In the modern time, Search engine came into the life of everybody like Google, B ...
随机推荐
- 刷题总结——二叉苹果树(ssoj树形dp+记忆化搜索)
题目: 题目背景 URAL:http://acm.timus.ru/problem.aspx?space=1&num=1018 题目描述 有一棵苹果树,如果树枝有分叉,一定是分 2 叉(就是说 ...
- EC++学习笔记(五) 实现
条款26:尽可能延后变量定义式的出现时间 尽可能延后变量的定义,知道非得使用该变量的前一刻为止方法A: Widget W; ; i < n; ++i) { W = ... } 方法B: ; i ...
- PatentTips - GPU Support for Blending
Graphics processing units (GPUs) are specialized hardware units used to render 2-dimensional (2-D) a ...
- (10) android控件-date
1.TimePicker <TimePicker android:id="@+id/timePicker4" android:layout_width="wrap_ ...
- T1063 合并果子 codevs
http://codevs.cn/problem/1063/ 时间限制: 1 s 空间限制: 128000 KB 题目等级 : 钻石 Diamond 题目描述 Description 在一个 ...
- Windows下配置scrapy需要MVC的14.0版本(转载)
转载于--http://blog.csdn.net/MrWilliamVs/article/details/77130965 杨煜冬煜杨的博客,他的博客比较杂,Java.Python都有--http: ...
- Ubuntu 16.04安装IntelliJ IDEA时快捷键冲突设置
解决快捷键冲突可以有如下方法: 1.直接修改IDEA的,但是不建议这么干,因为多平台时,或者去到另外一台电脑时,统一的快捷键能更快的适应新的开发环境. 2.通过修改系统默认的快捷键. 3.就这两种方式 ...
- Python基础语法08--MySql应用
python操作mysql数据库 Python 标准数据库接口为 Python DB-API,Python DB-API为开发人员提供了数据库应用编程接口. DB-API 是一个规范. 它定义了一系列 ...
- BUPT 2012复试机考 1T
题目描述 大家都知道,数据在计算机里中存储是以二进制的形式存储的. 有一天,小明学了C语言之后,他想知道一个类型为unsigned int 类型的数字,存储在计算机中的二进制串是什么样子的. 你能帮帮 ...
- TCP 的那些事儿(下)(转)
TCP的RTT算法 从前面的TCP的重传机制我们知道Timeout的设置对于重传非常重要, 设长了,重发就慢,没有效率,性能差: 设短了,重发的就快,会增加网络拥塞,导致更多的超时,更多的超时导致更多 ...