leetcode [64] merge tow sorted lists
之前忘记记录这题了,现在补上。
合并两个有序的list,要求是:
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
不知道我如下做是不是符合题目要求呢。
- /**
- * Definition for singly-linked list.
- * struct ListNode {
- * int val;
- * ListNode *next;
- * ListNode(int x) : val(x), next(NULL) {}
- * };
- */
- class Solution {
- public:
- ListNode *mergeTwoLists(ListNode *l1, ListNode *l2)
- {
- if (l1 == NULL) return l2;
- if (l2 == NULL) return l1;
- ListNode *tmp = new ListNode();
- ListNode *head = tmp;
- while(l1 && l2)
- {
- if (l1 -> val <= l2 -> val)
- {
- tmp -> next = l1;
- tmp = l1;
- l1 = l1 -> next;
- }
- else
- {
- tmp -> next = l2;
- tmp = l2;
- l2 = l2 -> next;
- }
- }
- if (l1)
- {
- tmp -> next = l1;
- }
- else
- {
- tmp -> next = l2;
- }
- return head -> next;
- }
- };
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